The following ions can coexist in large quantities in solution

The requirement for the coexistence of a large number of ions is that the ions do not react, neither form a weak electrolyte nor precipitate one of the gases.

and Ca2+ will form calcium bicarbonate, and the precipitate properties are similar to those of calcium carbonate.

and NH3 will produce ammonia which is a weak electrolyte.

and Mg2+ to form magnesium hydroxide precipitates.

So choose B

Ca(HCO3)2 and Mg(CO3)2 are both solubles (excess CO2 is introduced into lime water to precipitate first and then disappear, and the disappearance is the precipitation converted to Ca(HCO3)2).

No problem. In C, NH4+ +OH- = NH3 H2O, is a weak base.

In D, Al3+ +3OH- = Al(OH)3 (precipitate) Mg2+ +2OH- = Mg(OH)2 (precipitate).

Select B CaHCO3 hydrolysis to form gas, NH4+ and OH to form ammonia Al3+ and OH to form Al(OH)3 precipitation.

CaHCO3 and MGHCo3 in BA are slightly soluble in water.

NH4+ and OH- react in C to produce NH3

Mg(OH)2 precipitates can be generated in D.

No gases, precipitation, refractory, generated. No redox reaction, no double hydrolysis.

I think it's d, because acetate and bicarbonate are hydrolyzed in solution, making the solution alkaline. Whereas a more alkaline solution can make alo2- exist, because there is no possibility of reaction, it will only react with hydrogen ions.

In A, the stable valence states of chlorine are -1 and +7 valence, Clo- is unstable, and SO32- is the same as B ammonium ions and bicarbonate ions react and do not coexist.

C phosphoric acid is a moderately strong acid, so HPO42- must be hydrolyzed, and the solution is alkaline, so HCO32- cannot coexist.

Choose a, [al(oh)4)]-is alo2-.

Double hydrolysis of Al(OH)3 precipitates occurs with AlO2-.

h2o+alo2-=al(oh)3↓

4oh-=alo2- +2h2o

What is this aluminium hydroxide ion? Is metaaluminic acid heel? If yes.

Answer: a

Answer: CA can't, +3 valence iron is separated from the positive son to react with hydroxide ions to form a precipitate and cannot coexist in large quantities.

b No, hypochlorite ions have oxidative remorse, and iodine ions can be oxidized without coexisting in large quantities.

c Yes. d No, hydrogen ions and bicarbonate ions cannot coexist in large quantities.

d Sodium ion, copper ion, chloride ion, sulfate ion.

A hydrogen ion with hydroxide ions produces water.

b Calcium ions and carbonate ions form calcium carbonate precipitate c hydrogen ions and carbonate ions to produce carbon dioxide and water.

A H+ and OH- do not coexist (produce water), i.e. weak electrolytes. Can not coexist B Ca2+ and CO3 2- do not coexist (calcium carbonate is generated) C H+ and CO3 2- do not coexist (carbon acid is generated, carbonic acid is decomposed into carbon dioxide and water) d Yes, no precipitation and no weak electrolyte selection d

A H+ and OH- do not coexist (produce water).

BCA2+ and CO3 2- do not coexist (to generate calcium carbonate)CH+ and CO3 2- do not coexist (to generate carbonic acid, which is decomposed into carbon dioxide and water) D

H+ OH- does not coexist in A.

CaCO3 precipitate was generated in B.

H2CO3 is generated in C

d.

a. Hydrogen ion hydroxide ion.

bCalcium ions: Carbonate ions.

c Hydrogen ion Carbonate ion Selects D

a.Hydrogen ions and hydroxide ions react to form water. That is, weak electrolytes. Can't coexist.

b.Calcium ions and carbonate ions react to form a precipitate. Can't coexist.

c.Hydrogen ions and carbonate ions react to form carbon dioxide and water. Can't coexist.

So choose D

D can coexist, A, hydrogen ions and hydroxide reactions to form water, B calcium ions and carbonate react to form carbon dioxide gas C hydrogen ions and carbonate react to form carbon dioxide and water, so D pairs.

A colorless solution: indicates that there is no mnO4 (purple) in the solution

Take an appropriate amount of test solution, add excess hydrochloric acid, Youling gas is generated, and a colorless transparent solution is obtained;

It shows that there is CO32 in the solution, and there is no Ag+, Ba2+, and Al3+ at the same time, because they will all react with CO32, and now the cation is only Na+, so it has to exist.

And because of the addition of excessive hydrochloric acid, if ALO2 is present in the solution, it is now also converted to Al3+.

Excessive ammonium bicarbonate solution is added to the obtained solution, and gas is generated, and white precipitation is precipitated at the same time; Rushing spring.

Gas formation is normal, there must be excess hydrochloric acid, and excess ammonium bicarbonate to form CO2;

However, the formation of white precipitate can only be Al3+ and ammonium bicarbonate to Al(OH)3, so there must be ALO2 in the original solution.

Excessive Ba(OH)2 solution was added to the obtained solution, and gas was also generated, and white precipitate B was precipitated.

Gas formation is normal, with excess ammonium bicarbonate and ammonia formation.

But is the white precipitate baso4? Not necessarily, because ammonium bicarbonate meets the alkali into CO32-, thus giving BaCO3

In summary. Must not exist: ag+, ba2+, al3+, mno4

There must be Na+, ALO2, CO32

SO42 requires further testing.

1) Colorless solution K+, Na+, MnO4-, SO42- Because K+ Na+ salts are dissolved, they can coexist (2) CO32-, Na+, AlO2-, NO3- in the solution of pH = 1, there will be no carbonate ions in the strongly acidic solution 2H+ +CO32- =H20+CO2 (3) Add Al to the solution that can release the H2 in the solution Cl-, HCO3-, SO42-, NH4+ acid rent rolling solution can not present bicarbonate ions on the reason (4) In the solution of C(OH)-=10 -13mol L ionized by water, Na+, Ba2+, Cl-, Br- Since POH=13 ionized by water, the pH in the solution is 1, strong acid, but these ions can coexist, because the corresponding salts are soluble (5) In the solution with more Fe3+, Na+, NH4+, SCN-, HCO3- cannot coexist, because Fe3+ and the latter two ions react to produce complexes and precipitates, and there is more Fe, Then these two ions will be consumed (6) Fe3+, Al3+, No3-, I-, Cl- in acidic solution should be able to coexist No precipitation and no redox reaction a,12 b,36 c 24 d 35 What is this??? To parse, the more parsed, the higher the reward.

1) Dark green is the characteristic color of manganese ions: high manganese pyroxic acid (mNO4-) purple red (2) aluminium carbonate hydrolysis: 3CO32- +2Al3+ +3H2O=2Al(OH)3 +3CO2 (3) Hydrolysis of aluminium carbonate: 3CO32- +2Al3+ +3H2O=2Al(OH)3 +3CO2 (4) Barium hydroxide is soluble in water and ethanol; Insoluble in ether and acetone.

It absorbs carbon dioxide from the air and converts it into barium carbonate. Barium chloride solution is precipitated by the reaction of caustic soda to precipitate. (5) Fe2+ ions are generally light green in water, Fe3+ ions are generally yellow in water (6) Fe2+ ions are generally light green in water, and Fe3+ ions are generally yellow in water.

So Bu Grip chooses (4). (1) (5) (6) has color, and (2) (3) has precipitation.

Ba:H+,OH- reaction is selected to generate H2O

HCO3- reacts to generate CO2 and H2O

OH- reaction to generate Cu(OH)2 precipitate.

a. fe k no3 oh

No. Iron hydroxide precipitates can be generated.

na hco3 cl

No. CO2 gas can be emitted.

nh4 clso4

Not wild or can. The ridge was changed to barium sulfate precipitation.

k no3 so4

Yes. Zheng judged that there was no reaction between the four ions. Pick D.

This is what is covered in the section on ionic reactions. On the coexistence of ions: Coexistence:

It refers to the coexistence of a large number of ions, that is, the ions cannot react with each other, and the ion concentration does not decrease. Cannot coexist: the ions react with each other and the ion concentration decreases.

The law of non-coexistence between ions: 1. It cannot coexist in large quantities due to the formation of gas. (e.g. H+ and CO32-, SO32-, HCO3-, NH4+ and OH-, etc.) 2. It cannot coexist in large quantities due to the formation of precipitation.

Such as ag+ and cl-; Ba2+ and CO32-, SO42-, etc.; 3. It cannot coexist in large quantities due to the formation of difficult-to-ionize substances. (e.g. h+ and oh-, etc.; 4. A large number of redox anti-bond segments cannot coexist. (Such as:.)

Fe3+ with S2-, I-, etc. 5. When the solution is colorless and transparent, it does not contain color ions. Common colored ions are:

Cu2+ (blue), Fe3+ (yellow), Fe2+ (light green) or, MnO4 (fuchsia). The opposite is to be able to coexist.

A is an alkaline solution of OH- ions and Fe3+ will form Fe(OH)3 precipitate.

The solution in B is an acidic solution, and the NO3- ions show strong oxidation with the slow opening, which will oxidize Fe2+ to Fe3+

c can coexist in large numbers.

In d, HCO3- ions and H+ could not coexist in large quantities.