Chickens and rabbits are in the same cage, with 45 heads on the top and 126 feet on the bottom, how

Updated on educate 2024-04-06
17 answers
  1. Anonymous users2024-02-07

    If the chicken has x, then the rabbit is 45-x

    2x+4(45-x)=126

    2x+180-4x=126

    4x-2x=180-126

    2x=54x=27

    A: 27 chickens and 18 rabbits.

  2. Anonymous users2024-02-06

    Virtual (imperative) method to solve problems.

    Command all rabbits to lift their first two feet (not to the ground), and only the last two feet to land on the ground, then, there should be on the ground.

    45 2 90 feet, feet that do not touch the ground should have.

    126 90 36, these 36 are just the front feet of the rabbit, then, the rabbit has.

    36 2 = 18 rabbits.

    45 18 27 chickens.

    Simple and straightforward, all similar problems can be solved using the "command method".

  3. Anonymous users2024-02-05

    Solution: There are x chickens and 45-x rabbits.

    Because chickens have two legs, rabbits have four.

    So: 2x+4(45-x)=126

    2x+180-4x=126

    2x= - 54

    x=27 then there are 27 chickens and 45-27=18 rabbits.

  4. Anonymous users2024-02-04

    Solution: There are x chickens, rabbits have (45-x), then.

    2x+4(45-x)=126

    2x+180-4x=126

    2x-4x=126-180

    2x=-54

    x=2745-x=45-27=18

    A: There are 27 chickens and 18 rabbits.

  5. Anonymous users2024-02-03

    Using the binary equation, let's assume that chickens have x and rabbits have y.

    2x+4y=126

    x+y=45

    x=27y=18

  6. Anonymous users2024-02-02

    There are 18 rabbits and 27 chickens.

    Here's the equation:

    Solution: There are x rabbits, and there are (45-x) chickens.

    4x+2(45-x)=126

    4x+90-2x =126

    2x+90 =126

    2x+90-90 =126-90

    2x=36x=36÷2

    x=18 (only).

    45-18=27 (only).

    A: There are 18 rabbits and 27 chickens.

  7. Anonymous users2024-02-01

    Solution: If there are x chickens, there are (45-x) rabbits.

    2x+4(45-x)=126

    2x+180-4x=126

    2x-4x=126-180

    2x=-54

    x=2745-27=18 (only).

  8. Anonymous users2024-01-31

    How many chickens and rabbits are there?

  9. Anonymous users2024-01-30

    Assuming that all of them are prepared to watch rabbits, then the chickens have:

    45 4-126) (4-2) Carry let, 54 2, 27 (imitation and only), then rabbits have: 45-27 = 18 (only), answer: 27 chickens, 18 rabbits

  10. Anonymous users2024-01-29

    Assuming it's all chickens, then the scum slippery rabbit has:

    8 (wax only).

    Chickens: 20-8 = 12 (pcs).

    Answer: There are 12 chickens and 8 rabbits

  11. Anonymous users2024-01-28

    If there are x chickens, then (48-x)*4+2*x=156, the solution: x=18, that is, there are 15 chickens and 30 rabbits

  12. Anonymous users2024-01-27

    Let the rabbit be x, then the chicken is (56-x), the number of rabbit feet is 4x, the number of chicken feet is 2 (56-x), and by the known conditions, the chicken rabbit has a total of 160 feet, and the equation 4x+2(56-x)=160 can be listed

    Remove the parentheses to get 4x+112-2x=160, and merge the same terms 4x-2x=160-112, that is, 2x=48, so x=24

    Thus 56-24 = 32

    A: There are 24 rabbits and 32 chickens

  13. Anonymous users2024-01-26

    Let the rabbit be x, then the chicken is (56-x), the number of rabbit feet is 4x, the number of chicken feet is 2 (56-x), and by the known conditions, the chicken rabbit has a total of 160 feet, and the equation can be listed.

    4x+2(56-x)=160.

    Remove the parentheses to get 4x+112-2x=160, and merge the same terms 4x-2x=160-112, that is, 2x=48, so x=24

    Thus 56-24 = 32

    A: There are 24 rabbits and 32 chickens

  14. Anonymous users2024-01-25

    Suppose there are x rabbits and (36-x) chickens.

    36-x)×2+4x=100

    2x=28x=28÷2

    x = 14 chickens have: 36-14 = 22 (only).

    A: There are 22 chickens and 14 rabbits.

    Or. Let's say it's all chickens.

    With feet: 36 * 2 = 72 (only).

    Total difference in the number of feet: 100-72 = 28 (only).

    A rabbit has 2 legs, and 28 feet have a total of rabbits: 28 (4-2) = 14 (birds) Chickens: 36-14 = 22 (birds).

  15. Anonymous users2024-01-24

    Chickens and rabbits are in the same cage, with 20 heads and 54 legs, how many chickens and rabbits are there? Primary school math chicken and rabbit in the same cage problem application problem.

  16. Anonymous users2024-01-23

    Let the rabbit be x, then the chicken is (56-x), the number of rabbit feet is 4x, the number of chicken feet is 2 (56-x), and by the known conditions, the chicken rabbit has a total of 160 feet, and the equation 4x+2(56-x)=160 can be listed

    Remove the parentheses to get 4x+112-2x=160, and merge the same terms 4x-2x=160-112, that is, 2x=48, so x=24

    Thus 56-24 = 32

    A: There are 24 rabbits and 32 chickens

  17. Anonymous users2024-01-22

    Suppose there are x rabbits and (36-x) chickens.

    36-x)×2+4x=100

    2x=28x=28÷2

    x = 14 chickens have: 36-14 = 22 (only).

    A: There are 22 chickens and 14 rabbits.

    Or let's say it's all chickens.

    With feet: 36 * 2 = 72 (only).

    Total difference in the number of feet: 100-72 = 28 (only).

    A rabbit has 2 legs, and 28 feet have a total of rabbits: 28 (4-2) = 14 (birds) Chickens: 36-14 = 22 (birds).

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