c How to input values from the keyboard to assign struct variables

First, define the struct and assign values to the elements in the struct in turn

Reference**. #include

typedef struct stu{ define struct type int a; }

int b;

int c;

int main()

stu s;Define the struct.

Enter each element in turn.

printf("The struct elements are: %d %d %d",,, Output each element.

return 0;

Result: The struct elements are: 1 2 3

It's simple: first you have to have a structure name

struct stud

If it's an array, you can write it like this:

struct stud, got it? If you don't understand anything, contact again!

To assign a value to a struct, define the struct first, and then assign values to the struct members individually, you can use the scanf() function, for example:

#include

struct student

void main()

Screenshot of the run:

Forehead! If you define a struct variable ren, you need to assign a value to its members. --scanf("%s",&;

It's very simple: in this example, I suggest you use getsgets(ren[0].) instead of scanfgonghao) is OK because they are all character arrays

The simplest one is a student number and a name.

For example, include

struct stu

int main()

If you need other elements, add them as well.

To give you a small example:

#include

struct stu

main()Satisfied!

If it's an array of structs, it's fine, otherwise you'll have to useOperators operate one by one.

Define an array of structures.

For example, stuct temp;

The keyboard enters the value to the array.

scanf("d%",scanf("d%",

How do you want to initialize it?

struct node

struct node a,*b;

b=a;Clean.

memset(b, 0, sizeof(struct node));

Assignment.; strcpy(, "12345");

b->a=0;

strcpy(b->b, "12345");

c can't be assigned like this, this way can only be initialized at the time of definition.

If int a[2] = is correct, but defining an array and then a= is incorrect, you should assign values one by one. In addition, when you define it, you need to request memory for variables, and the compiler will assign the value of your initial words to memory, but if you use it as a pointer when you assign a value later, the syntax will be incorrect.

m1->edges=,}

You can define the array you want to start with a const array, and then use for to assign the value, there is no other way,};

with member symbols. Pander to.

Like what. struct date

struct student

student1;

So if you want to assign the year value to student1's birthday.;

typedef struct _book_infobookinfo;

The values are assigned: bookinfo bookinfo;

If you're satisfied, please give me some points, I'm seriously short of points. Hehe.

Struct assignment should not be done to all items in the struct, for example:

struct node

node s1,s2;

If the value of s2 is paid to s1, then:

s1->data=s2->data;

s1->next=s2->next;

This is called struct assignment.

Each part has to be assigned.

Direct assignment, no different from other members.

For struct variables, you can assign values directly like you do: s1 =s2, and the pointer to structs is represented like this.

struct structa *s1;

Still have questions, please ask.

str *st;This is to define a pointer, but without allocating a specific memory space to the pointer.

st).age= 1;Employing * on a pointer that does not specify a memory space will cause the program to "get confused" and quit abnormally!

str st1;What is defined here is a struct variable that has its own storage space.

1;This is normal struct element assignment! Normal, of course.

*st is the pointer to be assigned and should be used.

The latter is just a normal variable, which is to get the value of a property in the struct.

#include ""

#include ""

#define n 30

struct date defines a struct date that contains 3 members.

struct student defines a struct student num1;

main()

mem1=,mem2=;

struct student num1=,"Ankang City, Shaanxi Province",100};The error that appears is: syntax error:',"Shaanxi Province Labor City",100};The error that appears is:

syntax error:'

Changed the compilation through.