Everybody help me solve a 6th grade math problem.

A: B = 8:5 = 16:10

B: C = 10:7

So A:B:C = 16:10:7

Think of it this way: Divide 1815 into 33 (16+10+7) parts.

A accounted for 16 parts, B accounted for 10 parts, and C accounted for 7 parts.

That portion is 1815 divided by 33=55

One part is 55, then 16 parts A is 880, 10 parts B is 550, and 7 parts C is 385

Check it: A + B + C = 880 + 550 + 385 = 1815 success.

Because A is 8:5 than B, A is also 16:10 than B, so A is 16:10:7 than B

And 16 + 10 + 7 = 33

Therefore, A, B, and C accounted for 16 33, 10 33, and 7 33 respectively.

So A = 1815 16 33 = 16 * 55 = 880 B = 1815 10 33 = 550

C = 1815-880-550 = 385

Because, A B = 8 5, so 5 A 8 = B.

And because B C = 10 7, then 7B 10 = C.

C = 5 A * 7 8 * 10

1815 = A + B + C.

1815 = A + 5 A 8 + 5 A * 7 8 * 101815 = 33 A 16

A = 880, B = (880*5) 8 = 550, C = (550 * 70) 10

Except, * multiplication.

Think of B as a whole! A is eight times the size of B! C is seven-tenths of B's! That is, x+8 5x+7 10x=1815

B is equal to 550

A is equal to 550 8 5

A is equal to 880 C is equal to 550 7 10

C is equal to 385

It can be seen that B: C = 5:

Bring in A:B:C = 8:5:16:10:7 and then use it to distribute proportionally.

A=1815 (16+10+7)*16

B = 1815 (16+10+7)*10

C = 1815 (16 + 10 + 7) * 7

A: B = 8:5 = 16:10

A: B: C = 16:10:7

So just divide 1815 into 33 (16+10+7) parts, where A accounts for (1815 33)*16=880

The other two don't count. Do the math yourself.

The sixth grade has already learned equations, and it is easy to solve them with equations, so this book has a total of x pages, and the equations are listed and solved according to the title.

Now A and B have their own.

80 2 40 (kg).

It turns out that A has. 40 (1 1/7) 140 3 (kg) turned out to be B. 80 140 3 100 3 (kg).

Didn't you say that it weighs 80 kilograms? If it is how many kilograms each, look at the formula.

x+y=80 1 6x+y=5 6x gets x 140 3 y=100 3

Let A be x, B is, x-1 7x=1 7x+, y=I think the last thing you asked was how many kilograms each. and not how many kilograms in total.

Isn't the answer in the question, 80 kilograms.

The central angle of the fan chart is 360°, and the rose tree accounts for 52%, so use 360° 52%=. Chrysanthemum trees account for 18%, use 360° 18%=. If the tree is planted with 30%, use 360° 30%=180°

The central angle of the fan of a tree representing roses is (360x52%=) degrees, the central angle of a tree representing chrysanthemums is (360x18% = ) degrees, and the central angle of a tree representing lilies is (360x30%=108) degrees.

The fan-shaped central angle of the rose tree is 360*52%=degrees).

The fan-shaped center angle of the chrysanthemum tree is 360*18%=degrees).

The fan-shaped central angle of the lily tree is 360*30%=108 (degrees).

A square with the largest quarter circle in it, then the length of the sides of the square is equal to the radius of the circle.

So the square of the radius is 8

Therefore, the area of a quarter circle is 8* square centimeters.

Because E is the midpoint of AD, the area of BCE = half of the area of ABC, which is 12 2 = 6

Because F is the midpoint of EC, the area of BEF is half that of BCE, which is 6 2 = 3

So the area of the BEF is 3

E is the midpoint of AD, so the area of BCE = half of the area of ABC, which is 12 2 = 6

F is the midpoint of EC, and the area of BEF is half that of BCE, which is 6 2 = 3

The area of the BEF is 3