Allocate 202 183 56 0 to 2 faculties, 120 hosts each, please divide the corresponding subnets?

Divide the Class C network into as many subnets as possible, each subnet has 60 hosts, you can use a subnet mask or 26, because this subnet mask divides the IP address into a subnet of 64 IP addresses, of which 62 can be used as host IP addresses, one is a network address and one is a broadcast address. Therefore, four subnets can be divided, which are:

Each subnet has 64 IP addresses, of which 62 can be used as host IP addresses, one is a network location address, and one is a broadcast address, which can have 60 hosts.

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Can it be divided into two subnets, one subnet with 130 hosts and one subnet with 50 primaries?

Pro: You can divide into two subnets, one subnet can hold 130 hosts, and one subnet can hold 50 hosts. First, split the 24-bit subnet mask into two different subnet masks.

In order to accommodate 130 hosts, you need to use a collapse subnet with a 25-bit mask and can accommodate 128 IP addresses, of which 2 IP addresses are used for network addresses and broadcast addresses. In order to accommodate 50 hosts, a subnet mask of 26 bits is required that can accommodate 64 IP addresses, 2 of which are for network addresses and broadcast addresses. Then, divide the network into two subnets, which are and respectively.

The available IP address range for the subnet is where the network address is the broadcast address. The available IP addresses of the subnet are surrounded by the network address and the broadcast address.

Answer] :d to divide 10 subnets, the network bits need to be at least 4 bits, 2 4 = 16. If each subnet rents at least 10 hosts, the host bits are at least 4 bits, 2 4 = 16. From this, it can be concluded that the mask book is 24 + 4 = 28, that is.

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The first 11 bits of the host number are used as the subnet number to ask how many valid subnets can be divided. The number of valid addresses is 2 24 -2; The address space is huge; Number of valid addresses 2 20 -2 ; The address space is relatively large; Number of valid addresses 2 16 -2 ; The address space is a bit large The number of valid addresses is 2 8 -2 ; The method of subnet division of address space: borrow the first bit (n bits) of the host number as a new subnet number, and then add the same number of bits (n bits) of the network number in the subnet mask (that is, the number of 1), so as to generate a new subnet mask, subnet number, and subnet address; The number of clusters of subnets is 2N, which is as resistant as the number of bits of the host number in the new subnet at the same time minus n; Features: The network has changed from large to small.

Thank you for the trouble with the above question

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Now, the Class B network is subnetted, and the first 11 coarse answers of the main potato stool elimination number are used as the subnet number part. Excuse me: Number 1

How many valid subnets can be divided? 2.How many IP addresses can be assigned to a host per subnet at most3

What is the subnet mask?

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Understand. Okay pro.

Summary. To divide a network with an IP address into multiple subnets, each containing 25 hosts and requiring as many subnets as possible, the specified subnet mask should be ()AAnswer B

To divide a network with an IP address into multiple subnets, each subnet can include up to 12 hosts.

To divide a network with an IP address into multiple subnets, each subnet packet contains 25 hosts and requires as many subnets as possible, and the specified subnet mask should be ()AAnswer B

Topic: To divide a network with an IP address into multiple subnets, each subnet includes 25 hosts and requires as many subnets as possible, the specified subnet mask should be ()a

Each subnet requires 25 hosts 2 n-2 25, n takes 5, and the calendar family is the host bit needs 5 bits. The remaining limb of the subnet bit collapses by 3 bits, and the number of subnets is a class C IP of limb starvation, and the standard mask is. The subnet bit is 3, and the subnet mask is 0000.