Elementary School Math Problem Solving Chickens and rabbits have a total of 206 legs, and rabbits ha

Let's have x rabbits. The number of chickens is x+52.

4x+（x+52）*2=206

4x+2x+104=206

6x=102

x = 17 rabbits and 69 chickens.

Set x chickens. 2x+(x-52)*4=206

x+(x-52)*2=103

x+2x-104=103

3x=207

x = 69 rabbits: 69-52 = 17 (only).

A: There are 69 chickens and 17 rabbits.

If there are x chickens, then there are (x-52) rabbits.

The equation is 2x+4(x-52)=206

Solution: 2x+4x-208-206=0

6x-414=0

x=69, so x-52=17

So, there are 17 rabbits and 69 chickens.

206-52 2) 3 2=17 (only).

Total number of legs - the number of legs that chickens have more than rabbits (at this point the number of chickens and rabbits is equal) and then 3 = to get the number of chicken legs.

2 = number of chickens = number of rabbits.

17 + 52 = 69 (only).

Rabbit (or chicken) + number of chickens more than rabbit = number of chickens.

A: There are 69 chickens and 17 rabbits.

Summary. Chickens have 12 more legs than rabbits, which can be understood as chickens 12 2 = 6 more than 2 times as many rabbits, a total of 96 chickens and rabbits, with 96-6 = 90, it can be understood that chickens are eliminated, 3 times more rabbits 90, so rabbits 90 3 = 30, chickens 96-30 = 66.

There are 96 chickens and rabbits, and the chickens have 12 more legs than the rabbits.

Chickens have 12 more legs than rabbits, it can be understood that there are 12 2 = 6 more chickens than 2 times the rabbit filial piety, a total of 96 chickens and rabbits, with 96-6 = 90, it can be understood that the chickens have been eliminated, 3 times the rabbit 90 Dan is empty, so the rabbit 90 3 = 30, the chicken 96-30 = 66.

Can you add, I don't quite understand it.

This question starts with 2 legs of chickens and 4 legs of rabbits, and chickens have 12 more legs than the rabbits in the lead row, which can be understood as 12 2 = 6 chickens than 2 times more rabbits. If you use the solution system of equations to understand the meaning of the problem.

If there are x chickens, then there are (200-x) rabbits.

2x=4（200-x）-56

x=124 then the chicken has 124

Rabbit: 200-124=76

Let's have Y rabbits and x chickens. So x+y=200 4y-2x=56, and finally there are 76 rabbits and 124 chickens.

Set: chicken x, rabbit (200-x).

to get a system of equations. 4（200-x）-2x=56

The solution is x=124

200-x=76

That is, 124 chickens and 76 rabbits.

I asked someone else's.

The question is one word less, and we can understand it as two questions, one: the chicken's feet are 56 fewer than the rabbit's feet. One: 56 more chickens have more feet than rabbits.

The chicken's feet were 56 fewer than the rabbit's feet. Let's first remove the 56 feet of the rabbits, 56 4 14 (only) is equal to the removal of 14 rabbits.

The question becomes: There are 200-14 = 186 rabbits with the same number of legs: 186 1 3 = 62 rabbits

The actual number of rabbits is: 62 + 14 = 76 (only).

The number of chickens is: 200-76=124 (chickens).

There are 56 more chickens than rabbits. Let's start by removing 56 chickens' feet 2=28 (only), which is equivalent to removing 28 chickens.

The question becomes: There are 200-28 = 172 rabbits with the same number of legs: 172 1 3....Except endlessly. If you don't get an integer, it's wrong. There can only be one question.

56 4 = 14 (only).

200-14=186 (only).

Rabbit: 186 (2+1)+14=76 (only).

Chickens: 200-76 = 124 (pcs).

A: There are 124 chickens and 76 rabbits.

Equation solution: Let there be x rabbits and (200-x) chickens.

4x-（200-x）x2=56

6x-400=56

6x=456

x=76200-x）=200-80=124

Hope it helps!

Let the chickens be x and the rabbits be y.

From the meaning of the question, we can get {x+y=200, 2x=4y-56, x=124, y=76

So there are 124 chickens and 76 rabbits.

(4x25 ten 20) (4 ten 2) = 20 (only) 25-20 = 5 (only) Answer: There are 20 chickens and 5 rabbits.

It is better to use a one-dimensional equation.

There are x chickens and 25-x rabbits.

2x-4(25-x)=20

2x-100+4x=20

6x=120

x=20 There are 20 chickens.

There are 25-20 = 5 rabbits.

If you don't learn, use your own way.

Set: chicken x, rabbit (200-x).

2x+56=4（200-x）

2x+56=800-4x

2x+4x=800-56

6x=744

x=124200-x=76

A: 124 chickens and 76 rabbits.

Solution: If there are x chickens, then rabbits have (200-x).

2x+56=4（200-x）

2x+56=800-4x

6x=744x=124

A: There are 124 chickens and 76 rabbits.

It can also be solved with binary once (

Analyzing the meaning of the question, it can be seen that the number of chickens with "missing" feet:

56 2 = 28 only.

Then the rabbits are: (200+28) (2+1)=76 - (the number of feet of two chickens is equal to that of one rabbit).

Chickens: 200-76 = 124 (pcs).

Therefore, there are 124 chickens and 76 rabbits.

Let the number of chickens x the number of rabbits y x+y=200, 4y-2x=56 to get x=124 y=76 You can also use the Bowel method, if the rabbit lifts two feet.

Let the chicken be x and the rabbit be y. From the question, we know that x+y=200---4y-2x=56--- there is 1 formula multiplied by 2 to get 2x+2y=400--- add 3 and 2 formulas to get 6y=456, that is, y=76.

Substituting y=76 into 1 gives x=124

Solution: Let the chicken be x and the rabbit be y The chicken has two legs, and the number of chicken's feet is 2x; The rabbit has four legs, and the number of rabbit's feet is 4y.

Column equations: x+y=45

2x-4y=24 x=34 y=11 so there are 24 chickens and 11 rabbits.

Suppose there are x chickens, then there are 45-x rabbits.

So 2x-4(45-x)=24

2x-180+4x=24

6x=204

x=3445-x=11

There are 34 chickens and 11 rabbits.

If there are x chickens, then there is 2x-4(45-x)=24

Solution x=34

So 34 chickens and 11 rabbits.

If 200 are all rabbits, rabbit feet: 200 4 = 800.

Chicken feet: 0.

Chicken feet are less than rabbit feet: 800 pieces.

Replace 1 rabbit with a chicken, and reduce the number of rabbit feet by 4.

Increase the number of chicken feet by 2.

The difference between chicken feet and rabbit feet decreases: 4 + 2 = 6 feet.

In total, it needs to be reduced: 800-56 = 744 animals.

Chickens: 744 6 = 124 Seeking to adopt — one.

Rabbits: 200-124 = 76 pcs.