How to effectively traverse django s QuerySet

Updated on technology 2024-04-14
6 answers
  1. Anonymous users2024-02-07

    The most efficient traversal method:

    for e in :

    print(

  2. Anonymous users2024-02-06

    results = = 1) filter is a queryset and does not have a meta method.

    allhost = serverinformation.This sentence is correct vername = serverinformation._'servertype').

    Verbose Name is also true, S ervertype is a property of the model.

    vervalue = serverinformation._'serverzone').default can get the default value, in other words, you know how to get the verbose name, why don't you think of it directly.

    default.

  3. Anonymous users2024-02-05

    Don't rate your solution. Your templates are more familiar than I am. It's just that I feel like you may have taken a detour.

    Modules are just used to handle simple loops. It's not enough to do complex algorithms. That's what python does best.

    So you do a little bit of it in python. Form a structure that appears to be a list. Then, like a "printer", you can type it out sequentially directly in the template.

    The so-called MVC does not mean that all views are completed by templates, and all data logic is completed by models. In fact, in real engineering, it is more complex and multi-layered than the logic of MVC. There is no need to complicate this generalization.

    A lot of times, all-in-one.

    Everything is simply completed in the viewer, which is more readable and maintainable. This achieves the goal of software engineering.

  4. Anonymous users2024-02-04

    for k,v in dict:

    where k is the key of the dictionary and v is the value of the dictionary.

    Or for k in dict:

    v = dict[k]

    k is the key of the dictionary, and v is the value of the dictionary.

  5. Anonymous users2024-02-03

    Recursion. Use this function to recursively extract all the values in the dict into an empty list.

    def dict2flatlist(d,l):

    print(d)

    for x in :

    if type(d[x]) == dict:

    dict2flatlist(d[x],l)d = },8:"f"}

    l = dict2flatlist(d,l)print(l)

  6. Anonymous users2024-02-02

    pcr.You can get the names of all fields, and then you can use pcrGet the verbose name and getattr() to get the value

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