Unary equations, questions answered! Remember, you must use a one dimensional equation to solve it!

1.Two men, Man A, said, "Give me one of your sheep, and my sheep will be twice as many as your sheep." B said, "If you give me one of your sheep, we will have the same number of sheep." "How many sheep are there for each of them?

Solution: If A has x, then B has x-2.

x+1=2(x-2-1)

x+1=2(x-3)

x+1=2x-6

2x-x=1+6

x=7x-2=7-2=5

A: A has 7 and B has 5.

2.Now the price of a product is reduced by 10%**, in order to keep the total sales amount unchanged, how much more than when the sales volume is sold at the original price?

Solution: Suppose the sales volume increases by x

1-10%)(1+x)=1

1+x=10/9x=1/9

A: Sales increased approximately.

3.There are some rooms that need to be painted, and 3 first-class technicians go to paint 8 rooms a day, of which 50m of the walls will have time to be painted; In the same amount of time, 5 Level 2 mechanics painted 10 rooms and another 40m of walls. Each first-level technician paints 10m more walls a day than second-level technicians, and finds the area that needs to be painted in each room.

Solution: Set the area that needs to be painted in each room to be x square meters.

8x-50)/3-(10x+40)/5=10

Multiply by 15 at the same time to get:

5(8x-50)-3(10x+40)=150

40x-250-30x-120=150

10x=520

x=52A: The area that needs to be painted in each room is 52 square meters.

4.A rode a bicycle from A to B, and B rode a bicycle from B to A, and the two of them moved at a constant speed, and it is known that they set off at 8 a.m., and by 10 a.m., they were still 36 kilometers apart, and by 12 noon, they were 36 kilometers apart, and the distance between A and B was found.

Solution: Let the distance between AB and the two places be x kilometers.

x-36)/(10-8)=(x+36)/(12-8)

x-36)/2=(x+36)/4

2(x+36)=4(x-36)

2x+72=4x-144

2x=216

x=108A: The two places are 108 kilometers apart.

1: Let B have x sheep, then A has 2(x-1)-1 to get equation 2(x-1)-1-1=x+1

Solve x=5 so A has 7 and B has 5.

2: Assuming that sales should increase by x%.

Then (1-10%)*x=1

Solve x=10 9=

3: Each room has x square meters.

Then the speed of a first-level worker is (8x-50) 3

The second-level worker is (8x-50) 3+10

The equation ((8x-50) 3+10)*5=10x+40 is solved to x=22

4: Let the two places be separated by x

Then the total distance traveled by A and B in each hour is (x-36) 2, then four hours later, at 12 o'clock, there is an equation.

4*（x-36）/2=x+36

Solve x=108

Solution 1: Let A have x, and it can be seen from what B says, and B has x-2, and the words spoken by A list the unary equation.

x+1=2[(x-2)-1]

x = 7 B has 7-2 = 5.

2 Solution: Let the equation increase x%.

1-10%)(1+x%)=1

x%=1/9x=

1 Let A be x According to "B says, "If you give me one of your sheep, we will have the same number of sheep", then we know that B is x-2 and we get equation 2 (x-2-1) = x+1 and find x=7

2 Let the sales volume be x The original ** sales volume is regarded as 1 to get the equation 1*1=( Find x=1 9

3 Suppose the area to be painted in each room is x The area to be painted in one day by a first-level mechanic is (8x-50) 3 The area to be painted by a second-level mechanic in one day is (10x+40) 5 Then (8x-50) 3 -(10x+40) 5=10 is obtained by x=52

4 Let the distance between A and B be x, and the total distance traveled by A and B in two hours is x-36, and the total distance traveled from 8 o'clock to 12 o'clock is 2(x-36), and 2(x-36)-36=x is obtained, and x=72 is obtained

Let the number of white blocks be x.

Then because the number of sides where the black block meets the white block is fixed, so.

12 black blocks, 5 sides per adjacent white block) 12*5=3*x (x white blocks, 3 sides per adjacent black block).

x=20 means that the number of white blocks is 20.

8: Set: The original amount of coal is x?

x－15）÷（15÷3×1／2）＋3－10＝x÷（15÷3）（x－15）×2／5－7＝x／5

2x／5－6－7＝x／5

x／5＝13

x 6510: Tree planting this year x(1 20)11: Which of the following statements is incorrect: c

14: The two-digit numbers are: b and c

20: The ** price needs to be a9% off. (1 8 ) 1 20 ) 23: Set: Apple bought x kilograms?

4x＋（5－x）×3＝17

4x＋15－3x＝17

x 2 pears 5 2 3 kg.

Let's imagine that a garment production line and 2 children's clothing production lines can produce a total of 105 tents a day, and 2 garment production lines and 3 children's clothing production lines can produce 178 tents, then their difference is that a garment production line and a children's clothing production line can produce 178-105=73 tops a day (this should be no problem, you can understand it, if you can't understand this, then you don't need to do this question).

Solution to the first problem:

Design: One garment production line can produce tents x tops per day Then the children's clothing production line can produce 73-x tents per day.

The system of unary equations x+2*(73-x)=105

x+146-2x=105

x=41 to find the solution One day multiplied by the production line can produce 41 tents, then the children's clothing production line can produce 32 tents a day.

Validation: Bring x into the equation 2x+3(73-x)=178

Left equals right so the answer is correct.

So the answer to the first question is 41 tents per day multiplied by the production line, and 32 tents per day can be produced per day on the children's clothing production line.

The second problem is solved.

Each garment production line can produce tent x tops per day Each children's clothing production line can produce tent 73-x tops per day.

Then the daily production volume of the factory is:

The unary equation is 4x+5*(73-x)=the amount of production per day.

Bring x=41 into the equation 4*41+5*32=164+160=324 top.

Then the total output of 3 days is 324*3=972 tops, less than 1000 tops.

Therefore, if the factory is fully operational, it will not be able to complete the task as scheduled.

The above few people can see clearly, people want to solve it at a time, not at a time, not at a time, and there is no way, this is the current mathematics education, which can only be solved at a time.

(1) Set the top of x y respectively.

x+2y=105 2x+3y=178

The solution is x=41 y=32

2)3(4x+5y)=972<1000 so can't).

(1) Suppose that ready-to-wear can produce x sheets, children's clothing can produce y sheets, and the equation x+2y=105 1 can be obtained

2x+3y=178 2

Converting Equation 1 to x=105-2y and substituting Equation 2 yields 2(105-2y)=178

The solution is y=16

Substituting y=16 into equation 1 gives x=105-36 solution x=69 So 69 pieces of ready-to-wear and 16 pieces of children's clothing.

2) Make 69 pieces of ready-to-wear every day, and 16 pieces of children's clothing, then use the first day to make two ready-to-wear and three children's clothes to make 178 tops, and use 1 piece of ready-to-wear on the second day, 2 pieces of children's clothing can do 105 tops, 178+105 is less than 1000, so it can't.

I don't think it's as easy to use one dollar at a time as it is to use binary once.

1) Solution. Set the ready-to-wear production line as X top, and the children's clothing production line produces tent Y top on average every day.

x+2y=105

2x+3y=178

x=41 y=32

2 yuan per catty of vegetables, how many catties of vegetables can you buy for 15 yuan?

Set 15 yuan to buy x catties of vegetables. According to the title, 2x=15

The equation of 2x=15 solves the practical problem.

A test paper consists of 26 questions, 8 points for a correct answer, 5 points for a wrong answer, and a candidate has answered all 26 questions, but the total score is zero, ask him how many questions he answered correctly?

Solution: Let the student answer x questions correctly.

8x-5(26-x)=0

x=10Answer: He answered 10 questions correctly.

In the following equation, the unary equation is (d).

a 3x+y=1 b x -1/2 + 5=0 c x + 1/3 = 1-1/x d -5x = 3x+4

The so-called unary equation contains only one unknown and the highest order of the term is 1

A has 2 unknowns and b has an x square, which is quadratic and cx is on the denominator.

If 3x-2 and 4-5x are inverse numbers to each other, then x=1

Since it is an opposite number, that is, the addition is equal to 0, and a one-dimensional equation is slowly solved.

x=3 is the solution of equation 4x-3(a-x)=6x-7(a-x), then a= 9 2

Since x=3 is the solution of the original equation, bring x=3 into the original equation to get a one-dimensional equation about a, and treat a as an unknown to solve.

Solve the following equation and test it.

Shift the term to get -x=7

x=-72. 2+2/3x=3x+5

Multiply both sides by 3,6+2x=9x+15 at the same time

Shift item -7x=11

x=-11/7

3. 6/5y-1=3/7

Shift, 6 5y = 1 + 3 7 = 10 7

y=25/21

The test is to bring it in, left = ...Right = ...Left = Right).

dx=1

a=9/23x-3=4x+4

x=-7, after testing, is the solution.

2+2/3x=3x+5

x=-9 7, after testing, is the solution.

6/5y-1=3/7

y=25 21, after testing, is the solution.

d a is binary b is quadratic c c is a fractional equation, and a unary primary requirement is an integral equation 1 3x-2=-(4-5x) x=1

x=3 is substituted into the original equation 12-3(a-3)=18-7(a-3)a=

x=-77/3)x=-3 x=-9/7

6/5)x=10/7 x=25/21

Hour. 70x = 50x + 245 is a very simple equation.

The distance from home to school is x km, the time to go to school is x 6 hours, and the time taken to return is x 4 hours, the equation is: x 6 + x 4 = 2, and the equation is solved x = km.

2, the problem is wrong, 3, let the number of gold medals be x, then the total number of silver and bronze is (x-2), the column equation, x+(x-2)=100, the solution, x=51, the number of gold medals is 51, the total of silver and bronze is 49, and then the number of silver medals is y, then the number of bronze medals is (49-y), (49-y)-y=7, the equation is solved to get y=21, the number of silver medals is 21, and the number of bronze medals is 28

4. Let the number A be x, then the number B is (60-x), x=3(60-x)+12, and the equation is solved, x=48, so the number A is 48, and the number B is 12. 2[2(2x-1)-1]-1=0

x = 7/8.

Question 1 km 2.

I know question 6, I did.

2[2(2x-1)-1]-1=0

x = 7/8.

I promise yes.

If x fighters are transferred to A, 100-x fighters are transferred to B.

Column equation 91+x=(49+100-x) 3-1291+x=300+147-3x-12

4x=334

x=86A: 86 fighters to A and 14 fighters to B.

The ones with the x are placed on the left, and the numbers are placed on the right.

Then divide both sides by the coefficient before x.

This gives us x=.