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Anonymous users2024-02-07Pressure = 5dm
If the ball of 5 cubic decimeters is completely immersed in water, the buoyancy is 5*g, and the buoyancy of the ball is 5*g, and the ball 2kg = 2*g<5g, so the ball is floating on the surface of the water, and the buoyancy is received = 2*g.
The mass that overflowed from the barrel was 2kg
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Anonymous users2024-02-06Topic: The hydraulic formula p=PGH (p is density), substitution can be done.
Problem: 5dm3=, so p-ball = so floats in water, so f floats = g (float and sink condition), so f floats = 2kg * because f floats = g row so g row = g = , so the overflowed mass m = 2kg
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Anonymous users2024-02-051.5dm = p = density * g * h = 5000 pa25dm3= p=m v=2 400kg m3 is less dense than water, so it floats.
For a floating object, buoyancy is equal to gravity = g = mg=2kg*10n kg=20n
3.Because of the Archimedes' principle. The gravitational force of the object discharging water is equal to the buoyancy of the object. So the gravity of the overflowing water = f float = 20n
Do you understand? Happy learning!
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Anonymous users2024-02-04The mass of buoyancy 50 Ox spilled from the bucket was 5 kg.
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Anonymous users2024-02-03Radius 4 2 = 2 decimeters.
5 cm = decimeter.
So it's liters.
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Anonymous users2024-02-02r=6/2=3dm
Cylindrical barrel water volume v = r 2 * h = cubic decimeter.
That is, the barrel can hold 150kg < water
So no.
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Anonymous users2024-02-01The mass of the loaded water m =
So the total gravity g=(m+m)g=(
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Anonymous users2024-01-31The pressure of water on the bottom of the bucket = 10 1 = 10 (g c) is that. Barrel pressure on the water surface = 0.
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Anonymous users2024-01-30The pressure of the water on the bottom of the bucket is the gravity of the water g=20n; Pressure p=g s=20 n m 2.; There is no contact surface between the water surface and the wooden pass, so there is no pressure pressure, except that the bottom of the barrel is a contact surface, there is also a barrel wall, and the pressure is p=2000 Newtons per square meter.
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Anonymous users2024-01-29The main formula is: f=ps
Because the water weighs 45N, the pressure is 45N.
Obtained by f=ps.
p=f/s=45n/(2*10^(-3))=
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Anonymous users2024-01-28Liquid pressure formula.
p=density of water g h
kg/m^3 ×
2940pa
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Anonymous users2024-01-27P=GH is used to directly substitute the numerical calculation.
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