Urgent for the course design of a belt conveyor!

Transmission scheme formulation].

Working conditions: 10 years of service, 300 days per year, two shifts of work, stable load.

Raw data: drum circumferential force f=; belt velocity v=;

Drum diameter d=220mm.

Selection of electric motors].

Selection of motor type and structural type: according to the known working requirements and conditions, Y series three-phase jujube asynchronous motor is selected.

Determine the power of the motor:

Total efficiency of the transmission:

Total = with 2 bearings, gears, couplings, rollers.

Congratulations on the required operating power of the motor:

pd=fv 1000 total.

Determine the motor speed:

The stool of the drum shaft is made at the speed of the early:

nw=60×1000v/πd

The structure of the belt conveyor for coal mine is as follows: I hope it will help you.

Because of the tan so the slider slides down at rest, the object moves from point a, which is obtained by Newton's second law: mgsin + mgcos

ma1, the acceleration of the solution is: a1=gsin + gcos, and substituting the data can obtain: a1=.

Let the displacement of the object when it accelerates to the same speed as the conveyor belt be s1, and the duration t1 is eclips, and according to the displacement formula of uniform velocity, it is: s1=v2 2a1

Substitution number. It can be obtained that s1=. The motion time is obtained by the formula of uniform variable speed motion: t1=v a1

Substituting the data can obtain: t1=2s.

After that, the object moves downward relative to the conveyor belt, and Newton's second law is: mgsin mgcos ma2, the acceleration a2=gsin gcos is solved, and the acceleration a2=, displacement s2=ab s1 can be obtained by substituting the data, and then the formula of uniform velocity motion is obtained: s2=vt2+ *a2t2

Substituting data: t2=1s (the negative root should be rounded), the total time for the object to move from A to B is t=t1+t2=3s.

The frictional force on the object is: cos37*mg*

Downward force: sin37*mg

Object acceleration: (sin37*mg cos37*mg*The time taken by the object from A to B is obtained by a 2*t 2=l At this time, the velocity of the object is at

The reference is as follows: Mechanical Design Fundamentals Course Design Assignment .........Title of Topic Belt Conveyor Transmission Device Student College Professional Class Name Student Number 1. Content Design of Course Design Belt Conveyor Transmission Device (see Figure 1).

The design content should include: the overall design of the transmission device; design calculation and selection of transmission parts, shafts, bearings, couplings, etc.; Reducer assembly drawing and parts working drawing design; Preparation of design calculation specifications. Figure 2 is a reference transmission scheme.

2. Requirements and data known conditions for course design: 1. Working tension of conveyor belt: f = kn; 2 Conveyor belt working speed:

v = m/s；3 Roll diameter: d = 320 mm; 4 Service life: 8 years; 5 Working Situation:

Two-shift system, continuous one-way operation, stable load; 6. Manufacturing conditions and production batches: made in general machinery factories, small batches. 3. The work to be completed in the course design 1 1 reducer assembly drawing; 2. 2 working drawings of parts (1 for shaft and 1 gear); 3 Design specification 1 copy.

Fourth, the course design process, the arrangement of the serial number, the design of each stage, the content of the location, the start and end date, the design preparation: clear design tasks; Prepare design materials and drawing tools to teach 1-201 18th Monday 2 transmission device overall design: draw up transmission scheme; Select the electric motor; Calculation of transmission device motion and dynamic parameters Transmission parts design calculations:

Design and calculation of the main parameters of belt drive and gear transmission teach 1-201 18th Monday to 18th Tuesday 3. Reducer assembly sketch design: Initial reducer assembly sketch; Structural design of shafting components; Strength calculation of shafts, bearings, couplings, etc.; The design of the reducer box and accessories teaches 1-201 from Tuesday to 19 Monday to Thursday to complete the assembly drawing of the reducer: Teach 1-201 from Tuesday to 20 Monday 5 parts working drawing design teaches 1-201 Tuesday and Saturday of the 20th week to sort out and write the design calculation specification to teach 1-201 The 20th week of Wednesday to Thursday 7 Course design defense I-2-617 The 20th Friday.

Higher Education Press, Pu Lianggui, Ji Minggang. Mechanical Design [M].Beijing:

Higher Education Press, Wang Kun, He Xiaobai, Wang Xinyuan. Mechanical Design Mechanical Design Fundamentals Course Design [M].Beijing:

Higher Education Press, Mechanical Drawing, Mechanical Design Handbook and other books. Date of issuance of assignment: Signature of the instructor:

Plan Completion Date: Year Month Date Signature of the person in charge of the grassroots teaching unit: Signature of the superintendent of the dean:

Directory. 1. The formulation and description of the transmission plan .........3. Second, the selection of the motor .........3. Calculate the motion and dynamic parameters of the transmission device .........

4. Fourth, the design and calculation of transmission parts .........6. The design and calculation of the shaft .........15. Sixth, the selection and calculation ......... of rolling bearings

23 Seventh, the selection of key couplings and the calculation ......... checking26. Fatigue strength check ......... of high-speed shaft

I did similar designs when I was in college, and now I have a complete design process, including all the calculations and material selection, and I can ask me if you need to.

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The upstairs is strong enough When I did the design, it was all handwritten I thought that when I saw this kind of master, I admired that the owner of the building was also strong enough According to the previous years' participation in the Lingshu test - there will definitely be, the change data is calculated according to the formula brought in, and the description part is almost the same, but - the figure has to fight by itself, I can be weakly sure - the figure is really not Wang Kongfa to help you.