Find 100 equations with answers!!

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x/4=5/48，48x=4*5，48x=20，x=20/48=5/12，1/4：x=1/8:1/10，1/4*1/10=1/8*x，1/40=x/8，x=8/40=1/5，5/x=30:3，5/x=10，x=5/10=1/2，3/4:1/8=x：2，3/4*2=1/8*x，3/2=x/8，x=3*8/2=12，5-（x-1)=3-3x

5-x+1=3-3x

6-x=3-3x

x+3x=3-6

x=：x=:4，26=，x=26/

3 4=:x,,x=,On the highway, a small car with a length of meters is traveling at a speed of 45m seconds, and a large truck with a length of meters in front of it is driving in the same direction at a speed of 35m seconds, what is the overtaking time when the car catches up with the large truck?

Let it take time t to get the equation.

The solution is t=2s

A person walks at a speed of 6 kilometers an hour and rides a bicycle at a speed of 18 kilometers an hour, walks half the way from A to B, rides half the way, and then returns to A along the same road, walks half the time and rides the other half, and the return time is one and a third hours less than when he goes, finding the distance between A and B.

Suppose the distance between A and B is s

2s=(6+18)*[s/2/6+s/2/18)-4/3]

s=48A, B is racing on a 400-meter runway, B walks 80 meters per minute, A's speed is 1 and 1/4 of B's speed, now A is 100 meters in front of B, how many times do the two meet after walking in the same direction?

Solution: Suppose the two meet in x minutes, 1 and 1/4 =

A's speed = 80 meters traveled per minute).

According to the question: (100-80)x=400-100

20x=300

x=15A rides a bicycle from A to B, and B rides a bicycle from B to A, both of them moving at a constant speed. The two men are known to have departed at the same time at 8 a.m., and by 10 a.m. they were still 36 kilometres apart, and by 12 noon they were 36 kilometres apart. Find the distance between A and B.

Let A and B travel as X

x-36)/(10-8)=(36+36)/(12-10)

x=108 open pipe water into the tank, 5 minutes can be full, pull out the bottom plug after full, then the water in the tank can flow out after 10 minutes, once open the pipe into the tank, after a few minutes found that the bottom plug is not plugged, quickly plug the bottom plug, there is the same time before the water is filled, ask how much time to inject in total, before the water tank is full?

Set a total of x minutes of betting.

x/5 - x/10 + x/5 = 1

x = 10/3

Solution: The area of the old dormitory is x

20000-x)+3x+1000=20000+20000×20%21000+2x=24000

2x=3000

x=1500

1500 80 = 120000 (yuan).

1500 3 + 1000) = 5500 (square meters) 5500 700 = 3850000 (yuan).

3,850,000 + 120,000 = 3,970,000 (yuan) A: It takes 3,970,000 to complete the program.

Set up the demolition of the old school building x square meters.

2000-x+3x+1000=2000×（1+20%）x=1500

If the area of the forest farm is x hectares, then the area of the pasture is 20%xx + 20%x = 162

x + = 162

x = 162÷

x = 135

A: The forest farm is 135 hectares.

Let the height of the small giraffe be x meters, then the height of the large giraffe is meters, x=

x = m) giraffe's height m).

Answer: The height of a small giraffe is meters, and the height of a large giraffe is meters.

Steps to solve the problem with column equations:

Set the required unknown quantity to x;

2.List equations based on equiquantitative relations;

3.solving equations;

Pay attention to the inspection:

whether the solution of the equation satisfies the equation;

Whether the solution of the equation matches the problem.

Solution: Let the height of the fawn be x meters.

x Steps: 1. According to the equation of the equivalence relation series in the problem.

2. Solve equations.

3. Inspection. When testing, the value of the unknown is substituted into the original equation, and the value of the unknown that can make the left and right sides of the equation equal is the solution of the equation.

If the height of the fawn is x meters, then the height of the deer is meters.

Big deer is better than small deer.

x = the height of the deer is meters.

If the speed of the truck is x, the speed of the passenger car is 4x 3

x+4x/3)*

solution, x=90

A: The speed of the truck is 90km h and the speed of the bus is 120km h

There are x number of male and 170-x female students.

3x=7（170-x）

3x=1190-7x

x=119, then 119 boys have a loss and 170-119 = 51 girls.