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7x+3y+2z=212
x+y+z=47
y=2zx=20 y=18 z=9
Upstairs, how can you make sure that the one in front is just white and blue? It should be:
9 + 7 + 1 = 17.
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1. Solution: Set C to x.
y+2x+x=47
The solution is x=9 so: B = 2 * 9 = 18, A = 47-18-9 = 20 Answer: A 20 copies, B 18 copies, C 9 copies.
3. According to common sense, there should be 3 if you are lucky, just 3 colors.
It seems to be a matter of high school ranking.
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1. Let A be x, B be 2y, and C be y.
then x+2y+y=47,7x+6y+2y=212;
The solution is x=20, 2y=18, y=9;
2. Take 6 white, 7 blue, and then take it to ensure the requirements of the question.
That's 6 + 7 + 1 = 14.
Very simple question.
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1, A is x, B is 2y, C is y.
Then x+2y+y=47, 7x+6y+2y=212;
x=20, 2y=18, y=9;
2. Take 6 white, 7 blue, and then take it to ensure the requirements of the question.
That is, 6 + 7 + 1 = 14.
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Solution: If the actual amount is 10x, then the amount at the time of accounting is x, which can be listed as 10x-x=153
Solution: x=17
So the cash for the money actually received in the mistaken account was $170.
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According to the inscription, it can be seen that the 6 on the ten digits becomes 3 and is reduced by 20 times, and the 3 on the single digit becomes 1 and shrinks by 3 times, which is a total of 20 + 3 = 23 times, so 23 The original result is 20 = 460
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The result is 20*(x63 y31), where x,y is any combination of numbers above the hundred digits x=y
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A 6 in the 10th digit is written as 3, and a 3 in the single digit is written as 1
31x?=20, obviously this formula is not multiplication but division. The original question is wrong.
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Multiplication of several digits? Is it a two-digit number on a number that is wrong?
x*31=20 x=20 31 Correct result x*63=1260 31
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Solution: Set the toy x yuan.
x-1)+(x-2)=x
Solve the !! of x = 3 pairs
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How much money did the two of them bring with them? And how much money did the two of them each bring?
You see if it's a different question. But chew the words like this. It doesn't seem to mean the question. After all, it's only the first grade.
I don't know if it's right, but I hope it can help you.
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This toy is 3 yuan, Ding Ding brought 2 yuan, and Xiaopang brought 1 yuan. The teacher should have read it wrong.
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In fact, this question is equal to as much as you can, for example: toys 17 yuan Ding Ding brought 9 yuan, Chubby brought 8 yuan, 8 + 9 = 17, which also makes sense.
The key is how to write the equation.
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To cultivate students' open-mindedness, there is no only answer, as long as it is said correctly
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It's 3 yuan, the teacher corrected the mistake, just know it. Your answer is absolutely correct.
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Hello landlord, happy to ask you to answer questions!
Solution: Set the toy x yuan.
x-1+x-2=x
The solution is x=3, so the toy ** is 3 yuan.
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The teacher is too much, go find the girl.
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Is it that you didn't write the equation or that the teacher read it wrong?
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Your answer is correct, maybe the teacher is wrong, as long as your analysis is reasonable, you can argue with the teacher. Believe in yourself.
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The teacher corrected the mistake.
It's 3 yuan.
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Did you not explain the process clearly?
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It's a product of age, right?
Then 1984 = 2 * 2 * 2 * 2 * 2 * 31 = 64 * 31 = 32 * 62 Considering the age of normal people, there are only two options.
The age of both father and son last year was prime, so last year's father and son age could have been 63, 30, or 61, 31
Obviously, 63 and 30 are not prime numbers, 61 and 31 are prime numbers, so the father and son are old this year and the poem 32 + 62 = 94
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Is there a mistake in the question, the question already indicates that the sum of this year's ages is 1984!!
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It must be a product of age! 1984 = 48 * 31 = 24 * 62, and because the ages of both of them were prime numbers last year, it can only be 24 and 62, so the sum of the ages is 86
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"The sum of their ages this year is 1984? "Do you add yourself that old as your dad? Tragic.
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The sum of ages is 1984, and I admit I hell am.
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There are x people in total.
x+x/3+x/5=253
23x/15=253
x=165A: 165 people in total.
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I only thought of this method, so I'll talk to you.
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