How to purify aluminum magnesium alloys? And separation?

Updated on tourism 2024-03-20
7 answers
  1. Anonymous users2024-02-07

    Decanting: Separation of dense and insoluble solids from liquids Separation of sand and water filtration: Separation of insoluble solids from liquids Purification of edible water.

    Dissolution and filtration: separation of two solids. One is soluble in a solvent.

    The other is insoluble Separation of salt and sand centrifugal separation method: separation of insoluble solids from liquid Separation of mud and water crystallization method: separation of dissolved solutes from solution Extraction of salt from seawater:

    Separation of two immiscible liquids Separation of oil and water.

    Extraction: Add an appropriate solvent to dissolve and separate a component of the mixture with heptane.

    Extraction of iodine from aqueous solutions.

    Distillation: Separation of solvents and non-volatile solutes from solution Pure water distillation from seawater: separation of two liquids that are miscible with large differences in boiling points Separation of oxygen and nitrogen from liquid air, Petroleum refining.

    Sublimation: Separation of two solids. Only one of them can be sublimated by separating iodine and sand adsorption:

    Removal of gaseous or solid impurities from mixtures Removal of colored impurities from brown sugar with activated carbon Chromatography analysis: Separation of solutes in solution Separation of substances of different colors in black ink.

  2. Anonymous users2024-02-06

    Separation, which means to separate, to leave, to separate, to separate. It can be used for the separation of feelings between characters and objects.

    From a scientific point of view, separation is the process of using the differences in the physical or chemical properties of each component in a mixture to assign each component to different spatial regions or to the same spatial region at different times through appropriate devices or methods.

    With the addition of excess sodium hydroxide, aluminum will turn into sodium metaaluminate, which is soluble. Magnesium will become magnesium hydroxide precipitate, not melt, and then separated with a separating funnel.

  3. Anonymous users2024-02-05

    Add excess sodium hydroxide, after the reaction magnesium hydroxide will eventually become magnesium hydroxide precipitation, after filtration, there is only sodium metaaluminate in the solution, magnesium hydroxide is heated at high temperature to obtain magnesium oxide, hydrochloric acid is added to the filtered solution, and then excess ammonia is added, after complete reaction, filter and wash, heat and precipitate to full reaction, and alumina is obtained.

  4. Anonymous users2024-02-04

    Excess dilute hydrochloric acid is added first, then excess ammonia is added, and after a complete reaction, it is filtered and washed, heated and precipitated to full reaction.

  5. Anonymous users2024-02-03

    With the addition of excess sodium hydroxide, the alumina is dissolved, and the magnesium oxide is not. An appropriate amount of hydrochloric acid was added to the solution to precipitate aluminium hydroxide, and alumina was precipitated by burning.

    Al2O3+2NaOH==2Naalo2+H2ONaalo2+HCL+H2O==AL(OH)3 +NaCl2AL(OH)3==Al2O3+3H2O (condition is burning).

  6. Anonymous users2024-02-02

    There are four steps.

    1.Add an overdose of OH:mg2+ +2oh- =mg(oh)2↓

    al3+ +4oh- =alo2- +2h2o2.Filtration: Mg(OH)2 is obtained

    Acid is added to Mg(OH)2 and dissolved to give Mg2+:

    mg(oh)2 + 2h+ =mg2+ +2h2o4.Add excess hydrochloric acid to the filtrate obtained in step 2 (to obtain aluminum ions).

    alo2- +4h+ =al3+ +2h2o

  7. Anonymous users2024-02-01

    With the addition of excess sodium hydroxide, the alumina is dissolved and justified, and the magnesium oxide is insoluble. Add an appropriate amount of hydrochloric acid to the solution to the hydroxide balance aluminum precipitation, and burn the precipitation to obtain alumina.

    Al2O3+2NaOH==2Naalo2+H2ONaalo2+HCL+H2O==AL(OH)3 +NaCl2AL(OH)3==Al2O3+3H2O (condition is burning).

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