Two math problems, please calculate in columns!

Question 1 Number of people in the morning 276 * 5 6 = 230 people.

Number of people in the afternoon 276 * 2 3 = 184 people.

The second question is divided into three groups, which are xy z, and are arranged according to the meaning of the question.

x=1 3(y+z) y=1 2(x+z) z=10 Solve the equation to get x=6 y=8

So the three groups are 6 people, 8 people, 10 people, a total of 24 people.

1. 276 * 5 6 + 276 * 2 3-276 = 138 people.

2. Set up the first group of x people, then the second group 1 2 (x+10), the third group of 10 people, the column formula is as follows:

1 2(x+10)+10]*1 3=x solution x 6, 1 2(x+10)=8

So the number of people in the three groups is: 6+8+10 24

Question 1: 276x5 6=230, 276x2 3=184;

230 in the morning and 184 in the afternoon;

Question 2: Let the first group have x people, and the second group is y people:

x=(y+10)/3

y=(x+10)/2

So x=6, y=8

There are 24 people in total.

If there is a participant in the morning, the remaining students in the afternoon will not participate, and 2 3 1 6 1 2, half of the 276 students will participate in the study in the morning and afternoon.

Let a person, then the second group has 3a 10 people, and from equation 2 (3a 10) a+10, we can get how many people in the first group can be solved.

2.Solution: Let the second group be x, then the first group is 1 3 (x+10).

1\3(x+10)+10=x

1\3x+4\3*10=xx=6

Solution: Let the dividend be x and the divisor y

then x=3 + 8 y

248=4x+4y+8 (sum of dividends, divisors, quotients) [not counting the remainder?] 】Solve y= x=? (not in place) [the title is wrong] so the title should be:

Then the sum of the dividend, divisor, quotient, and remainder is equal to 248 ......then x=3 + 8 y

248=4x+4y+8+3×4

The solution is x=51 y=6 i.e. the dividend is 51 and the divisor is 6ps: if the divisor of the dividend is expanded to 4 times, the quotient is unchanged and the remainder is expanded by 4 times).

Let the dividend be x and the divisor y

x=3+8*y

4x+4y+3*4=248

Now you can figure it out for yourself.

I can only calculate until the dividend plus the divisor is equal to 60 and then count. There is a decimal. This question may be that the remainder is wrong. The remainder should be 6

2. Class size: 18 3 7 18*7 3 42 (people);

Number of students in the school: 42 1 20 42*20 840 (people).

Calculate the speed of the aircraft: 6370000 2

One circumference around Jupiter's equator: 71400000 2

If the apprentice's work efficiency is x, then the master is 4x 5 (the master is slower than the apprentice??? Time is t

t*x-22=t*4x/5

You can solve it, t can be added or not, and x=112 ...... can be obtainedHope it helps.

Father: (400 20 7 + 400 80 3) 2 155 2

Meters. Son: 400 20 m min.

It takes time. Father: 400 points.

Son: 400 points.

Let the parent speed be x m min and the child speed y m min.

20/7（x+y）=400

80/3（x-y）=400

The process is calculated by itself.

The first question is x4 5=80, x=100 100*3 4=75

The second question is x5 6=90, x=108

That number is 100, and three-quarters of it is 75

Solution: (1) Let this number be x.

35%x+40=40%x

5%x=-40

x=800 is 800

2) Let this number be x.

3x+3x+

3x=x=This number is (3) Let this number be x.

40×50%-3|5x=5

20-3|5x=5

3|5x=-15

x=25 is a number of 25

4) Let this number be x.

36%x+9%x=

45%x=x=70

This number is 70

A is 90*(1-1 10)*(1+1 10)=

B is 90*(1+1 10)*(1-1 10)=

Apparently the two supermarkets end up being the same.

32 1/8 3/4 4 3/4 4 3/4