Find the solubility mass fraction of the quantity and concentration of the substance conversion form

Well, let the mass of the solution be m, the solubility is s, the mass fraction is w, the concentration of the substance is c, and the density of the solution is p

m is the molar mass of solute.

c = the amount of solute material in the volume of the solution.

1.Amount of solute material = m * w m

Solution volume = Mp

Collation yields c=(mw m) (m p).

Then sort out c=pw m

But since the unit of density is g cm3 and the quantity concentration of the substance is mol l, in order to unify the unit c=1000pw m

2.If in a saturated solution with known solubility, we can get w = s (100+s) and bring w into c = 1000 pw m, c = 1000 ps [(100 + s)m].

Note: The unit of C is mol l, the unit of P is G, the unit of cm3 is G, and the unit of S is G

1.If the unit of density is g cm3, then c=PW m

2.If the unit of density is kg m3, then c = 1000 pw m [Note: p is the density, w is the mass fraction, m is the relative molecular mass, and c is the amount concentration of the substance].

s=100c/1-c

s=100c*m/1000d-c*m

c=c*1000d/m

Other than that. The mass score is c?I remember it was w....

Where are you, I haven't learned it either.

Concentration of a substance: The amount of a solute contained in a single or land-based volume solution is called the concentration of a solute.

Quiet calculation formula and derivation formula before change:

1. Set the unit volume to 1L=1000ml (the conversion unit is because it is the same as the density unit).

2. The basic formula for the quantity concentration of a substance is c=n v, where n represents the amount of the solute substance, and v represents the volume of the solution.

Then according to n (the amount of the solute) = m m, and m (the mass of the solute) = v

3. The mass of the solute = the volume of the solution and the percentage of the solute, so it can be obtained, m (mass of the solute) = v = 1000ml w

4. Bring this in n (the amount of solute substance) = m m, and get n = 1000ml w m

5. Finally, bring in c=n v, and get c= 1000ml w m 1l.

The formula for calculating the quantity concentration of a substance is a formula used to calculate the quantity concentration of a substance. The content of the formula is: the amount of solute = the amount and concentration of solute x the volume of solution n = c·v. This formula is also called Moore's Law.

The ratio of the mass of the solute to the mass of the solution, called the mass fraction of the solute (expressed in w, formerly known as the mass percentage concentration).This is a commonly used representation of the composition of a solution, and the formula is:

Mass fraction of solute = (solute mass solution mass) * 100% = solute mass (solute mass + solvent mass] * 100%.

Example 10 g of sodium chloride dissolved in 90 g of water in the resulting sodium chloride solution.

Mass fraction of solute = 10 100 = 10%.

The conversion formula between the quantity concentration of the substance and the solute mass fraction is: c = 1000 * d * w m, where: c is the amount concentration of the substance, d solution density, w solute mass fraction, m molar mass of the solute.

Derivation process: n=m v

The unit of d: g cm3, or g ml

Let the volume of the solution be v = 1000 ml = 1 l

The mass of the solution is: m = 1000 VD

The mass of the solute is: m=1000vdw

Amount of solute substance: n = 1000 VDW m

The amount of substance concentration of the solution: c = n v = 1000 * d * w m

Question: The volume of liquid is l liters. The density is p, molar mass.

is m, the amount concentration of the substance.

is n, and the mass score is q%.

Then: the mass of the volume is n*l*m (in g).

The mass of the liquid is l*1000*p (in g).

Thus, q% = (n*l*m l*1000*p)*100%=(n*m 10*p)%.

The quantity that must be known in the formula: the quantity concentration of the substance; molar mass; The density of the solution.

The amount of solute material = m * w m solution volume = m p, collated to obtain c = (mw m) (m p) and then sorted c = pw m; But since the unit of density is g cm3 and the quantity concentration of the substance is mol l, in order to unify the unit c=1000pw m

If in a saturated solution with known solubility, we can get w = s (100+s) and bring w into c = 1000 pw m, c = 1000 ps [(100 + s)m].

Quantity concentration of a substance: The amount of a substance containing solute per unit volume of solution, called the concentration of a substance of solute.

Conversion Formula and Derivation Formula:

1. Set the unit volume to 1L=1000ml (the conversion unit is because it is unified with the density unit) 2. The basic formula for the quantity and concentration of a substance is c=n v, where n represents the amount of solute and v represents the volume of the solution.

Then according to n (the amount of the solute) = m m, and m (mass of the solute) = v3, the mass of the solute = the volume of the solution and the percentage of the solute, so it can be obtained, m (mass of the solute) = v = 1000ml w

4. Bring this in n (the amount of solute substance) = m m, and get n = 1000ml w m

5. Finally, bring in c=n v, and get c= 1000ml w m 1l.

The amount of a substance containing solute in 1 l of solution is the amount concentration of the substance.

1l=1000ml

1000*d = solution mass.

1000*d*w% is the solute mass.

1000*d*w% m is the amount of solute substance.

c=1000*d*w%/m

c = = n v = m (solute) m v = = m (solution) * w (solute mass fraction) m v = = p (density) * v * w m v = = p * w m

It is obtained that C (concentration) is equal to the product of p (density) and w (solute mass fraction) divided by m (molar mass.

Sen Fiber; Because.

The unit of p (density) is usually g cm3, and the unit of c is mol ml. The unit of the middle stool of c (concentration) is mol l, in order to make the unit mol l; So c==1000pw m

Let the mass of the solution be m, the solubility is s, the mass fraction is w, the concentration of the substance is c, and the density of the solution is p

m is the molar mass of solute.

c = the amount of solute material in the volume of the solution.

1.Amount of solute material = m * w m

Solution volume = Mp

Collation yields c=(mw m) (m p).

Then sort out c=pw m

But since the unit of density is g cm3 and the quantity concentration of the substance is mol l, in order to unify the unit c=1000pw m

2.If in a saturated solution with known solubility, w=s (100+s) can be obtained

Bring w into c = 1000 pw m and c = 1000 ps [(100+s)m].

Note: The unit of C is mol l, the unit of P is G, the unit of cm3 is G, and the unit of S is G

One of the errors in the question is 1g ml = 1000g l 1ml = make no mistake about it.

There are generally two ways to convert this unit: (Take g ml into g l as an example) one: you directly use 1ml = 1 1000l for this, and you can get 1g ml = 1g (1 1000) l = 1000g l two:

Or multiply the numerator denominator of 1g ml by 1000.

That is: 1g ml = 1000g 1000ml, you can get 1g ml = 1000g l

..For the first question.

1kg l=1000kg m3=1000000g m3, you can use the above method to calculate it yourself.

Second question.

1l= So 1g l=1000g m31ml=1cm3 That is to say, 1g cm3 =1g mlIn short, this is a lot, you can write it directly, and you need to practice. -If you still don't understand QQ or hi me.

The conversion formula between the quantity concentration of the substance and the solute mass fraction is: c = 1000 * d * w m, where: c is the amount concentration of the substance, d solution density, w solute mass fraction, m molar mass of the solute.

Derivation process: n=m vThe unit of d: g cm3, or g mlLet the volume of the solution be v = 1000 ml = 1 l

The mass of the solution is: m = 1000 VD

The mass of the solute is: m=1000vdw

Amount of solute substance: n = 1000 VDW m

The amount of substance concentration of the solution: c = n v = 1000 * d * w m

Kilograms per liter to grams per cubic meter are multiplied by one hundred, one gram per cubic meter is equal to grams per liter, grams per cubic centimeter and grams per milliliter are the same. To put it bluntly, it is the relationship between several volume units, 1 cubic meter, 100 liters, 10 5 milliliters, 10 5 cubic centimeters (but usually when finding the quantity and concentration of a substance, it only involves the conversion of milliliters and liters, multiplied by one thousand).

The formula c = 1000pw m p density w mass fraction m molar mass.

By solubility. The maximum number of grams of solute that can be dissolved in 100 g of solvent is s

Quality score. The formula is w=m.

M liquid. According to the above two definitions, w = m substance, m liquid = m quality (m quality + m water) = s (s+100).

So ws+100w=s;

1-w)s=100w;

s=100w/(1-w)