A sophomore organic chemistry inference problem It is known that A can undergo the following reactio

The unsaturation of C13H18O7 is 5°, and the unsaturation of more than 4° indicates that there may be a benzene ring.

A(C13H18O7, relative molecular mass 286) plus a molecule of water to produce B (glucose with a relative molecular mass of 180, molecular formula C6H12O6) and unknown substance C, it can be inferred that C has a molecular formula of C7H8O2 and a relative molecular mass of 124.

C oxidizes to D under appropriate conditions (C7H6O3, unsaturation is 5, there may be benzene ring), C undergoes color reaction when it encounters ferric chloride, indicating that there are phenolic hydroxyl groups, and 1molC reacts with sufficient sodium to form 1mol hydrogen, indicating that there are 2 hydroxyl groups. The benzene ring has only 4 unsaturations, so it can be known that d has a carboxyl group. C is hydroxymethylphenol, D is hydroxybenzoic acid (according to the later said D acetylation to produce E is a common drug, it is known that D is o-hydroxybenzoic acid, that is, salicylic acid, and E is acetylsalicylic acid, that is, aspirin).

D and (CH3CO)2O to produce CH3COOH and unknown substance E, this is a substitution reaction, (CH3CO)2O is acetic anhydride, in fact, it is also esterification, or acetylation. E is a common drug, E can react with sodium bicarbonate solution to release carbon dioxide.

Find: the molecular formula, b is able to occur the type of chemical reaction (write two).

Answer: The molecular formula of B is C6H12O6, which can react with the new copper hydroxide suspension and silver ammonia solution, and esterification reaction can occur.

The structure of the short formula: no stickers, review is too time-consuming, say the name, acetylsalicylic acid, is salicylic acid (phenolic hydroxyacetylation of o-hydroxybenzoic acid to produce acetate).

3.It is an isomer with d, containing a benzene ring and containing an ester group

A: Don't draw anymore, you can draw according to the explanation below. It is to change the carboxyl group to the formate group, and then move the phenolic hydroxyl group to form three structures of the adjacent pair.

Chemical equation for reaction with sodium, equation for reaction with sodium bicarbonate solution:

Answer: Both hydroxyl groups in C can react with sodium. H+ ionized by carboxyl group in D combines with HCO3- to form carbonic acid and decomposes into CO2 and water.

Hehe, I studied physical structure.

The answer is not true!

According to the esterification reaction (under certain conditions, one mole of C and two moles of B completely react to form esters), it can be seen that C has two alcohol hydroxyl groups and B has a carboxyl group, and the relationship between the combination and the front and back (B with the molecular formula C2H2O2Cl2 is obtained after oxidation of organic compound A, and C is obtained after hydrolysis of A), and the conclusion is obtained

A is Cl2CH2OH, B is Cl2CHcoOh, and C is Hoch(Cl)CH2OH.

The ester is Cl2CHCOOCH(Cl)CH2OOCCHCL2, and the molecular formula is C6H5O4Cl5;

The molecular formula and oxidation products of B can be inferred that B is dichloroacetic acid instead of alcohol, and C is completely reacted with two moles of B to form an ester, then C is a diol (but not necessarily ethylene glycol), and the answer given is only the simplest possibility.

These substances are all determined based on the degree of unsaturation and the associated reactions.

A is benzaldehyde.

c6h5-cho

A and acetic anhydride CH3-CO-O-Co-CH3 are addition reactions, and after reducing acetic anhydride, the structure of A will be found.

The structure of b is:

Benzene ring ortho. One is -OH, and the other is CH(OH) CH2 COOH, which is obtained by ester hydrolysis of the substance in front of B, and C is the product of intramolecular esterification of B.

There is also a ring next to the benzene ring, which is a cyclic ester.

D, on the basis of C, the -OH on the ring on the right side of the benzene ring is eliminated to obtain Cc

The unsaturation of C4H10O is 0, which is an alcohol or ether; AB can react with Grignard reagent as alcohol, emitting flammable gas: methane comes from the methyl group of Grignard reagent and the hydroxyl group of alcohol. [B can react with acidic dichromate, A, C do not.

Explain that A is a tertiary alcohol and B is a primary or secondary alcohol. [A and b are heated with phosphoric acid to obtain the same product.] ] indicates that the skeleton structure is consistent, and it is an elimination reaction to generate alkene.

C reacts with a molecule of Hi, and one of the products is isopropanol. Hydrohalogenic hydrolysis of ether to form alcohols and halocarbons. , the binding formula is methylisopropyl ether.

Structure: A tert-butanol B 2-methyl-1-propanol C methylisopropyl ether.

Structural formula: CH3 CH3 CH3

ch3——c——oh ch3——ch——ch2——oh ch3——ch——o——ch3

ch3

A 2-methyl-3-pentanone (CH3), 2CH (C = O), C2H5B 3-methyl-2-ethyl-butanol (CH3), 2CH (OH) C2H5C 2-methyl-2-pentene (CH3) 2C = CHC2H5D acetone, CH3-(C=O)-CH3

e acetaldehyde CH3CH2CHO

A can undergo iodoform reaction, indicating that A is a methyl ketone.

B can undergo a silver mirror reaction, indicating that B contains -cho.

C has both methyl ketone structure and -cho structure.

Potassium permanganate oxidation, indicating that it contains a double bond and the molecule is broken into 2 fragments, which are 2-butanone and C Therefore, the structure of a, b, c:

Please note that the original question is not rigorous, and the oxidation of KMno4 double bonds gives carboxylic acids or ketones, but does not give the aldehyde group in C.

But in order to have an answer, it has to be like this.

There seems to be a problem with the title, how can there be groups that can undergo silver mirror reaction after oxidation with potassium permanganate? I guess it's oxidized with ozone.

A is a ketone with a methyl group and B is an aldehyde, and both contain double and double bonds. c is acetaldehyde... I think it can be launched.

Upstairs is the right solution! , but I can push down from d and e according to the conditions, d must be propionaldehyde, e must be acetone, and then push forward in turn, and the answer is the same.

It can form a yellow precipitate with 2,4-dinitrophenylhydrazine, indicating that there is a c=o group, and it will not react with Toren reagent to form a silver mirror, indicating that it is not an aldehyde but a ketone. A catalytically hydrogenates to obtain compound B, then B is an alcohol. B is reacted with concentrated sulfuric acid at high temperature to obtain compound C, that is, the alcohol hydroxyl group is eliminated to form a carbon-carbon unsaturated double bond, and C is an olefin.

C is treated with ozone and zinc powder to obtain a molecule of aldehyde D and a molecule of ketone E, and the ozone hydrolysis reaction occurs to generate an aldehyde and a ketone, indicating that the carbon skeleton is T-shaped, and there are only 6 carbons, and its skeleton can only be.

c cc-c-c=c or c-c=c

c c-cd cannot react with iodoform, indicating that d does not have a -coch3 structure, and the second carbon skeleton can be ruled out, then c is.

ch3ch2ch2=c(ch3)2

Extrapolating backwards to A, then A is CH3CH2Coch(CH3)2

c6h6o6

The structure is a benzene ring with 6 and hydroxy-6 hydroxyphenol bar.

Complete combustion to produce CO2, H2O ==> contains only C H or C H O elements.

The amount of CO2 produced is equal to the amount of O2 = = > H number: O number = 2:1

1molA with sodium yields 3molH2 ==> -OH number + COOH number = 6

The position of c in the infrared spectrometer is exactly relative ==> and cannot be -cooh, but only 6 -oh

n(o)=6,n(h)=2*6=12,n(c)=(180-16*6-12*1)/12=6

Molecular formula: C6H12O6

Brief structure: cyclohexanol (6 C's form a ring, each C is connected to a -OH).