Reward! Physics masters, please come in! The concept of flat throwing motion. The good ones have a b

I think you have a problem understanding. The time of the flat motion can be calculated from the initial velocity and the lateral displacement of the flat throwing motion. But that's not the same thing as a decision.

S is unknown until the object is thrown flat, how can t be determined?But h is known, and h=1 2gt*t, where g is constant. Therefore, the time of the flat toss motion is only determined by the height at which it is thrown.

Conversely, s can be derived from v t. While t is determined by h, v does not change. Therefore, the horizontal range of the flat throwing motion is determined by the height of the throwing point and the initial velocity.

1) Isn't the displacement formula for the transverse sub-motion of the flat throwing motion x=vt? So why is it said that the time of the flat toss motion is only determined by the height at which it is thrown? Instead of the initial velocity and lateral displacement determined?

In other words, why is the time of the flat throwing motion independent of the initial velocity and displacement in the transverse direction?

Because the flat throwing motion can be decomposed into a uniform linear motion in the horizontal direction and a free-fall motion in the vertical direction. The movement time is the time of free fall motion, t = 2h g under the root number, so the movement time is determined by the height.

2) Why is it said that the horizontal range of a flat throw motion is determined by the height and initial velocity of the throwing point, but not by time and initial velocity?

These two statements are the same, because time is determined by height.

If the longitudinal motion of the flat toss is completed, even if the lateral velocity is large, it is useless. Therefore, the motion time of the flat throwing motion depends on the time it lands, i.e. the height of the throwing point.

The time of the flat throw is determined by the height, whereas the lateral displacement is determined by the speed and time of the flat throw. So it should be said that the horizontal range is determined by altitude and muzzle velocity.

Its height determines how long it will move in the vertical direction, as it says above "h=1 2gt square." In the case of constant g, the greater h the greater the greater t the greater the greater the t" This motion time is certain in the whole motion process, which is only determined by the height h, so the time of the flat throwing motion is only determined by the height at which it is thrown. The initial velocity does not have any effect on this, and the transverse displacement is also determined by the horizontal initial velocity *t.

So you can look at the whole process like this: the height determines the time of movement, t, and the initial velocity of t and the level determines the horizontal range.

h=1 2gt square. In the case of constant g, the greater the h, the greater the t, and the greater the t.

From s=vt s, it is larger.

1) The formula of the longitudinal sub-motion of the flat throwing motion is h=, so as long as the height of the throwing is constant, and g is known (g = or 10), the obtained time is certain, so the time of the flat throwing motion is only determined by the height of the throwing In the formula x=vt, the initial velocity and displacement are variables, and the displacement (or initial velocity) can only be obtained by using this formula through the known initial velocity (or displacement) and a certain time. 2) According to the formula of the longitudinal motion of the flat throw, it can be known that the time is determined by the height of the throw. Therefore, the horizontal range is determined by both altitude and muzzle velocity, not time and muzzle velocity

Time is determined by height, not by time, pay attention to cause and effect.

Descending distance y=1 2gt 2

v vertical = gt = 2y t

v water touches this song flat = v muzzle velocity = x chop wax t

v vertical v horizontal = 2y x

Because it falls on an inclined plane, y x is tan a (which can be seen in the drawing), so v is vertical v level = 2tan a, that is, the instantaneous Xiao Zheng velocity direction is fixed and has nothing to do with the initial velocity.

The distance of the descending touch is y=1 2gt 2

v vertical = gt = 2y t

v water laugh Zheng Ping = v muzzle velocity = x t

v vertical v horizontal = 2y x

Because it falls on an inclined plane, y x is tan

a (can be seen in the drawing).

So v vertical v horizontal = 2tan

a, ie. Instantaneous curing speed.

The direction is fixed and independent of the initial velocity.

If the initial velocity is 0, the ratio of displacement in the same time is 1:3:5:7....

The difference of displacements in the same time is equal, and the number of symbols is as follows: s=at 2

The ratio of cheating time within the same displacement of the Bi family is 2-1 under the root number: 3 under the root number - 2 under the root number....