Hurry to solve math, algebra, geometry problems

According to the title, b(-2,0)d(1,0).

Then find the analytic formula of the function of ad and bc.

is y=-2x-2, y2=-x-2

Because they intersect at one point, -x-2 = -2x-2

The solution is x=0, so point e is on the y-axis.

2.First, find the coordinates of point e: substitute x=0 into y=-2x-2 to get the coordinates of point e (0, 2) so the parabolic vertex is (0, 2).

Use the formula y=a(x+m) 2+k to bring in the vertex coordinates.

y=ax^2-2

Bring in a point other than the fixed point.

3=a-2a=-1

Then bring back y=a(x+m) 2+k to get y =-x 2-23The third question is whether the coordinates of point C are wrong, because the horizontal movement and the ordinate remain unchanged.

As pq bc intersects at the point h, ac at the point q we can find :cd provable: ahc ahp ahq ahd hq hd ch hp and he ab pq bc quadrilateral behp is a parallelogram ch hp be let hc x then hq hd 2 4 x can be found from the pythagorean theorem:

ad aq cq x solution x ch hp be i.e. be=3 2

1.affected.

Cross point A to do AQ BF at point Q

From EBF=60 degrees, FBA=30 degrees.

In RT Baq, AQ = 1 2*AB

160(km)

Because 160<200, it is affected.

After the hour passes the point A, draw an arc with a radius of 200km, cross BF to the point Mn, connect AM, AN in RT AQM, according to the Pythagorean theorem, we can get MQ=120, in RT AQN, according to the Pythagorean theorem, we can get NQ=120, so MN=MQ+NQ=240

240 40 = 6 (hours).

So City A was affected by this typhoon for 6 hours.

There are two problems in this question: (1) This "equation" is not an equation, and it is an equation after adding =0, but it is not a unary equation, nor is it a binary equation, but a quadratic equation; (2) The position relationship between the two circles cannot be judged in this question, and the position relationship between the two circles can only be judged by knowing the situation of the root of the equation.

In the equation =b -4ac=(r+r) -d r+r and d are both positive numbers, if the equation has two unequal real roots, then 0, then r+r d, the two circles are separated;

If the equation has two equal real roots, then =0, then r+r=d, two circles are intangent;

If the equation does not have a real root, then 0, then r+r d, the relationship between the two circles may be intersecting, inscribed, and contained (including concentric circles).

It's simple, but you don't score, forget it, don't bother to type.

I guess you have a problem with this formula! =0 should be added at the end. There is no equal to a few, it is difficult to judge.

This is the first year of junior high school, and I'm only in the second year of junior high school.

Proof that the connection GH, the intersection AC at the point O, the connection AG, and the CH ABCD are parallelograms.

ab=cd，ab∥cd，bh=dg

AH=CD quadrilateral, AHCG is a parallelogram.

og=oh，ao=oc

ae=cfoe=of

The quadrilateral gfhe is a parallelogram (a quadrilateral whose diagonals are bisected diagonally is a parallelogram).

I just want to say, back then, I knew how to do this.

The inverse ordinal number of both is equal. Think of it as follows: Let p be the ,.. (1,2).

n) becomes (a1,a2,..an), if for iaj, since p (-1) reflects ai to i and aj to j, then for ajiThat is, the reverse pair in p corresponds to the reverse pair in p (-1).

n(n-1)/2-a

Considering the permutation p, if the logarithm i has t(i)=ai, then the number of ai on the left side of i is greater than i, and the number of i-1-ai on the right side of i in p-1 is less than i, that is, t(i)=i-ai in p-1, so t(p)+t(p-1)=a+t(p-1)=sigma(i-1)=n(n+1) 2-n=n(n-1) 2, that is, proof.

If the question is incorrect, it should be "How much is BC?" ”

The analysis is as follows: <>