Question 3: Add Na2CO3 dropwise to the clarified lime water

1。It shouldn't have ...... responseCO2+H2O=H2CO3 both have carbonate that should not react.

NaHCO3+HCl=NaCl+H2O+CO2 to generate CO2 106:84=Oops, do the math yourself.

Consume hydrochloric acid 2:1

A white precipitate is generated.

Ca(OH)2+2NaHCO3=Ca(HCO3)2+2NaOH has no phenomenon.

Soda ash is Na2CO3

Problem 1: There is solid precipitation, and CO2 is passed into the saturated Na2CO3 solution to form NaHCO3, which is less soluble than Na2CO3

Question 2: Na2CO3 2HCl 2NaCl H2O CO2NaHCO3 HCl NaCl H2O CO2 can be obtained: the ratio of HCl consumption is 2:

1. The generation of CO2 is 1:1 Question 3: It will produce precipitation.

na2co3 ＋ca（oh）2＝caco3＋2naoh2nahco3＋ca（oh）2＝caco3＋2na2co3

Ca2++2OH-+ 2HCO3-= CaCO3 +2H2O+CO32- [Test Analysis] Because Ca(OH)2 is a small amount, with its stoichiometric number of 1, the stoichiometric number of HCO3- to ensure that 2OH - complete reaction should be 2, that is, the stoichiometric number of NaHCO3 can determine the cavity shape as the smallest integer 2, and the chemical equation is: Ca....

After carbon dioxide is introduced into the gray water in the clarifier file, a white precipitate will be produced, which is calcium carbonate (CaCO3), and there will also be water generation, which is the formation of white stove precipitation and water mist (the phenomenon can not appear in the name of the substance Hint) Ca(OH)2 + CO2 = CaCO3 + H2O and then add a small amount of hydrochloric acid: that is, CaCO3 and hydrochloric acid (HCl) are inverse.

ca(oh)2+co2=caco3↓+h2o

The CaCO3 formed by the reaction of Ca(OH)2 and CO2 is insoluble in the water, and the mass of Ca(OH)2 is greater than that of H2O forming the ulnar cavity, so the mass of the solution decreases.

ca(oh)2+co2=caco3↓+h2o

The CaCO3 formed by the reaction of Ca(OH)2 and Qiaobo CO2 is insoluble in water, and the mass of Ca(OH)2 is greater than the mass of H2O generated. type and.

Ca(OH)2 is present in clarified lime water

It will react with CO2 and produce jujube Qingcheng.

ca（oh）2

co2=caco3↓+h2o

Because the calcium carbonate produced is a precipitate.

Mass is not counted in the solution.

The previous mass was 74 + 44 = 118

After the acre hall. The mass is just the mass of the water18

Therefore, the mass of the solution can be seen to be smaller before the stool is resistant.

Just look at the equation: Ca(OH)2+CO2=CaCO3 flutter + H2O, and then look at the difference in the relative molecular weight of the chain.

44 went in and 100 came out, so the mass of the solution decreased.

Ca(OH)2+CO2=CaCO3 +H20 There is Ca(OH)2 in the original solution, and the relative mass is 74, which disappears after the blind response, and becomes a swimming punch to do H2O filling, and the relative mass of H2O is 18 because 74 18

So the quality of the solution is reduced.

In fact, this anti-lease should be regarded as the first part of the two elimination parts, oh- and HCO3- react to form H2O and CO3-

Corresponding equation: oh-HCO3-

H2OC32-Part 2 CO32- and Ca2+ react to form CaCO3 precipitate.

Corresponding equation: CA2+CO32-

caco3 neutralizes these two equations and takes the formula, and this is the answer:

ca2+2oh-

2hco3-

caco3{precipitation}+h2o, thank you!!

ca2+2oh-

2hco3caco3

2H2OCo3)2+ [This is carbonate.

Ions because of the clarified lime water.

It is a strong electric volt to rise the lyte, and in the solution is a number of calcium ions and hydrogen and oxygen ions. Moreover, carbon deficiency and old acid sodium is also a strong electrolyte, and sodium ions and bicarbonate are in solution.

Because the ionic reaction of the metathesis reaction type is mainly based on a small amount, and the small amount is 1, that is, the stoichiometric number of a small amount is 1, the ionic equation of this reaction should be: HCO3 - CA2+ +OH - = CaCO3 +H2O

The chemical equation is: NaHCO3 + Ca(OH)2= CaCO3 + NaOH + H2O

I don't know if I've learned it before, first of all, the left side should be a CA ion, and the right side of the carbonate should be negative 2 valence.

A small amount of CO2 is passed into the clarified lime water.

, the mass of the solution is reduced after the reaction.

Because of the reaction equation:

CO2 + Ca(OH)2 = CaCO3 (precipitate tremor) + H2O into the solution is CO2, the precipitate is cavity-resistant CaCO3, and the weight gain of the solution is:

Therefore, a small amount of CO2 is introduced into the clarified lime water, and the mass of the solution is reduced after the reaction.

Let the mass of Na2CO3 be X, and the mass of NaHCO3 is 100GCaCo3 precipitate requires CO244G, i.e., Element C is required 12GC element conservation: Element C in Na2CO3: X*12 106 Element C in NaHCO3: (

x*12/106 +

x=naHCO3

Let the amount of Na2CO3 be x mol, and NaHCO3 be y molNa2CO3 - CO2; nahco3——co2；Both CO2 and CACO3 are 1:1

106x+84y= 44*(x+y)=44 x=na2CO3 is and NaHCO3 is.