Olympiad Engineering Problems I think it s difficult

Let the workload of B be x, then the workload of A is 3x 2, there are y workers, there are workers 3y (1+3)=3y 4 at site A in the morning, there are y 4 people at site B, 3y 4+y 4*7 12=43y 48 at site A in the afternoon, and y-43y 48=5y 48 at site B

A is just done, 3x 2=3y 4 2+43y 48 2=79y 96B's work x=y 4 2+5y 48 2+4=17y 96+479y 96=(17y 96+4)*3 2 Is the question correct??

Every 1 12 batches of workers is considered as a squad, and its efficiency is to complete x number of work sites per day.

Then 9x 2+7x 2=3 2,x=3 16 from site A, the part that has been done at site B is 3x 2+5x 2=3 4, and the remaining work is 1-3 4=1 4

Let several squads do this work, and to do it in one day, it takes 4 or 3 squads.

Then 4 3 squads = 4 people.

All workers = 12 squads = 36 people.

In the afternoon, seven-twelves of the workers went to site B.

What is the meaning? What happened to Seven Twelve? Did you drop the word?

Let's take a look at the parts that will be completed in 4 days.

The ergonomics is increased by 50%, and the same work is completed for the original 1+50%=3 2, and the time taken is the original 2 3

To complete this part of the work according to the original ergonomics, it is required:

1 (1-2 3) = 3 days.

With the original method, to complete the whole work, it is required: 4 + 3 = 7 days to look at the part after 200 meters.

With the original method, it was needed: 2 (1-2 3) = 6 days then 200 meters were repaired by the old method, and it was used in: 7-6 = 1 day to repair 200 1 = 200 meters per day.

Analysis: After doing it for 4 days, then the following tasks will be completed in a new way: 1 50% 2 days to complete, then the subsequent tasks will be planned to be:

2 1 3 days, a total of 4 3 7 days If you do 200 meters first, the remaining tasks will be: 2 50% 4 days then the previous 200 tasks are actually used:

7 4 2 1 days actually do it every day: 200 1 200 meters.

After improving work efficiency, if the work is completed according to the planned time, 1 + 50% = portions will be done for another 1 day, and 50% more than planned every day, then the planned number of days is 4+ days.

Completed 2 days ahead of schedule, indicating that the plan will take days.

Then it is planned to repair 200 (7-6) = 200 meters per day.

I said I don't want equations.

The column formula can be considered in this way, if the first 4 days also use the new construction method, then the completion of the whole project can be 1 + (4-4 days, these 7 3 days are equivalent to the original total construction days (1-1, so that the original total construction days are 7 days. If you want to list a general formula, it is [1+(4-4 days; In the second process, only 2 days ahead of schedule was completed, which was 7 3-2 = 1 3 days more than all according to the new construction method, and the extra 1 3 days was due to the fact that the first 200 meters were constructed according to the old method, so it took (1 3) (1-1 days) to repair 200 meters according to the old construction method, so that the original plan was to repair 200 1 = 200 meters per day.

This topic can do that.

The original plan was to repair x meters per day, and it would take y days to complete.

4x+ solution: y=7 that is, the original plan was to be completed in 7 days.

Simplification: 200+

Solution: x = 200 meters.

The original plan was to repair x meters per day and complete it in y days.

4x+ solution: y=7

That is, it was originally planned to be completed in 7 days.

Simplification: 200+

Solution: x = 200 meters.

Let the work efficiency of A be A, and the work efficiency of B is, according to the title: 36 A + 28 B = (A + B) * 48

36 A + 28 B = 48 A + 48 B.

So, 12 A = 20 B.

A = 5 3 B.

Then remove the 42 days that A did alone from the total workload, 48 A + 48 B - 42 A = 6 A + 48 B.

6*5 3B + 48B.

30 B + 48 B.

78B. So it takes 78 days for Huan B to complete the task.

28 1 48 = 7 12 A B 28 cooperative.

1-7 12 = 5 12 A 36-28 = 8 days to complete.

5 12 8 = 5 96 A is done every day.

Something is wrong with your numbers. Check where you made a mistake.

24.100% sure, if you find the answer the same as mine, mine, I'll tell you about the process.

The amount of work done by the five engineering teams per day is as follows: From the question, the engineering team does 1 12 (1) per day The engineering team does 1 7 (2) The engineering team does 1 8 (3) per day The engineering team does 1 42 (4) (2) -(1): i.e. 5 84 more per day is written as - =5 84 (1) - (4): that is, 5 84 is written as -=5 84 (2) -(4):

That is, do 5 42 more per day than write - =5 42 so: can calculate =1 24 can calculate , or you can not calculate (1) + (3): get + =5 24 so + =5 24- =5 24-1 24 = 1 6 i.e. five engineering teams work together to do 1 6 per day

Therefore, the cooperation of the five engineering teams will take 6 days to complete.

The word in the question indicates what each engineering team does every day.

It takes 6 days.

1 3 4 42 A It takes 8 days for the engineering team Then it takes 4 days for the two engineering teams to put all the teams together.

That is, the engineering team is a group, the engineering team is a group, the engineering team is a group, the engineering team is a group, and all these teams are combined to complete the project.

Then it is equivalent to 3 engineering teams to complete the project, it takes 1 (1 12 + 1 7 + 1 4 + 1 42) = 2, then it takes 2 * 3 = 6 days for the engineering team to complete.

No. 1, 2, 3 valves per minute 1 20

No. 2, 3, 4 valves per minute 1 21

No. 1, 3, 4 valves per minute 1 28

Valves No. 1, 2, 4 are 1 30 per minute

1 20 + 1 21 + 1 28 + 1 30 = 1 6 is three times the working efficiency of 1, 2, 3 and 4 valves.

1 6 divided by 3 equals 1 18 is 1, 2, 3, 4 valve efficiency and 18 points to complete.

A and B cooperated for six days and completed: 8*8 81=8 8 Then B completed in 81 days: 8-8 8=8 8 that is, B completed in one day:

8 8) 81 = 8 81 A completes in one day: 8 81-8 81=8 88 then A alone: 8 [8 88]=88 days, B to:

8 [8 81] = 81 days.