The contoured triangle puzzle is made by super toppers!! The best to use your brain!! The first year

It depends on your personal knowledge

1,3 Definitely true; 2 Not true.

1. It is easy to prove that the congruent triangle can be understood as the same triangle is obtained by translation, then the corresponding midline, high and angle bisector correspond to equal, of course, all of which can be proved according to congruence;

3. Congruence can be proved with "corner edges". If the two horns are equal, then the third horn will also be equal.

Add one more side and you will be proven.

In 4, "the height on both sides and the third side corresponds to the congruence of two triangles equally" can be proved with "hypotenuse right-angled edge".

But the height on both sides and the height on one of the sides corresponds to two equal triangle congruences. Can't think of a way to prove it.

It should be 2 pcs.

It's d.,But the detailed proof has to draw some pictures.,At least 12 drawings have to be drawn here.,There's no way to draw it.,But the judgment method can tell you:

1st: SAS for the midline, AAS for the high, ASA for the angular bisector

Step 2: First, use SSS to prove the congruence of two small triangles, get a set of base angles corresponding to equality, and then use SAS

Step 3: Prove the congruence of two small triangles with AAS or ASA to get a set of corresponding sides equal, and then use AAS or ASA

4th: First use HL to prove the congruence of two small triangles, get a set of bottom angles are equal, and then use SAS, I hope it will help you!

Find the congruence twice, the first time the triangle ADC is equal to the triangle ABE, and then the DPE is equal to EPB.

Make an auxiliary line, set the intersection of DE and CB to P, BC midpoint M, connect. ∠abc=∠acb=∠cbe=∠abc=∠deb=∠cbe=∠mde=∠dmb=45°

Therefore, the triangle MDP congruent macro permeability is like the triangle BPE. and got the revelation of the knot.

Think like this direction.

There are four methods: three sides, two sides and their angles, two corners and their edges, two corners and the opposite side of one of them.

Example: Knowing that in abc and triangle def, ab=de, ac=df, bc=ef, verify abc def.

Proof: In abc and def, ab=de, ac=df, bc=ef, so abc def

Three-sided congruence or two angles plus an edge or two sides plus an angle.

I've done it for people before, just repeating the answer. See for yourself. As for what SAS means, you can see for yourself, the example questions are just applied, you can see these and you will understand it.

1.An equilateral triangle with all sides of 1 and an equilateral triangle with all sides of 2 (both 60 degrees of angle, AAA) are not congruent.

2.I'm sorry I can't show you the picture, you draw a triangle of "a=60°, b=30°, c=90°", and then c is the top to make a high intersection ab at the point d, find a point e on db to make ad=de, connect ce (you should understand that this way you get ac=ce), then abc and ebc are in line with ssa (ac=ec, bc=bc, b= b) but not congruent. (A very simple picture, found that I am so verbose b sweat).

Triangle rulers used by students and triangular rulers used by teachers.

Isosceles right triangles with different side lengths do not match.