Who will help me solve 2 math problems? A 10 points

Sand volume: 1 3 cubic meters.

I can pave a road: m.

After 8 minutes, there is water: 8 liters.

B with water: 8 liters.

At this time, the water surface is as high.

Then the area of the first base is 18 12 = times the area of the second base.

The area of the nail base is:

Cm.

1. The radius of the bottom surface of a conical sand pile is 1 meter, indicating meters, and the thickness of 2 inside is spread on a 5-meter-wide highway with a pile of sand, how many meters can be paved?

x=1/3**

x = meters. I can spread rice.

2. There are 6 liters of water in a cylindrical container, and the cylindrical container is empty, and now the water surface is the same as the same height at the rate of liters per minute, and the bottom radius of container B is known to be 10 cm, what is the bottom area of container A?

8 minutes A injected 12 liters of water, a total of 12 + 6 = 18 liters, the bottom area s = 18 h8 minutes B injected 12 liters of water, a total of 12 liters, the bottom area, h = 12 dm.

So s=18 square decimeters.

v cone = 1 * 1 * cubic meter).

v cuboid = v cone = cubic meter.

The length of the road that can be paved = v cuboid (road width x thickness) = m) 8 minutes volume of water injected = v cylinder A = v cylinder B = liter) = 12 cubic decimeters.

h cylindrical A = h cylindrical B = v cylindrical B s Cylindrical B bottom area = 12 (decimeter) s Cylindrical A bottom area = v cylindrical A h cylindrical A = 12 square decimeters) Answer: The bottom area of container A is square decimeters.

/3πr²h=1²×

m).5 liters = 1500 ml = 1500 cubic centimeters.

1500 8 + 6000 = 18000 cubic centimeters.

18000 【12000 (10 10 square centimeters.

1. Sand volume v = 1 3 * bottom area * height = cubic meters.

m).2. The volume of water in B is literated.

Height h = 12000 100 = 120

The volume of water in A is 12 + 6 = 18 liters.

Base area = 18000 (120) = 150 square centimeters.

Such a simple question asked? Just set the formula directly. Tell me the area formula of the cone aid can be paved.

Let the original gasoline in the mailbox be x liters, and the equation can be listed by the title: solve the equation to get x = 10Note: This is the amount of gasoline left after A to B, and the lower part of the equation is the amount of gasoline used from B to C.

The unit is unknown, and it is difficult to calculate.

Is it 25%?

Is it 20%?

If so, then there is a result for this question.

The answer is: 10 liters.

What is the unit of your gasoline liter or what.

To do this kind of problem is to find multiple equations, and then find the unknowns.

Because A has the correct solution, he brings x=1 y=-1 into the system of equations ax+by=2 cx-3y=-2

We get a+b=2, c+3=-2, so c=-5

Because B copied the wrong c, the solution is x=2 y=-6, so x=2 y=-6 can be brought into ax+by=2 to get 2a-6b=2, and a=b=2 is combined to get a=7 4, b=1 4

So a=7 4, b=1 4, c=-5

Bringing x=1 into x2+px+q gives 1+p+q=0, and bringing x=-2 into x2+px+q gives 4-2p+q=5

Solve the two equations of 1+p+q=0, 4-2p+q=5 to obtain p=-2 3, q=-1 3

A and b are inverses of each other: a+b =0

So the result of the formula you are talking about is 0

1、y=5 x=0

2, -4x 2=-4 1 It's good to simplify it 3, a=b=plus or minus 6 m=plus or minus 12, 2 values 20, I will send the solution process to your mailbox, and the mailbox will give me 5, a 2 + b 2 + ab=

a+b）^2=1，（a-b）^2=25

Launch a 2 + b 2 + 2 ab = 1

a^2+b^2-2ab=25

Introduce 2x(a 2+b 2)=26 and add up the two formulas a 2+b 2=13

Launched 2ab=-12 ab=-6

a^2+b^2+ab=13-6=7

Not all of them are right.

^1.From the problem y=5, then x=o

2.Simplify. Original=-4x 2=-1 4

pcs: 37, 20, 13, 12, 15

1).a^2+b^2-2ab=25 (2)

1)-(2)=4ab=-24

ab=-6a^2+b^2=13

a^2+b^2+ab=7

1. x=0,y=5 2.(2x+y)+(2x-y) can determine 4x 1 3 ab=36, so a and b have 5 pairs of values, and m can take 5 4 I don't understand what you write.

5 A 2+B 2+2AB=1 A 2+B 2-2AB=25 to get a 2+b 2=13 AB=-6 So the result is 7

1. Solution: Because the power of 0 is meaningless.

So y-5=0

So y=5, so 3x+10=10, so 3x=0, x=0x=0, and y=5