If a piece of wood floats on the water, why can the wood float on the water?

The original displacement was V-24, later the displacement was V-24-18

It turns out that the drainage is more than later (V-24)-(V-24-18)=18 (cm 3), and the result is xg cm 3Yes.

24x=18*1

Since it is floating, the gravity of the wood block after cutting is the same as the gravity of the reduced drainage. x=3 4

So the density is grams per cubic centimeter.

And the volume is 96 cubic centimeters.

Let the original volume be x

x-24)*1 The original wooden block is heavy, so the density is (x-24)*1 xx-24-18)*1 After cutting, the wooden block is heavy, and the density is (x-24-18)*1 (x-24).

Density unchanged (x-24)*1 x=(x-24-18)*1 (x-24).

x=96 brings in a density of.

Let the volume of the start in water be x

24/x=18/(x-18) x=72

The volume is 72 24 96

Density 72 1 96

The volume is.

24 cubic centimeters) density.

72 96 = grams cubic centimeters).

Let the original volume be v

Then: 24 v=18 (v-24).

The solution is v=96

96 cubic centimeters, grams of cubic centimeters.

Here's why:Because the gravitational force experienced by an object is related to the density of the object, while the buoyant force experienced in the water is not related to the density, but only to the volume of the water discharged by the object. Wood is less dense and its gravity is less than it is buoyant in water and therefore does not sink, whereas iron is subjected to gravity greater than it is buoyant and therefore sinks.

Density:

Density is a measure of the mass within a specific volume, density is equal to the mass of an object divided by the volume, which can be expressed by the symbol (pronounced rho), and in the International System of Units and the Chinese legal unit of measurement, the unit of density is kilograms per cubic meter.

The above content refers to Encyclopedia - Density.

Because the void of the wood contains air, it can float up and use that air to hold it up.

Because wood is less dense than water, it floats when it encounters water and does not sink underwater.

Because the weight of wood is relatively light, it is less dense than water, so it can float on the water, and the mass of water is greater than the mass of the wood itself.

Because wood is denser than water, it will float when placed in water.

Originally, only one object was floating, and the total buoyancy of the stone and wood was subjected to the total gravitational force of the stone and the wood block.

Now the stone is placed on the block, and the block is still floating, indicating that the total buoyancy experienced by the stone and the block = the total gravity of the stone and block.

Because the total buoyancy of the stones and wood increases, so their total displacement also increases, so the water surface height increases. Answer B should be chosen.

Answer: Since the wooden blocks are still floating on the surface of the water, and the gravity of the wooden blocks and stones has not changed, the buoyancy of the wooden blocks and stones is fixed, so the volume of water they discharge is also fixed, so the height of the water has not changed. So the answer is C hope).

You can list a system of equations:

U water v wood = m wood 1

U water (v matter + v wood + v metal) = m matter + m wood + m metal 2

M metal = u metal V metal 3

where u is the density.

In the process of solving, you need to know the volume or density of the object, otherwise you can't solve it.

Also, your topic is not rigorous, is the suspension of wooden blocks suspended by all three objects or only the suspended wooden blocks? In addition, when the block is suspended, does the metal underneath already touch the bottom of the container?

A little personal opinion for reference.

1 Analysis:

Wooden blocks must be lighter than water.

After putting 4kg of catty, the wooden block is just in the water, indicating that the wooden block can provide buoyancy that exceeds its own 4kg force.

Now that the metal is in the water, it is buoyant on its own, and it is not enough, but it also needs wooden blocks to help it provide 4kg of buoyancy.

So, let the volume of the metal be v and its density is = 5000 kg cubic meters.

Then its gravity is: m*g = *g*v

At this point, the buoyancy force given to it by water is f = water*g*v

The relay given to it by wood is 4kg*g

So m*g = *g*v = water*g*v + 4 * g approximately divides g

> v = water * v + 4

Known Water = 1000 kg cubic meters = 5000 kg cubic meters.

So (water)*v =4

(5000-1000)*v = 4

v = 4/4000 = 1/1000

m = ρ*v = 5000 * 1/1000 = 5 kg

In this problem, the mass and volume of the wooden block are not known, so they cannot be found directly, so they can be solved by using the equation method. Analysis of the two cases shows that after placing an object on a wooden block, the gravity of the object and the wooden block should be equal to the buoyancy of the wooden block; When hanging an alloy block, the gravity of the wood block and the alloy block is equal to the buoyancy of the water on the wood block and the alloy block; Then the two equations can be solved in parallel;

Let the mass of the wood block be m wood, the buoyancy force is f float, and the volume of the alloy block is v; Yes.

m+m木)*g=ffloat;

m wood * g + * g * v) = f float + water * g * v;

Substituting data, Lianli obtains:

g*v=40 n + water*g*v;

Then we can solve: v=40n water)*g

40n／［(5×10^3 kg/m^3 - 1×10^3 kg/m^3 )×10 n/kg］

1×10-3m3；

then the mass of the alloy block m = *v = 5 10 3 kg m 3 1 10 -3 m 3 = 5 kg;

A: The mass of the alloy block is 5kg

I hope it helps you, and if you have any specific questions, please ask again

In fact, it is very simple, put an object m = 4kg on the wooden block = hang an alloy block with a density of 5000 kg cubic meters m - its buoyancy under the wooden block.

It's all about density.

m= *g*v- water*g*v;

You can calculate the volume, and of course the mass will be calculated.

When the block of wood is placed in the water and rises to the bottom, according to Archimedes' original code theory, the buoyancy is equal to the weight of the liquid discharged by the object, that is, the weight of the water discharged by the wooden block. Therefore, the weight of the block is equal to the weight of the drained water, and the total volume of the block and the water is equal to the volume of the drained water.

Therefore, in this case, the water does not overflow the container because the volume of water discharged by the block is equal to the total volume of the block and the water.

After putting a piece of wood into the water, the water will overflow, and the depth of the water will remain the same, according to p= water gh, then the pressure of the water on the bottom of the cup will not change The pressure of the container on the table is equal to the gravity of the container and the water, because the wooden block floats, G row = F float = G wood, so the one is overflowing.