A small problem with chemistry. Kneel down and beg my brother and sister to help me answer.

The reaction equation is:,Cu2s+14Hno3==2Cu(NO3)2+H2SO4+10NO2+6H2O.(Can equations be written?)

According to the conservation of N element and its destination, the ratio of the amount of Hno3 as an oxidant and the amount of Hno3 exhibiting acidity is 10:4==5:

2. Acidity 、、、 refers to the conversion of acid into its corresponding salt, for example, nitric acid is acidic in this question and combines with copper ions to form copper nitrate. This kind of problem is very easy to do, first write the redox equation, go on the road to see the reduction product of the acid (provided that it is an oxidizing acid) and the corresponding salt generated, and calculate the proportion according to the central element of the acid.

Acidity means that it reacts with metal and non-metal compounds to form salts, which is the Cu(NO3)2 of the substances generated, acidity is not reducing, but only refers to the reaction of acids and certain compounds to form corresponding acid-containing salts.

In this problem, the number of redox electrons is drawn using the two-line bridge method, and the total acid consumed is subtracted by the acid consumed by redox, which is the acid that expresses acidity, and then the ratio of the two is found.

Reaction formula: Cu2S + 14Hno3 = 2Cu(NO3)2 + H2SO4 + 10NO2 + 6H2O

In this reaction, the dilute nitric acid is partly involved in the redox reaction, and partly only as an acid, i.e. as a hydrogen ion. From the reaction formula, it can be seen that the amount of nitric acid as an oxidant is equivalent to the amount of the substance that produces NO2, that is, 10mol, and the amount of nitric acid as an acid is equivalent to twice the amount of the substance that produces copper nitrate, that is, 4mol, so the ratio of the amount of Hno3 as an oxidant to the amount of Hno3 that exhibits acidity is 10:

Acidity refers to dilute nitric acid that is used as an acid in a reaction. In this reaction, part of the dilute nitric acid plays the role of an oxidant, and part of it only does acid and does not participate in the redox reaction. You try to do the math.

I can only tell you how to do it, not the answer. I'm sorry.

To show acidity is to play the role of acidity, such as the nitric acid in copper nitrate, which produces salts, is to play the role of acidity.

Acidity is mainly manifested in the properties of salts formed with alkalis or alkaline oxides, and the acid itself does not rise or fall with valence.

Nitric acid that reduces monovalent copper to bivalent copper is reducible, and nitric acid combined with bivalent copper is reducible.

Refers to nitric acid that becomes copper nitrate. Nitric acid, which exhibits oxidizing properties, becomes nitrogen dioxide.

'/n=

The quantity of a substance of h is 1mol, the quantity of a substance of o is 2mol (multiplied by the number of measurements), and the number of atoms is and.

3.In the standard case, n=v'/v=

g n2 n = m m m = 7 14 =

v'=nv=

5.In the standard case, n=v'/v=

So it contains a molecule.

6.In the standard case, n=v'/v=

m=mn=multiplied by 10 to the 23rd power h is.

So it contains a 23rd H multiplied by 10

m=mn=

This kind of childish question is to turn the book and find the formula to do it yourself!

(1) Multiply 10 by the 23rd power of CO2 (carbon dioxide) The amount of matter is 2mol (2) The mass of 49 grams of H2SO4 is nh=1mol NO= The number of atoms is multiplied by 10 to the 23rd power *7 2.

3) In the standard case, the mass of the object is:

4) The volume of 7 grams of N2 in the standard case is 7 14 2 * (5) in the standard case, find the 23rd power molecule containing 2 * times 10 (6) in the standard case, find the mass as .

7) How many grams of H2SO4 are contained in the 23rd power of 10?

i.e. NH2SO4=

mh2so4=

1.The amount of carbon dioxide is 2 moles.

The amount of sulfuric acid is moles.

3.Under standard conditions, the amount of carbon dioxide is equal to divided by 3 moles.

The amount of nitrogen is molar, and the volume of molar gas in the standard condition is 5Under the standard condition, if the amount of gas is 2 moles, the number of molecules contained is 2 mol multiplied by 10 to the 23rd power, which is equal to the 23rd power multiplied by 10.

7.First calculate, multiply 10 by the amount of the substance to the 23rd power of h, then the amount of the substance containing h, then the amount of the substance of sulfuric acid should be half of h, is, so that the mass of sulfuric acid at this time is multiplied by 98g mol equal.

That's it! But I have to remind that this kind of homework is only the most basic calculation in high school, I hope that if you don't understand, you should read more books and practice more, these are not problems! Come on.

The answer is a

In the mixture of iron and copper, add a certain amount of dilute nitric acid to make it fully react and there are no nitrate ions in the solution.

Then add a certain amount of dilute sulfuric acid to it, and after full shaking, because there is nitrate in the solution, it can be regarded as nitric acid in the solution (there is H+ provided by sulfuric acid and nitrate ions in the solution itself), so as long as there is metal, the reaction will continue.

So m1 must be greater than m2