Topic C Perpetual Calendar 2 people Is there a program analysis? 10

Hehe, the command line type cal -y 2008 will do.

#include""

int judge(int year,int month) defines a function that divides months into four categories (28,29,30,31).

else return(4);*30-day month, the return value is 4* }main().

char*month=;

clrscr();

printf("please inter the year:");

scanf("%d",&year);

printf("");

printf("the calendar of the year%d.",year);

printf("");

a=(year+(year-1)/4-(year-1)/100+(year-1)/400)%7;

for(i=0;i<4;i++) * output calendar of previous months * printf("");

for(k=0;kprintf(" ");*six spaces* for(m=1; m<32;m++)

a=(a+m)%7;*Calculate what day of the week the first day of the next month is* printf("");

printf("********************==");

printf("");

#include

using namespace std;

int leapyear(int year);

int main()

for(i=1;i<=b-1;i++)

else if(i==4||i==6||i==9||i==11)else if(i==2)

result+=c%7;

result%=7;

if(result==0)

result = 7;

cout <<"It's the week"

To determine whether it is a leap year, if it is a leap year, return 1 (366 days), otherwise, return 0 (365 days).

int leapyear(int year) can be done with a few minor changes.

: Defines the entry point for the console application.

#include ""

#include

#include

#include

using namespace std;

void week(int y, int m, int d) date for the week.

c = y / 100 + 1;

if( m <= 2)

w = ( y + y / 4 + c / 4 - 2 * c + 26 * m + 1 ) / 10 + d - 1 ) 7;

cout

cout <<"sun";

else if (w == 1)

cout<<"mon";

else if (w == 2)

cout<<"tue";

else if (w == 3)

cout<<"wed";

else if (w == 4)

cout<<"thu";

else if ( w == 5)

cout<<"fri";

else/ cout <<"sta";

Initialize the perpetual calendar based on the system time.

void printmonth(int y, int m, int d) prints out the given time for the monthly calendar,};

int leap,i;

leap = ( y % 4 == 0 &&y % 100 != 0 ||y % 400 == 0);

for( i = 1 ; i < d ; i++

cout <<"★" ;

for(i = d; i <= ym[leap][m]; i++

int judge(int y, int m, int d) to determine whether a given time exists,};

int leap, i;

if( y <= 0 ||m < 1 ||m > 12 )

return 0;

leap = ( y % 4 == 0 &&y % 100 != 0 ||y % 400 == 0 );

if( d < 1 ||d > ym[leap][m] )

return 0;

elsereturn 1;

int search(int y, int m, int d) finds the corresponding experience for a given time to print.

int main()

return 0;}

#include

define yes 1 defines the sign constant"Yes"

define no 0 defines the sign constant"Nope"

Function isleap(): Determines whether a leap year is int isleap(int year).

Function week of newyears day(): Find the day of the week when New Year's Day is.

int week of newyears day(int year) main function: Prints the calendar.

int main()

cout <