There are 38 chickens and ducks, 4 chickens in a group, 3 ducks in a group of 11 groups, and how man

There are x groups for chickens and y groups for ducks.

x+y=11

4x+3y=38

The solution is x=5 and y=6

So there are 5 groups of chickens and 6 groups of ducks.

Suppose that these 11 groups are all chickens, then there are 4 chickens in total 11 = 44, which is 44-38 = 6 more than the actual number. This is because there are ducks in 11 groups.

There are 4-3 = 1 more chickens per group than ducks per group, so ducks have: 6 1 = 6 groups.

Chickens have: 11-6 = 5 groups.

4 5 = 20 (only) 24 chickens, 3 6 = 18 (only) 18 ducks, A: 5 groups of chickens and 6 groups of ducks.

If there are x groups of chickens, then there are 11-x groups of ducks.

4x+3（11-x）=38

4 chickens + 3 ducks = 38

Chicken + Duck = 11

Chicken = 5 groups. Duck = 6 groups.

5 groups of chickens and 6 groups of ducks.

Train a system of equations, let the chicken be a and the duck be b.

a+b=38

a/4+b/3=11

Solution a+b=38

3a+4b=132

b=18a=20

20 chickens, 20 4 = 5 groups; 18 ducks, 18 3 = 6 groups.

Assuming that all 11 groups are ducks, then it should be 11 3 = 33, which is 38-33 = 5 less than the actual number, so there are 5 groups of ducks and 6 groups of chickens.

Number of chickens.

105 pcs. Number of ducks.

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Number of ducks = (178-32) 2 = 73

Number of chickens = 73 + 32 = 105

Check, chicken plus duck = 73 + 105 = 178

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There are 360 chickens and ducks, and there are 1 4 more chickens than ducks, how many chickens and ducks are there?

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Let's have x ducks.

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A circle, the circumference is, what is its area?

The circumference, the area, I sent you together.

2 Radius Radius 4cm

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There are 360 chickens and ducks, and there are 1 4 more chickens than ducks, how many chickens and ducks are there?

Don't you need to solve with equations?

That's right. Uh-huh.

Chickens, 360 (1+1+1 4) 160 chickens.

Correction: Ducks, 360 (1+1+1 4) 160 ducks.

Chickens, 160 (1+1 4) 200 chickens.

This problem is very simple and easy to understand using equations.

Solution: There are x chickens.

If there are two less ducks than three times that of chickens, then there are 3x-2 ducks.

x+3x-2=34

4x=36x=9

34-9=25.

A: There are 9 chickens and 25 ducks.

(34+2) (1+3) according to the proposition

Problem solving ideas: The key words in the application problem are average, division is generally used, multiplication is generally used, and addition and subtraction are generally used for who is more or less than whom, and columnar formulas are applied according to the keywords. Problem solving process:

A: There are 9 chickens and 25 ducks.

Extended data $: Vertical calculation - the result of the calculation will be the dividend from the high digit of the number of each digit divisor, each calculation of the quotient retained, the remainder plus the next digit for the calculation, in this order will be the divisor so the number of digits is calculated, the obtained quotient is combined in order, the remainder is the result of the last operation.

Problem solving process: Step 1: 36 4=9 The remainder is: 0 According to the above calculation steps, the combined result is 9

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Solution: Suppose there are x chickens.

According to the question column, the formula is.

3x-2+x=34

4x=34+2=36

x=36/4=9

The answer is 9 chickens and 25 ducks.

Suppose the number of chickens is x, the ducks are 3x-2, +3 -2=34, 4x=36, x=9, 3x9-2=25, so the number of chickens is 9 and the ducks are 25.

5 contain 1 chicken.

There are 4 ducks on the back of the chicken.

There should be 4 ducks in the back.

A14 - (9 + 1) = 4 only.

There are a total of 14-1=13 ducks, and there are 9 ducks in front, and 13-9 equals the back.