Please come up with ten sixth grade one dimensional equations

Updated on educate 2024-03-12
11 answers
  1. Anonymous users2024-02-06

    Hello, the blue sky that can't be erased:

    Solution: Let the original specified time be x hours, according to the topic.

    12×[x+(20/60)]=14×(x-1)12x+4=14x-14

    14x-12x=4+14

    2x=18x=9So,14 (x-1)=14 (9-1)=112Answer: The original stipulated time was 9 hours; The distance between A and B is 112 km.

  2. Anonymous users2024-02-05

    Set the specified time to be x hours, and set the distance between ab and the two places to y

    Then we get the system of equations: y 12 = x + 1 3

    y 14=x-1 after subtraction.

    The solution is y=112x=9

  3. Anonymous users2024-02-04

    (1) Let the original specified time be tmin, according to the title:

    12(t-20)=14(t+60)

    Solution: t=540min=9h

    2) The distance between the two places is:

    14*8=112km

  4. Anonymous users2024-02-03

    Solution: Set the original time to x hours.

    20 minutes = 1 3 hours.

    12*(x+1/3)=14(x-1)

    12x+4=14x-14

    2x=18x=914*(9-1)=112(km)

    A: The original regulation was 9 hours, and the distance between A and B was 112km.

    I don't know how to ask me!!

  5. Anonymous users2024-02-02

    Solution: Set the specified time to x

    12*(x+20)=14*(x-60) (1 hour equals 60 minutes, * represents the multiplication sign).

    The solution is x=540

    Then the distance is equal to 12 * (540 + 20) = 6720 A: The original stipulated time is 540 minutes, and the distance between A and B is 6720 kilometers.

  6. Anonymous users2024-02-01

    This problem can be solved without equations.

    You can make it with a ratio.

    You give it a try. If you don't, you can ask me.

  7. Anonymous users2024-01-31

    a6n+4y=3y-3m

    4y-7y=-3m-6n

    3y=-3m-6n

    y =m+2n

    The gene of the front ruler is y=1

    The shooting is m+2n=1

  8. Anonymous users2024-01-30

    The title seems a little wrong, right?。。。

  9. Anonymous users2024-01-29

    In the first year, the profit of factory A is 100 million, and B is 10-x billion.

    Therefore, x=6

    In the first year, the profit of factory A was 600 million, and the profit of factory B was 400 million.

    In the second year, factory A made a profit of 100 million, and factory B made a profit of 100 million.

  10. Anonymous users2024-01-28

    Factory A's profit in the second year is x

    Factory B's profit in the second year is 10*(1+12%)-x=x*(1-10%)+

    x = the profit of factory A in the second year.

    Factory B's profit for the second year is.

  11. Anonymous users2024-01-27

    Solution: The profits of factories A and B in the second year are x and y respectively

    Then x+y=100(1+12%), x(1+10%)+y(1+15%)=100, x=66, y=46

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