3 6th grade application questions that I don t understand Urgently!!!!!! 5

1.Use the sum of the basket of apples to be unchanged to solve the problem, and think of the basket of apples as a unit"1"

It turns out that the mother's apples account for 2 (2+3) = 2 5 of the apples in this basket of apples, and then the mother's apples account for 3 (2+3) = 3 5 for this basket of apples: 10 (3 5-2 5) = 50 kilograms.

2.The mass of bananas and apples accounts for 2 3, indicating that oranges account for: 1-2 3=1 3 The mass of apples and oranges accounts for 13 18, indicating that apples account for: 13 18-1 3=7 18

A total of fruit was delivered: 420 7 18 = 1080 kg.

3.Think of a batch of parts as a unit"1"

A does 1 2 of B and C, and it follows that A does all: 1 (1+2)=1 3 B does 1 3 of A and C, and it follows that B does all: 1 (1+3)=1 4 so C does all:

1-1 3-1 4=5 12 This batch of parts: 25 5 12=60 pcs.

1. At the beginning, the neighbor's house has x

Then we have 2 3*x in our house

Afterward. Neighbor's house = x-10

Mom = 2 3*x+10

Rule. 2/3*（2/3*x+10）=x-104/9*x+20/3=x-10

5/9*x=50/3

x=30 so. It turned out to be shared.

It is recommended to send one question once, not to do 3 questions in one go, and only offer a reward of 5 points.

1.It's so easy! : 10 (1-2 3) = 30 30 + 30 2 3 = 50.

2.It's easier! : The mass of bananas and apples accounts for 2 3, indicating that oranges account for: 1-2 3 = 1 3

The mass of apples and oranges accounts for 13 18, indicating that apples account for: 13 18-1 3 = 7 18

A total of fruits were delivered: 420 7 18 = 1080 kg 3A = 1 2 (B + C).

B = 1 3 (A + C).

Then A 1 2 (1 3 A 1 3 C C).

1 2 (1 3 A 4 3 C).

1 6 A 4 6 C.

A-1 6 A-4 6C.

5 6 A 4 6 C.

A 4 5 C 4 5 25 20

B 1 3(20 25) 15

Total 20 15 25 60

Another way: because A 1 2 (B C).

2 A, B, C.

Add A on both sides of the equation at the same time, and the equivalent value remains the same: 3 A A B C.

3A Total.

A 1 3 total.

B = 1 3 (A + C).

3B, A, C.

4B, A, B, C.

B 1 4 Total.

Then C is equal to 1-1 3-1 4 5 12

So the total is 25 5 12 60

1 Solution: Suppose mom began to divide x kilograms of apples.

x+10=3/2(3/2x-10)

x=2020*2 3+20 50 (kg) 2 450 divided by (2 3 + 13 18 1) 900 (kg) 3Think of a batch of parts as a unit"1"

A does 1 2 of B and C, and it follows that A does all: 1 (1+2)=1 3 B does 1 3 of A and C, and it follows that B does all: 1 (1+3)=1 4 so C does all:

1-1 3-1 4=5 12 This batch of parts: 25 5 12=60 pcs.

1. Set the water depth to x

Because both containers are filled with the same pure and noble water.

So. x-20）*5=（x-10）*3

Solution. x=35cm

2. Set the injected water to x

20+x/5=10+x/3

x/3-x/5=10

2x/15=10

x = 7575 5 = 15 cm.

So the water depth is 20 + 15 = 35 cm.

3. Solution: Set to inject x cubic centimeters of water.

20×5＋x）：（10×3＋x）＝5：3

x = 7575 5 20 35 (cm).

Or: 75 3 10 35 (cm).

3. The water added is V

Then we get 20+v 5=10+v 3

If v=75, then A's increased height = 75 5=15, total height = 15 + 20 = 35cm

I borrowed 1 book and put it in 17 books, there were 18 books in total, then Xiaofang 1 2, that is, 9 copies, Xiaoyuan 1 3, i.e. 6 copies, Xiaochang 1 9, i.e. 2 copies, a total of 17 copies, and 1 book remaining.

Calculated according to the first requirement:

17 (1 2) book).

17 (1 3) Ben).

17 (1 9) copies).

Try to round it according to the second requirement: 9 copies of Xiaofang, 6 copies of Xiaoyuan, 2 copies of Xiaochang, and the sum is exactly 17 copies.

The root cause of the above phenomenon is that the three students were assigned more books than the teacher expected, and the teacher planned to keep some of them for himself, but he was too embarrassed to take the books apart and divide them, so he had to put his own into them.

It's easy! Answer: Xiaofang 9 Ben 1 2 = 9 18; Ohara 6 Ben 6 18 = 1 3; Xiao Chang's 2 Ben 1 9 = 2 18

Isn't it just that the book for you is given now is all in its entirety.

The teacher borrowed another book, and there were 18 books in total. Xiao Fang gets 18 1 2 9 books; Ohara gets 18 1 3 6 books; Xiao Chang gets 18 1 9 2 books. After the division is completed, the teacher will return the borrowed one.

(1) 16,12 least common multiple 144

2) No... Odd-numbered plates, odd-numbered plates, less than 48 (3) with x grains.

x-4) is a multiple of 7, (x+3) is a multiple of 5, and x is a multiple of 3, so x is a multiple of 7 or 2

Start trying... x minimum is equal to 102

Or think directly about x being the least common multiple of 3,5,7 minus 3... 105-3=102 nostalgia. I'm getting old.

2. If you can't do it, the sum of the odd numbers can only be odd numbers.

In a cylindrical bucket, a section of 5 cm round steel is put into the water, and the water surface rises by 9 cm, and when the round steel is pulled vertically out of the water surface by 8 cm long, the water surface drops by 4 cm. Find the volume of a circle.

Solution:1The speed of car A: the speed of car B = 40:30 = 4:3ab The distance between the two places:

120 km

2.When Xiao Gang ran 90 meters, Xiao Ming ran (100-25) = 75 meters, then Xiao Ming is still from the finish line

100-83 and 1-3

16 and 2 3 meters.

3.The processing speed ratio of A and B is 250:150=5*3, and the total number of parts in this batch is total:

750 pcs. 600 pcs.

1.A and B are traveling in the opposite direction from A and B at the same time, but when A arrives at B, B is 30 (thousand) meters away from A, and when B arrives at A, Car A is more than 40 kilometers from B, how many meters are A and B apart?

According to the title, the speed ratio of car A to car B is 3:4

That is to say, car A will take 4 parts of the road, and car B will take 3 parts of the road. When car A arrived at place B, car B traveled 30 kilometers less. Then the distance between A and B is 30 4 = 120 km.

2.Xiao Gang and Xiao Ming have a 100-meter dash race (assuming that the speed of both is the same). When Xiao Gang ran 90 meters, Xiao Ming was still 25 meters away from the finish line, so, when Xiao Gang reached the finish line, how many meters was Xiao Ming from the finish line?

According to the title, the speed ratio of Xiao Ming and Xiao Gang is 75:90= According to this ratio, calculate how many meters Xiao Ming ran when Xiao Gang reached the finish line: 100 meters.

100-83 = 17 meters.

A: When Xiao Gang reached the finish line, Xiao Ming was still 17 meters away from the finish line.

3.A and B each process the same number of parts, and process at the same time, when A completes the task, B still has 150 unfinished, when B completes the task, A can overcomplete 250, how many parts are in total?

It is also calculated in proportion.

A completes 5 copies, B completes 3 copies. The difference is 2 copies, 2 copies are 150 pieces, then 1 part is 75 pieces. 5 parts is 75 5 = 375.

Am I right?