5th grade math olympiad questions, the master is coming!! 100 points will be added if you answer co

1. Fill in the blanks. 1.2002 = 2*7*11*13 The answer is 33

3.The title is unclear, please describe it completely.

2. Practical questions.

1.Is it possible that there is a problem with the question, B, C, and D have an average score of 90, but the scores are not less than 90 points and are not the same as each other?

2.Let the length of the train x, the speed v. x + 1000 = 120 * v, 1000 - x = 80 * v gives v = 10, x = 200

3.Mr. Wang is x years old, and Xiao Ming is y years old. x = 3y-2, x-8 = y + 10 gives x= 28 y=10

4.The first box x, the second box y x -9=y+9 x+12=2(y-12) x=72 y=54

1. Wrong questions Each person's score is not less than 90 points, and the average score of B96 and B C D cannot be 90 points.

2. (120+80) 2=100 seconds 1000 100=10 meters seconds 120*10-1000=200 meters.

3, set Xiao Ming is x years old this year.

x+10=3x-2-8 x=10

The teacher is 28 years old.

3.I can't understand the question, but I found the correct speed, A runs 5 meters per second, B runs 3 meters per second, please check the question and add it!

Two. 1.No.

2.(120+80) 2=100 (s) 1000 100=10 meters (s) 120*10-1000=200 (m).

3.Xiao Ming is x years old this year.

x+10=3x-2-8

x=1010+8=18 (years old) 18 + 10 = 28 (years old) A: Xiao Ming is ten years old this year, and the teacher is 28 years old.

4.30 in one basket and 12 in two baskets.

5.I didn't count I'll talk about these things first, it's too late, it's past two o'clock, I'll go to bed, and I'll talk about it tomorrow.

1. Fill in the blanks.

2. Practical questions.

1. Wrong questions Each person's score is not less than 90 points, and the average score of B96 and B C D cannot be 90 points.

2. (120+80) 2=100 seconds 1000 100=10 meters seconds 120*10-1000=200 meters.

3, set Xiao Ming is x years old this year.

x+10=3x-2-8 x=10

The teacher is 28 years old.

Ah! It's good for you that the teacher asks you to do your homework, don't be irresponsible for yourself.

Do such a simple question yourself, doing the question is to improve your own ability

Carried away = 5 7 Total carried away 5 12 The first time it was carried 3 8 Then the second time it was 5 12-3 8 = 1 24 The second time it was 50 50 (1 24) = 1200.

I don't know if you have learned the equation x, ySo I don't use it, the first time I take away 3 8, then there is 1 3 8 5 8;The second time 50 is transported, and the ratio of what is taken away and what is left is 5:7, then the proportion of what is taken away and the rest are 5 12 and 7 12 of the total tonnage, respectively, because the remaining 7 12 is equal to the remaining 3 8 after the first shipment and subtract 50

Then the total proportion of 50 transported is 3 8 7 12 1 24, so the total tonnage is 50 (1 24) 1200

To sum up: the total tonnage is 1200 tons.

1200 tons.

Set up the original goods in the warehouse x tons, 3x 8 + 50) :(5x 8-50) = 5:7 to solve x = 1200

The rest accounted for seven-twelve, and the first time it was transported away, it was three-eighths, so the second time it was transported away, it was one-twenty-four, and it turned out to be 50*24=1200... Give it the best...

Suppose there is x tons of the original equation from the proposition:

3/8×x+50）/(x-3/8×x-50)=5/7

Solve the equation: x=1200.