Hall Effect Analysis After the IM reaches a certain value, the UH IM curve is skewed by 30

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The Hall potential output by the Hall element is proportional to the excitation current and the perpendicular component of the magnetic induction intensity.

However, this only means that ideally, in practice, there will always be a range in the linear region of any component, and outside of that range, its characteristics will change to more than the range, and even the output will no longer change with the input.

In other words, linear relations exist only in a fixed interval.

The change in the slope of the im-vh straight line indicates that it has deviated from the linear interval!

The first one is used to measure the Hall coefficient. I don't know what your exact test parameters are, but my judgment is so.

The other relationship with the excitation current is of course used to measure the magnetic field value, but if you don't have a Hall coefficient in the first place, you can't get the magnetic field value from the Hall voltage, so I judge that the purpose of the first one is to obtain the Hall coefficient.

First of all, you have to understand that b = uh and h is the strength of the magnetic field.

The distance is constant, h and i are proportional;

uAlmost unchanged for non-magnetic materials; For magnetic materials, u is no longer a constant, b and h are not proportional, and it is not a single-value function, but a b(h) function image of a magnetic material.

Becoming a hysteresis loop, the initial h is fixed, and this image is in the first quadrant.

The slope of 's decreases until the rate of change is almost 0, at which point it becomes magnetically saturated.

You can also think of it this way, that the value of u decreases as h increases (but does not cancel out h for b).

Therefore, the larger the excitation current, the smaller the DB when the DI is constant, so the DUH is smaller.

It is very likely that the ferromagnet reaches saturation when the current is large, and the magnetic permeability gradually decreases and the magnetic field grows smaller, and the Hall element changes linearly to the magnetic field, so it ......You know.

This is the induced voltage, when the excitation current is 0, the electricity on the induction chip is not discharged, and it is 0 when it is short-circuited with the grounding terminal.

Residual leakage voltage, grounding can be discharged.

You're making semiconductor materials, right? If it is a metal, it should not have this phenomenon, if it is a p-type semiconductor, then this is a normal phenomenon, and it means that the temperature of your experiment has gradually approached the intrinsic excitation temperature of the material, resulting in more valence electrons on the conduction band of the p-type semiconductor at this time, and when the influence of valence electrons exceeds the holes, the Hall voltage will change sign.

The Hall effect is a type of electromagnetic effect, which was discovered by the American physicist Hall (1855-1938) in 1879 while studying the conductive mechanism of metals. When an electric current passes through a conductor perpendicular to the slow-burning external magnetic field, there is a potential difference between the two ends of the conductor perpendicular to the magnetic field and the direction of the current, which is known as the Kiebhol effect. This potential difference is also known as the Hall potential difference.