Xiao Xiao Ming and Xiao Li have 150 gold coins, how many gold coins do they have?

150 pcs. Every country has a large market for collecting ancient gold coins, and collectors also need to be aware of counterfeit gold coins. Maintenance of Gold Coins The order of oxidation resistance of the coins is gold, nickel, silver, brass, and copper.

Nickel has more oxidation resistance than silver, and copper is the most susceptible to oxidation. Platinum, palladium, and aluminum-magnesium alloys do not need to be sorted because they are not the mainstream of refined coins.

The gold element in nature does not react with the oxygen and other gases in the air, because the purity of the gold coin is not too pure, which contains a small amount of silver and other metal components, so the surface of the gold coin often appears trace oxides, mainly the sulfur element in the air and the silver in the gold coin to form trace sulfides.

Metal oxidation is related to the material, and it has a lot to do with storage, such as ** jewelry before 1000 years, some of which are golden and some are also dirty, so it is meaningful to discuss the way of coin binding and storage.

Xiao Ming and Xiao Li have 150 gold coins. According to the title. They have a total of 150 gold coins.

Addition of a single digit: When two single digits are added, the sum can be found directly by counting the number.

The result of the addition of two single-digit numbers is usually compiled into an addition table.

Addition of multiple digits: the addition of numbers on the same digit; Add up to ten in one place, and add one to the previous one.

To add multiple digits, you can first write two multi-digit numbers as the sum of different counting units.

Then, according to the law of addition and the law of one-digit addition, the numbers of the same counting unit are added together.

Addition Rule: When using the "truncation method" in addition or subtraction, add or subtract directly from the left high position (while paying attention to whether the next digit needs to be carried and misplaced) until you get the answer that the option requires precision. When using the "truncation method" in multiplication or division, in order to make the results as accurate as possible, it is necessary to pay attention to the direction of the interception approximation:

1. To expand (or shrink) one multiplier factor, it is necessary to shrink (or expand) another multiplier factor;

2. To expand (or shrink) the dividend, it is necessary to expand (or shrink) the divisor. If you are looking for the sum or difference of the product of two times (i.e., a*b+ -c*d), you should pay attention to:

3. If one side of the plus sign is enlarged (or reduced), the other side of the plus sign shall be reduced (or expanded);

4. Enlarge (or reduce) one side of the minus sign, then enlarge (or reduce) the other side of the minus sign.

Xiao Ming and Xiao Li each have 150 gold coins, and they have a total of 150 * 2 = 300 gold coins.

Xiao Hong has 500 gold coins, which are Xiao Ming's 2 3, Xiao Mei's 5 6, and Xiao Ming's gold coins, 750 gold coins.

Divide 500 by 2 3 equals 750, which means that Xiao Hong has 500 gold coins and Xiao Ming's 2 3 has 750 gold coins.

500 2 3 500 3 2 750, so Xiao Ming has 750 gold coins.

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We can assume that Xiao Ming's money is xYuan, then Xiaohong is 1 5x.

You can get: x+. The solution is x 500, so Xiao Ming is 500 yuan, and Xiao Hong is 100 yuan.

Xiaohong and Xiao Ming have a total of 600 yuan, and Xiaohong's money is 1 5 of Xiao Ming's money. How much money does Xiaohong and Xiaoming have?

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Well. Hello! Glad to answer for the key to eliminate you!

We can assume that Xiao Ming's money is xyuan, then the small red balance is 1 5x. You can get the manuscript to know:

x+。The solution is x 500, so Xiao Ming is 500 yuan, and Xiao Hong is 100 yuan.

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Dear, have you learned the unknown?

No. Okay, then you wait a minute.

Good. Change to a good one.

That can be calculated like this: 600 yuan. This one is Xiao Ming's. 600-500 = 100 yuan, this is Xiaohong's.

Dear, you can help the teacher upgrade, and I will explain the relationship to you in detail.

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Xiao Hong has another 30 gold coins to surpass Xiao Ming.

Hello! Glad you raised your question!

According to the inscription: 36 7 29 (pieces) 30 (pieces) Answer: Xiao Hong must have at least 30 gold coins to surpass Xiao Ming.

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Xiao Ming has 50 yuan, which is 2 times less than Xiaoli, 8 yuan, and Xiaoli has 29 yuan.

According to the title, Xiaoli has x yuan.

Column equation: 2x-8=50

2x=50+8

2x=58x=29

So the little bend finger Li has 29 yuan.

Methods for solving equations:

1. Denominator: Multiply both sides of the equation by the least common multiple of each denominator at the same time.

2. Remove brackets: Generally, go to the small brackets first, then bury the waiter to remove the middle brackets, and finally go to the braces.

3. Shift terms: Move the terms containing unknown numbers in the equation to the other side of the equation, and don't forget to change the sign when moving the remaining items to the other side of the equation.

4. Merge and talk about similar terms: Transform the original equation into the form of ax=b.

5. The coefficient is one: the coefficient of the two sides of the equation divided by the unknown number at the same time.

6. Derive the solution of the equation.

Xiaomin and Xiaoli each have 50 yuan and 29 yuan.

Because the two of them have a total shortage of 100 + 50 = 150 yuan, and the same amount is 150 2 = 75, so Fan argues that Xiaohuai needs to give Xiaoli 100-75 = 25 yuan.

25 yuan, and divide the amount of money that Xiao Oak Gao told him to be more than Xiao Li to two Liang Ming people, and the two people will have the same amount of money. So the difference between one hundred and fifty and divide by two gives 25.

100 + 50 = 150, 150 2-50 = 25, Xiao Ming gave Xiao Li 25 yuan, the two of them are the same.

Xiao Ming has 50 yuan, which is 2 times less than Xiaoli's 8 yuan, and Xiaoli has 29 yuan.

The details are as follows: Xiaoli's amount;

So Xiaoli has 29 yuan.

The nature of hybrid operations is macroIn mathematics, when the first-level operation (addition and subtraction) and the second-level operation (multiplication and division) are in a single grinding formula at the same time, their order of operation is first multiplication and division, then addition and subtraction, if there are parentheses, they are counted in the parentheses first and then outside the parentheses, and the order of operations at the same level is from left to right.

From the commutative and associative properties of addition, it can be obtained: several additions are added, and the positions of the additions can be arbitrarily exchanged; Or add a few additions and then add them to the other additions, and their sum does not change.

Xiao Ming has 50 yuan, and Xiao Li's amount may be greater than Xiao Ming's 50 yuan, or less than Xiao Ming's 50 yuan.

Supplementary conditions: The amount of money in Xiao Li's bright branch is 15 yuan more than 2 times that of Xiao Ming.

Key dress 115 (yuan).

Answer: Xiao Wu Minli has 115 yuan.