Which computer teacher helps! 10

Summary. Hello dear! Could you please describe your problem more specifically, e.g. in what language is it written in? Tell the teacher in detail so that the teacher can better help you.

Hello dear! Could you please describe your question more specifically, such as what language is it written in? Tell the teacher in detail, so that the teacher can help you more well.

How many questions, what types, what subjects.

Please describe it to me in the text.

**The distortion is serious, please describe the expression.

erroneous/boundary xextreme xnormal xabnormal x

And there's more. types of test datadescriptionerroneous/boundary xextreme xnormal xabnormal x

Test data types that are always within the acceptable range of the hypsum mask can be described as an error boundary. Test data types that are within the acceptable limit or just outside the acceptable limit can be described as extreme. A test loss data type that is always rejected can be described as an anomaly.

The type of test data within the acceptable range can be described as normal.

4 * 7 * 8 * 4 = 896 people, each student is guaranteed to have one Internet port, 1 is equipped with 4 CISCO6509, each of which provides no less than 224 Internet ports, that is, 5 boards with 48 ports.

2 Connect the server to one or two boards separately, depending on the number.

3 4 devices do VSS virtual into one, do NAT in the exit direction, ** Internet access.

4 Control the broadcast storm through the features of the Cisco device, Storm-Control, reduce the broadcast domain, and divide multiple VLANs to go through Layer 3.

5 Boson Simulation is very old, and now there are new ones that are better to use.

One bit of address stores one byte (i.e. 16), 1000h is 4096 (16 3) in decimal, and 4fffh is 20479 (20480-1) in decimal, so the storage space is 16384 bytes, which is 16384 1024 = 16kb, and the first two are the same so the answer is the same.

The third is the second minus the storage space of 1000 addresses, that is, 4096, so the storage space is 12288 1024=12kb

The last one can be seen as 0001 10000, so the storage space is 65536 1024 = 64kb

The first question, which is a very simple math problem, does it take the same amount of time to pass 10 people through 10 people and 100 people through a door?

The second problem, the phenomenon you mentioned, if it exists, the hard disk is broken, qualified mechanical hard disks usually do not exist this phenomenon (if there is a strong magnetic field around, it is possible to lose data), the solid state drive used now, the quality is relatively poor, this situation may occur, the reason is the loss of flash memory chip data.

, which means that the last 24 bits (bold) are non-1 host bits, which are not broadcast addresses (if the host bits are all 1s, they are broadcast addresses and cannot be used), so they can be used;

, which means that the last 19 bits are not all 1 host bits, which is not the broadcast address, so it can be used;

, which means that the last 24 bits (italics are bolded) are all 1 host bits, which is the broadcast address, soIt cannot be used

, which means that the last 19 bits (italics are bolded) are all 1 host bits, which is the broadcast address, soIt cannot be used

, which means that the last 24 bits (bold) are non-1 host bits, which are not broadcast addresses (if the host bits are all 1s, they are broadcast addresses and cannot be used), so they can be used;

, which means that the last 19 bits (bold) are not all 1 host bits, which is not the broadcast address (if the host bit is all 1, it is the broadcast address and cannot be used), so it can be used;

, which means that the last 24 bits (italics are bolded) are all 1 host bits, which are not broadcast addresses, so they can be used;

, which means that the last 19 bits (italics in bold) are all 1 host bits, which are not broadcast addresses, so they can be used;

I don't think there's an address available.