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typedef struct yidingkehu
else p=p->next;
while(m!=0);
if(m==0)
doelse p=p->next;
while(m!=0);
if(m==0)
If you find it, come and give him a refund.
doif((p->yupiao)>=(>next2->yudingpiao))
h2=(struct yidingkehu*)malloc(sizeof(yidingkehu));
strcpy(h2->name,>next2->name);
h2->dingpiaoshu=>next2->yudingpiao;
n=p->>next2->yudingpiao;
p->yupiao=n;
q3=>next2;//
next2=q3->next2;These two statements are used to delete the node.
if( ;free(q3);Free up space.
printf("The deletion in the chain team is successful");
h2->next1=h->next1;
h->next1=h2;to insert it into the linked list of customers who have booked a ticket.
printf("The booking for the customer who made the reservation was successful");
else printf("There are not enough tickets left to book tickets for pre-booked customers! ");
else If it is not found, that is, there is no information about the person in the system, and it prompts whether to find it again.
printf("Sorry, there is no one booking for this flight or you have not booked a ticket for this flight");
printf("Do you want to find and cancel your booking again? ");
printf("If required, please enter 1, otherwise press 2");
scanf("%d",&m);
printf("");
while(m==1);
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My program is big, and I will contact you when you want it.
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From the meaning of the title, it can be seen that a+b+c=19x3=57
c+d+e=25x3=75
The above two formulas are added to obtain a+b+c+c+d+e=57+75=132, and from the third condition, we can know that a+b+c+d+e=21x5=105, so c=132-105=27, upstairs should also be like this.
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Formula 1: a+b+c=19*3
Formula 2: c+d+e=25*3
Formula 3: a+b+c+d+e=21*3
Formula 4: = Formula 3 minus Formula 1: d + e = 21 * 3-19 * 3 Formula 2 minus formula 4: C = 25 * 3-21 * 3-19 * 3 = 27
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(1) Because, AD BC
So, CAD ACB (Equal Inside Wrong Angles).
Again, acd b
So, ABC DCA
then, bc:ac ac:ad
i.e., AC2BC AD6212
Solution, AC 2 3
2) Because, ABC DCA
Then, the similarity ratio bc:ac 6:2 3 3:1 because, the ratio of the area of the similar triangle is the square of the similarity ratio.
So, s acd:s abc 1:3
Because, s quadrilateral abcd s abc s acd, s acd:s quadrilateral abcd 1:(3 1) 1:4 so, s acd s quadrilateral abcd 1 4
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(1) f(x)=5x(15 x 40)g(x)=90(15 x 30) =2x+30(30 x 40)(2) so that 5x 90 solves x 16, so when the activity time is 15 x 16, when the activity time of house A is worth 16, and when the activity time of two families is the same x 16, it is cost-effective at house B.
If you agree with my answer, please click the [Accept as satisfactory answer] button in time Friends who ask questions on the mobile phone can comment on [Satisfied] in the upper right corner of the client. Your adoption is what keeps me going
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If you take a look at the chips and solutions of TI and NS, they are generally used in the application articles of related chips, which should be very mature by now, and it should not be difficult to use the method of integrating chips.