Math vegetable problems, math problemsMom bought a lot of vegetables and fruits and had to ask two m

1) Option 1: 4x

Plan 2: 16000+

2）4x=16000+

Get: x=10000

So: when there are more than 10,000, choose option 2.

When there are less than 10,000, choose option 1.

When it is equal to 10,000, it is acceptable.

1. Solution: (1) Customized purchase of carton from the carton factory:

Y1 = 4x cost of processing cartons by the vegetable processing plant itself:

y2=16000+

2）y2-y1=

When y2=y1, we get x=10000

When x 10000, y2 y1

When x 10000, y2 y1

So when x 10000, y2 y1

Choose option one, the cost of buying cartons from carton factory custom is low when x 10000, y2 y1

Option two, the cost of processing cartons by the vegetable processing plant itself is low at that time x = 10,000

Both plans are available, and the cost of both plans is the same.

Cost of option 1: y1=4x

Cost of option 2: y2 = 16,000 +

Compare the two: when y1y2

i.e. x>10000

Option 2 is chosen.

1) Question 1: How much does 5 kg of beef cost?

meta); Answer: 5 kg of beef is 93 yuan

2) Question 2: How much does 10 kg of cabbage and 3 kg of eggs cost? ,42 (yuan);

A: A total of $42 is required

There are three kinds of vegetables, namely an acre of radish, an acre of cabbage, and an acre of sweet potatoes.

The above is a joke, hehe, three kinds of vegetables, a total of 20 square meters, radish accounts for 1 5, cabbage accounts for 2 5, ask how many square meters of sweet potato, the answer is 8 square meters.

You don't need to look at it below.

Manifestations of good study habits:

Cantonese version: Have a goal, have a plan;

Ability to concentrate and eliminate distractions;

Do not rely on others and complete learning tasks independently;

Love to use your brain, love to observe, love to ask questions;

Have a learning method that suits you;

Frequent use of reference books and reference books;

Like to read, appropriate Internet access, broaden knowledge; Discuss issues frequently with classmates;

Today's business, today's end.

Cultivating Good Study Habits (Cantonese Edition): The cultivation of good study habits begins with the formulation of a concrete, clear and feasible plan.

Textbook: The Habit of Single-minded Learning;

study habits of concentration;

regular and quantitative study habits;

study habits of serious thinking;

the habit of completing homework independently;

Pay attention to the habits of learning hygiene;

Diligent and persistent study habits.

Study Habits for Success (Textbook): While it is important to set learning goals and make a study plan, it is even more important to execute the plan. In the process of executing the plan, the most important thing is to develop good study habits.

Sujiao version: Have a scientific and reasonable plan, and be able to persevere.

Learning is self-motivated, without the need for parents or teachers to supervise.

Have a regular schedule and rest, get up early and go to bed early, and don't fight fatigue.

Complete your homework on time and without procrastination.

Adopt the five-stage learning method: preview, listening, reviewing, homework, and summarizing.

Solution: (1) Set up x cars to transport A kinds of vegetables, and Y cars to transport B kinds of vegetables.

40-x-y) cars transporting B vegetables.

4x+5y+6(40-x-y)=200,y=-2x+40,40-x-y=40-x-(-2x+40)=x,The number of vehicles transporting each vegetable is not less than 10,x 10,-2x+40 10,10 x 15

X can be taken, and there are six types of vehicle arrangement:

1. A: 10 cars, B: 20 cars, C: 10 cars.

2. A: 11 vehicles, B: 18 vehicles, C: 11 vehicles.

3. A: 12 vehicles, B: 16 vehicles, C: 12 vehicles.

4. A: 13 vehicles, B: 14 vehicles, C: 13 vehicles.

5. A: 14 vehicles, B: 12 vehicles, C: 14 vehicles.

6. A: 15 vehicles, B: 10 vehicles, C: 15 vehicles.

2) 250,000 yuan = 2,500 hundred yuan.

W[Profit]=4x 16+5y10+6(40-x-y) 1236x+2000,36x+2000 2500, x13(8 8)by (1)10 x 15, x can take 14 or 15So, if you want to make the profit from this sale reach the expected profit of 250,000 yuan, which plan five or six should be taken.

Solution: (1) Let the vehicles of A, B, and C vegetables be X, Y, and Z respectively, then X+Y+Z=40 .

and 4x+5y+6z=200 .

and x 10, y 10, z 10

From , we get x=z,y=40-2z ③

40-2z 10, i.e. z 15

10≤z≤15

When z=10, x=10, y=20, when z=x=11, y=18, when z=x=12, y=16

When z=x=13, y=14

When z=x=14, y=12

When z=15, x=15, y=10

2) 64x+50y+72z≥2500 ..

By substituting , 64z+50(40-2z)+72*z2500 solves z 125 9=

A 14, B 12, C 14, profit of 2504 (100 yuan) = 10,000 yuan) A 15, B10, C15, profit of 2540 (100 yuan) = 10,000 yuan).This is the most profitable and the best.

Solution: It can be set that transport A has x cars, transport B has Y cars, then transport C has (40-x-y) cars, 1) from the title, you can get: x 10

y≧1040-x-y≧10

4x+5y+6*(40-x-y)=200

So, we get: 2x+y=40, and we have: x 10, y 10, x + y 30

So, there are the following schemes: A: 10, B20, C10 A: 13, B14, C13

a :11,b18,c11 a :14,b12,c14

a :12,b16,c12 a :15,b10,c15

2) The expected profit is: 64x+50y+72*(40-x-y).

From the title, it gets: 64x+50y+72*(40-x-y) 2500

From the condition 2x+y=40, we get: y=40-2x, and substitute y=40-2x into the inequality, we get: 64x+50*(40-2x)+72*x 2500

Solution: x 125 9 (125 9 is approximately equal to 13....

Therefore, there are 2 options that can be taken: A: 14, B12, C14 or A: 15, B10, C15

1) Let the number of cars allocated to the three vegetables of ABC be X1, X2, X3Then there are the following:

4*x1 + 5*x2 + 6*x3 = 200x1+x2+x3=40

x1, x2, x3> = 10 and x1, x2, x3 are integers.

There are 6 solutions that can be solved:

10+i,20-2*i,10+i) i=0,1,2,3,4,52) Let the number of cars allocated to the three vegetables of ABC be x1, x2, x3Then there are the following:

Objective function: 16 x 1 + 10 x 2 + 12 x 3 = 25004 x 1 + 5 x 2 + 6 x 3 = 200 x 1 + x 2 + x3 = 40

x1, x2, x3 are integers.

Isn't 25w too much. This is unsolvable.

It's a bit complicated Ask your math teacher.

11、x≥1

c(x,2)=45 This is a permutation-combination problem where x is below and 2 is above.

Or the graph at 75° is not visible.

>=1 (the formula under the root number should be greater than or equal to 0).

degrees (angles b and d are equal, a and c are equal, so 6*b = 360 degrees) can be brought into the solution).

is a quarter of a large triangle).

Let last year be x, then the growth rate of the two years should be equal, and then solve), solve x=10

degrees (180-150 and then divided by 2).

The next two questions are not clear

If the width of the canal is x meters, then 100 by 50 - [2 by 100 + 2 by (50-2x)]x=4600