Four questions, please, these four questions, please.

1) According to the inscription, the elder brother has 6 more books than the younger brother, and if the younger brother is x book, then the elder brother is x+6 books, x+6+1=3· (x-1)

Solution: x=5

So, it turns out that the elder brother has 11 books and the younger brother has 5 copies.

2) If the pony is x years old, then the Malaysian is 4x years old, 4x+20=2(x+20)-14

Solve x=3

Therefore, Malaysia and pony are now 12 and 3 years old respectively.

3) If the admission score is X, the average score of the admitted candidates will be X+;

The total score of 1000 students is 55 1000, of which 150 (x+6) are accepted and the total score is not admitted.

55×1000-150(x+6)

The average score of non-admitted students is [55, 1000-150 (x+6)], 1000-150).

From the proposition, x+, we get x=81

That is, the cut-off score for admission is 81 points.

4) Let C x kg, then A is x+2 kg, and (A + B) 2=x+3, so B's weight is 2(x+3)-(x+2)=x+4, x+(x+2)+(x+4)=63 3

Solution x=61

So, B weighs 65 kilograms.

1 (3 2 + 1 2) (3-1) + 1 = 5 (Ben) (Brother) 5 3 2 = 11 (Ben).

Brother) 2 solution: If the pony is now x years old, then the Malaysia is 4x years old 4x+20=2(x+20)-14x=3

Pony) 4x=12 (Malaysia).

3 1000-150 = 850 (person) (55 1000 + 38 850) points).

4 A + B is more than 2 C 3 2 = 6 (kg) B is 6-2 = 4 (kg) than C (63

3-4-2) 3+4=65 (kg).

This is the conclusion I have come to after meditating on it, and if it can help you, I hope you will give me one (satisfaction).

If you can't ask, I'll do my best to help you out

It is not easy to answer the question, if you are dissatisfied, please understand

Set brother X, brother Y.

Column: x-3=y+3

x+1=3(y-1)

The solution is x=11 y=5

Set up big horse x, small pony y.

Column: x=4y

x+20=2(y+20)-14

The solution is x=12 y=3

3.The average grade point of those who are admitted is X, and the average score of those who are not admitted is Y.

Column: x-y=38

150x+850y=1000*55

The solution is x= y=

Therefore, the cut-off score for admission is:

4.Let A x, B y, and C z.

Column: x+y+z=63*3

x+y=2（z+3）

x-2=z gives x=63 y=65 z=61, so B's weight is 65kg

The elder brother has an exercise book x book, and the younger brother has an exercise book y book. The columnable equation x-3=y+3 x+1=3(y-1) is solved to give y=5 x=11

Let the current age of the pony be x, then the current age of the horse is 4x, and the equation 4x+20=(x+20)*2-14 is solved to x=8

If the cut-off score for admission is X, the average score of the admitted students is X+, and the average score of those who are not admitted is X+

Then the equation can be 55*1000=(x+ solution x=81 points.

Let C's weight be x, then A's weight is x+2, and B's weight 2(x+3)-(x+2)=x+4 has an equation.

x+x+2+x+4=3*63 x=61 B's weight is 65

1) If the elder brother gives the younger brother 3 books, the two of them will have the same number of exercise books, so it turns out that the elder brother has 3 2 = 6 more than the younger brother.

After the brother gave the brother 1 book, now the brother has 6 + 1 + 1 = 8 copies more than the brother The difference is the problem.

8 (3-1)=4 books 4 3=12 books Now brother 12-1=11 books Original brother.

11-6=5 Ben original younger brother.

2) In another 20 years, Malaysia will be 14 years younger than twice the age of the pony.

Then Malaysia's age in 20 years is more than twice the age of the pony now: 20 2-14 = 26 years.

So Malaysia is now more than twice as old as a pony: 26-20=6 years old.

Then the pony's current age: 6 (4-2)=3 years old.

Malaysia: 3 4 = 12 years old.

3) The average score of the admitted students is x, and the average score of the unadmitted students is x-38150x+(1000-150)(x-38)=1000*551000x=87300

x = less than the average grade.

4) C = 63-3 2 3 = 61 kg;

A = 61 + 2 = 63 kg;

B = 63 + 63-61 = 65 kg;

1.The elder brother is X, and the younger brother is YIf the elder brother gives the younger brother 3 books, the two of them will have the same number of exercise books:

x-3=y+3.If the younger brother gives the elder brother 1 book, the elder brother's exercise book is 3 times that of the younger brother: 3x(y-1)=x+, x=11

2.The age of the pony is x, and the age of the horse is 4x 2x(x+20)-14=4x+20,x=3

The first course is 9x=18, the stool is clear and the land is x=2 the second jujube land road is -x=-3, x=3 the third way, y=-1 the fourth road 5 6b=3, b=18 5