Is there a formula for how to calculate humidification 20

w= *(v1*v2)*(x1-x2)*c represents the density of air.

v1 represents the volume of dehumidification space.

v2 represents the volume of fresh air.

x1 represents the moisture content of the air before dehumidification (dry air at a humidity of 95% rh and a temperature of 18).

x2 represents the moisture content of the air after dehumidification (dry air at a humidity of 70% RH and a temperature of 18).

The computer room is calculated according to 20g per cubic meter, such as 200 square meters, the floor height is 5 meters, the closure is good, the temperature is 20 degrees, and a humidifier with a humidification capacity of 20 kg is required;

The workshop is calculated according to 15g per cubic meter, such as 200 square meters, 5 meters high, good closure, temperature 20 degrees, and a humidifier with a humidification capacity of 15 kg;

The office is calculated according to 8g per cubic meter, such as 200 square meters, 5 meters high, good closure, and a temperature of 20 degrees, which requires a humidifier with a humidification capacity of 8 kg;

The archive warehouse is calculated according to 6g per cubic meter, such as 200 square meters, the floor height is 5 meters, the closure is good, the temperature is 20 degrees, and a humidifier with a humidification capacity of 6 kg is required.

Humidification capacity calculation:

According to the design specification, if the indoor humidity is not considered, the fresh air and indoor air humidity exchange in winter can be the main parameters.

Assume that the air parameters are calculated indoors and outdoors in winter: dry bulb temperature -20 degrees Relative humidity: 70%.

Interior design air parameters: dry bulb temperature 20 degrees Relative humidity: 50%.

The design code provides a formula for calculating humidification capacity:

w = fresh air volume * air density * (indoor air humidity content - outdoor air humidity content) * safety factor humidification mass flow.

kg/h=(m^3/h)*(kg/m^3)*(kg/kg-kg/kg)

According to the data, the recommended steam flow rate value is 30m s---60m s

According to the calculation formula:

Flow rate = mass flow rate * steam density = *r 2 * vm 3 h = (kg h) (kg m 3) = m 2 * (m h) steam density can be found by the steam diameter calculation software in the software folder.

The pipe diameter can be calculated.

w=ρ*v1*v2）*(x1-x2)*c

Represents air density.

v1 represents the volume of dehumidification space.

v2 represents the volume of fresh air.

x1 represents the moisture content of the air before dehumidification (the moisture content of the air at a humidity of 95% RH temperature of 18 is dry air).

x2 represents the moisture content of the air after dehumidification (dry air at a humidity of 70% RH and a temperature of 18).

Summary. Relative humidity refers to the ratio of water dissolved per unit volume of air to the maximum amount of water dissolved, expressed in rh%, such as %, etc. Typically, temperature is inversely proportional to relative humidity.

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w= *v1*v2)*(x1-x2)*c represents the air density of the wheel ruler, v1 represents the dehumidification space, and v2 represents the volume of fresh air.

X1 generation of the first table to do the air moisture content before the number of humidity (at the humidity of 95% RH temperature 18 air content of the air moisture content of dry air) X2 represents the dehumidification of the air moisture content (at the humidity of 70% RH temperature 18 of the air Hulun water content table obtained dry air).

Relative humidity refers to the ratio of water dissolved to cavitated per unit volume of air to the maximum dissolved water. Typically, temperature is inversely proportional to relative humidity.

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What I want to ask is why 1000 and not 1000

It would have been 1000

Between g h and kg h is 1000 bars. No.

Can you show me your derivation process?

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The derivation process of the humidification capacity formula.

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The moisture content is calculated as d=622 ps (p ps), where:

P is the air pressure (Pa), ps is the water vapor partial pressure (Pa), and the relative humidity (%)

This formula can be used to calculate the moisture content of the air, i.e. the mass (grams) of water vapor mixed in dry air in kilograms of weight per hand.

Selection example: The air volume of the fresh air air-conditioning unit in a workshop is Q=10000m3 h, the air state of the humidifier inlet is t=30, 10 rh, the air shape of the humidifier outlet is t2=, 50 rh, the cross-sectional wind speed is, the effective width of the surface cooler through the surface is 1200mm, and the effective height is 917mm.

1. Effective humidification capacity.

w= 2, the required wet film standard humidification capacity.

Wind speed ratio through the wet film =

l= = Therefore: the thickness of the wet film material to meet the needs is 200mm