A few questions about the first integer, the arithmetic problem of the first integer

1.The number of times is the same x 4y 2 and x (b-1) y 4 are the same, 6 = (b-1) + 4, so b = 3

If the constant term is the opposite, then 1-a and 2b-3=3 are inverses, so 1-a=-3, a=4, a-b=1

2.Suppose the cost is x, so the list price is, **** is.

The profit is that x=25a 3 is the list price.

3.After that there are 2x 3+x 2+2x+1=ax 3+bx 2+cx+d, so a=2, b=1, c=2, d=1

a+b+c+d=6

1. The order of the polynomial is 6, so the second b-1+4=6, so b=3;2b-3=1-a, so a=-2, so a-b=-5;

2. The cost price is set to x, the selling price is x (1+40%) 80%, and the profit = selling price - cost price, that is, x (1+40%) 80%-x=a, so the available cost price x=a 12%;

3、（1+x^2）(1+2x)=1+2x+x^2+2x^3=2x^3+x^2+2x+1=ax^3+bx^2+cx+d

So a=2, b=1, c=2, d=1, so a+b+c+d=6, b=1

4m^2+8mn+4n^2

Let the odd number be n, so n*(n+2)+1

Let n+1=a

So (a+1)*(a-1)+1

Perfect squared difference formula.

a^2-1+1=a^2

Because n is an odd number.

So n-1 is an even number.

Question 1: The number of female students is (x*48%) and the number of male students is (x*(1-48%)

Question 2: The average speed of this coach is ( s 3 ).

Question 3: Reach (m*(1+10%)) kilograms.

Question 4: To be paid (15*p*yuan.)

(1) Son's height: (a+b) 2

Daughter's height: (

2) Xiaohong's height: (m.

Xiaoliang's height: (m.

(1) The son's height is.

The daughter is tall.

2) Little Red's height is about equal to meters.

Xiaoliang is meters tall.

(1) Son: A+B 2

Daughter: (2) Xiaohong: (

Xiaoliang: (

It should be (a+c)-(b-d).

a+c）-（b-d）

a+c-b+d

a-b)+(c+d)

Choosing D opens the brackets, and then after some processing (merging similar terms, general points, factorization, etc.), it should be possible to simplify the factors related to the known conditions, and then it can be calculated.

Did you make a mistake? Probably (a+c)-(b-d).

Remove the brackets and put them back together.

a-b）+(c+d)=-1

If the question is correct, then there is an error in the option.

（a+c）-(a-d)

a+c-a+d

c+d, so there is no right one in the options.

The answer is 2(a+c)-(a-d) can be reduced to, that is, without parentheses: a+c-a+d

A and -a are inverse numbers to each other, so 0 is left, then c+d. remainsAccording to the title, c+d is equal to 2, so (a+c)-(a-d) is equal to 2

Integer is a general term for polynomials and monomials Multiplication and division of integers is mainly multiplication and division of polynomials Here are some exercises for integer calculations, I hope it will help you learn! 1 Calculation: (1)(a- 2b+c)(a+2b-c)-(a+2b+c)2; (2)(x+y)4(x-y)4；(3)(a+b+c)(a2+b2+c2-ab-ac-bc) 2 Simplify:

1)(2x-y+z-2c+m)(m+y-2x-2c-z)； 2)(a+3b)(a2-3ab+9b2)-(a-3b)(a2+3ab+9b2)；3)(x+y)2(y+z-x)(z+x-y)+(x-y)2(x+y+z) (x+y-z) 3 Known z2=x2+y2, simplify(x+y+z)(x-y+z)(-x+y+z)(x+y-z) 4 Let f(x)=2x3+3x2-x+2, and find the quotient and the remainder formula obtained by dividing f(x) by x2-2x+3

The nth is (-1) to the (n+1) power and x (n+1) to the power of the (n+1).

That is, the nth is the (n+1) power of the Quiet Frontier (-x).

The n+1 is (-x) to the (n+2) power.