Can you explain a few sentences in braces around this vb question? Thank you

option explicit

private sub form_click()

dim s as string, i as integer, flag as boolean

s = "this is a book."

s = lcase(s)

print s

flag = true

for i = 1 to len(s) 'Start the loop, the number of loops is the length of s.

if mid(s, i, 1) = " " then 'If 1 character in position ith in the s string is a space.

flag = true 'Set the mark as true.

elseif flag then 'Otherwise (if the character in that i position is not a space) and the b tag is true.

Change the s string to take the i-1 character on the left side of the s, plus the uppercase letter of the judgment character, plus the character of length -1 on the right (that is, the character becomes uppercase, and the other characters remain unchanged).

flag = false 'The tag is set to false.

end if

next i}

print s

end sub

What it does is convert words in a string to the first letter.

The ** in curly braces, its working idea is:

Loop through each character, and if it's a space, set the flag to true.

This tag is used to indicate whether the last processed character was a space or not. If the previous character is a space, the currently processed character is capitalized, and the flag is false.

One of the problems with this paragraph is that if you encounter an even number of spaces in a row, you can't convert the subsequent word to the first word uppercase.

The answer you gave yourself is a) 21

Master 2 key points:

1. The rules of operation of the operator symbol.

2,for i = 1 to 20 step 2 The rule of this cycle.

The solution is as follows: 1. The operation rules of the operator symbol.

The notation is to calculate the quotient within the range of integers for two integers, regardless of remainders, e.g

When I first started learning division in elementary school, I had not yet been exposed to decimals and fractions, so the teacher explained that the quotient remainder.

Then in the VB there is:

Special note: 2, for i = 1 to 20 step 2 The rule of this cycle.

Usually i is called the loop control variable, 1 is called the initial value of the cycle, 20 is called the end of the cycle, and 2 is called the step size.

For loops with positive step sizes, the loop termination value is based on the value of the loop variable > (note: if the step size is negative, then the loop termination value is based on the value of the loop variable < loop termination) is the condition for terminating the loop.

1st: i = 1;x=x+i\5 --x = 5 + 1 \ 5 --x = 5

2nd: i = 3;x=x+i\5 --x = 5 + 3 \ 5 --x = 5

3rd: i = 5;x=x+i\5 --x = 5 + 5 \ 5 --x = 6

4th: i = 7;x=x+i\5 --x = 6 + 7 \ 5 --x = 7

5th: i = 9;x=x+i\5 --x = 7 + 9 \ 5 --x = 8

6th: i = 11;x=x+i\5 --x = 8 + 11 \ 5 --x = 10

7th: i = 13;x=x+i\5 --x =10 +13 \ 5 --x = 12

8th: i = 15;x=x+i\5 --x =12 +15 \ 5 --x = 15

9th: i = 17;x=x+i\5 --x =15 +17 \ 5 --x = 18

10th: i = 19;x=x+i\5 --x =18 +19 \ 5 --x = 21

11th: i = 21, at this time i > 20, so the loop is not executed, the second is the end of the loop.

So the value of x is 21