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No, you first have to understand what an equation is, and there is a solution to a one-dimensional equation.
A quadratic equation may have two solutions, one solution, or no solution, and the general formula for a quadratic equation is ax 2+bx+c=0
When b 2-4ac>0 there are two solutions.
There is a solution when b 2-4ac=0.
There is no solution when b 2-4ac < 0.
There will be no three solutions to a three-dimensional equation.
For example, 3x 3-24=0
The solution is x=2, so you have to understand the meaning of the equation of several elements.
A few elements refers to the number of last known numbers in the equation, and several times refers to one of the highest degrees in the equation.
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Theoretically, this is true, provided that it is within the municipal and boundary. Because any unary nth order equation can be formed into the product of n primary polynomials, but the coefficients of each polynomial may be different.
Therefore, if n polynomials are equal to zero, then any one polynomial is equal to zero, then both sides of the equation are true.
So, there are n solutions. The difference is that if the equation is missing, it may be missing. For example, x3+1=0
then there is only one root with x=-1.
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The landlord was right.
Solution of a unary nth order solution Real number solution + imaginary number solution = n
The third and fourth floors mentioned that there are several identical solutions or that there are no imaginary solutions, which my teacher talked about when I was in middle school.
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Yes, there are equal solutions.
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No, it is possible that there are 7 solutions to a quadratic equation.
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Theoretically, a quadratic equation can be divided into two factors.
For example, in the equation x2-5x+6=0, the left part of the feast can be multiplied by (x-3)(x-2)=0
For the product to be zero, either of the two inconsecutory silvers must be zero, so if x-3=0 or x-2=0, the product is also zero.
This gives you two solutions.
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Summary. To solve the quadratic equation of the 2 3rd power, the first thing to make clear is that the quadratic equation of the 2 3rd power means that the quadratic term in a quadratic equation has an exponent of 2 3, that is, x (2 3). Reason:
2 A quadratic equation to the power of 3 is a special quadratic equation that is solved differently from a quadratic equation in general because the exponent of its quadratic term is not an integer, but a fraction. Solution: To solve the quadratic equation of 2 3 power, we must first convert it into a general quadratic equation, that is, x (2 3) into the form of x 2, so that it can be solved using the solution of the general quadratic equation.
Personal tip: When solving a quadratic equation of the 2nd and 3rd power, you should first convert it into a general quadratic equation, and then use the solution of the general quadratic equation to solve it.
How to solve a quadratic equation to the power of 2 3.
Solution: The general form of the quadratic equation is ax +bx+c=0, let a=2 3, b and c be arbitrary real numbers, then the quadratic equation can be written as:
2 3)x +bx+c=0 solution: x=[-b (b -4ac)] 2a) i.e.: x=[-b (b siji-4(2 3)c)] 4 3).
Can you elaborate on that a little bit more?
To solve the quadratic equation of the 2 3rd power, the first thing to make clear is that the quadratic equation of the 2 3rd power means that the quadratic term in a quadratic equation has an exponent of 2 3, that is, x (2 3). Reason: The quadratic equation of 2 to the third power is a special quadratic equation, and its solution is different from the general quadratic equation because the exponent of its quadratic term is not an integer, but a fraction.
Solution: To solve the quadratic equation of 2 3 power, first of all, it should be converted into the general quadratic high-purity range, that is, x (2 3) into the shape of x 2, so that the solution of the general quadratic equation can be used. Personal Tips:
When solving a quadratic equation of the 2 and 3rd power, it is necessary to first convert it into a general quadratic equation, and then use the solution method of the general quadratic equation to solve it.
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The same is to solve the equation first, but the coefficients of this problem cannot be rationally assigned to the solution of Qinchen, and can only be solved by applying the formula: sell guess.
x1=x2=
x3 = Thus according to the "threading method" the solution set is: (x1, +u (x3, x2).
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Summary. In general, higher order equations should find special relations, such as the commutation method. to play the role of downgrading.
Dear, hello, I'm glad to help you learn, what you said about this kind of love beam rolling situation is called the high-order equation high-order equation of the square slag group method first to think of the descending of course, in the case of a reed orange, the high-speed equation must have a certain special structure, so this should be judged according to the actual topic
In general, higher order equations should find special relations, such as the commutation method. to play the role of downgrading.
How to solve this kind of problem, use the method of junior high school.
Dear, please be patient for a while and I'll take a look at your actual topic.
First of all, the square 324 x yard spring + x 36 equation is multiplied by x 324 + x 4 36x at the same time, and this delay becomes a quadratic equation.
x^4-36x²+324=0(x²-18)²=0x²=18x=±3√2
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Summary. Hello, there are only quadratic and quadratic solutions in the equation: you can use the relationship between 4 and 2 to transform the quadratic into the second and the quadratic into once, so that you can get a quadratic equation, and then continue to solve it according to the quadratic equation.
Hello, there are only four and quadratic solutions in the equation: you can use the relationship between 4 and 2 to transform the quadratic into two stabs, and the quadratic into one, so that you can close the accompaniment to get a quadratic equation Tongyu, and then continue to solve the car wheel stupid according to the quadratic equation.
In that case, can you understand?
If you don't understand, tell me**I don't understand?
How to solve this problem.
Hello dear this solution: after replacing him with an ordinary one-dimensional quadratic equation, according to the one-dimensional quadratic equation to find the solution, you can file the group to get the explanation he obtained, equal to 18 and because of her quadratic way 18, so his final solution is equal to plus or minus three times the root number two Because there is a limit to the calculation of the fiber, the specific calculation is shown in the figure.
Is it understandable? Tell me if you don't understand.
Is there any other solution?
The x-square is equal to y, which is a bit difficult to understand.
Hello dear, there are other solutions, but what grade are you in?
If you are a university student, we can learn other solutions, and if you are currently a junior high or high school student, this method is the most suitable for you to understand.
I suggest that you write it yourself by referring to my problem-solving process.
And then to understand it ourselves, this situation requires us to think about it, not to understand it at a glance.
This belongs to the development of brain power.
Junior high school. We haven't learned that.
Hello dear, you haven't learned it, it's just a flexible use of thinking.
In fact, it is within the scope of your learning.
You haven't learned this method, but you can think about it, and this method is actually the same as solving a quadratic equation that you learned.
It's just one more hypothesis.
If you have any other questions about this issue, you can choose to upgrade the above services, and you can consult me as many times as you like.
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Yes, there must be.
But it doesn't have to be a real solution.
If it is in the real range, it should be a maximum of two solutions, or one or none.
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In the complex range it is. In the range of real numbers, it is not necessarily , two solutions of the same real number are one.
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For the unary quadratic equation ax +bx+c=0(a≠0), when the discriminant formula =b -4ac>0 there are two solutions to the equation and =b -4ac=0 there is one solution to the equation.
b -4ac<0 has no solution.
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