High School Chemistry Questions What is the definition of high school aliphatic hydrocarbons about a

Updated on educate 2024-05-23
13 answers
  1. Anonymous users2024-02-11

    Because the relative density of hydrogen is 27, the hydrocarbon formula is 27*2=54g|mol because the hydrocarbon can react with 100ml of bromine water.

    Therefore, the hydrocarbon has two unsaturated bonds, and because the hydrocarbon is a hydrocarbon, it is composed of only C, H elements, which is set to CNH(2N-2), 12N+(2N-2)=54, N=4, so the hydrocarbon is C4H6

  2. Anonymous users2024-02-10

    First of all, relative to the density of hydrogen is 27, its molecular weight is about 54, divided by 14, the carbon content is 4, and in such an ideal case, the molecular weight can be considered to be 54.

    Approximately, it can react with br2, then the unsaturation is 2, containing two double bonds, four carbons, and the stable existence is 1,3-butadiene.

  3. Anonymous users2024-02-09

    From the relative density of gaseous unsaturated hydrocarbons to hydrogen is 27, it can be concluded that the molar mass of the hydrocarbon is 27x2=54g mol, and the amount of the hydrocarbon is the amount of the substance with a concentration of 100ml of bromine water.

    The hydrocarbon happens to react with bromine water, the ratio is 1:2, so the unsaturation of the hydrocarbon is 2, let the molecular formula of the hydrocarbon be CNH(2N-2), so 12N+2N-2=54, and the solution is n=4

    Hence the molecular formula of this hydrocarbon is C4H6

  4. Anonymous users2024-02-08

    It is easy to obtain that the relative molecular weight of the hydrocarbon is 54, and the hydrocarbon is added with bromine water, so the hydrocarbon has two carbon-carbon double bonds or one triple bond, and the molecular formula can be CNH2N-2So 12n+2n-2=54, n=4Therefore, the molecular formula is C4H6

  5. Anonymous users2024-02-07

    Aliphatic hydrocarbons refer to hydrocarbons that have the basic properties of aliphatic compounds. Because this type of organic matter was first extracted from fat, it is also called aliphatic hydrocarbons. Aliphatic hydrocarbons and their derivatives (including halogenated hydrocarbons) are called aliphatic compounds.

    In aliphatic compounds, the carbon atoms are arranged in a disturbing straight, branched or cyclic pattern, which are called linear aliphatic hydrocarbons, branched aliphatic hydrocarbons and alicyclic hydrocarbons, respectively.

    Aliphatic hydrocarbons are generally important components of oil and gas. C1 and C5 low-carbon aliphatic hydrocarbons are the basic raw materials of petrochemical industry, especially ethylene and propylene and C4 and C5 conjugated olefins, which are the most widely used in petrochemical industry.

  6. Anonymous users2024-02-06

    Aliphatic hydrocarbons: Hydrogen-depleting compounds with the basic properties of fatty compounds.

  7. Anonymous users2024-02-05

    The answer is c. The key to the topic is the molecular weight of fats.

    According to the iodine value, the amount of unsaturated bond substances in 100g of oil can be calculated, which is 116 254=;

    A option, the molecular weight of the oil is 886, then the amount of the substance of 100g of oil is 100 886 =, then according to the iodine value, there are 4 double bonds in the molecule, which is inconsistent with the molecular structure;

    option b, the molecular weight of the oil is also 886, and there are 4 double bonds in the molecule, which does not match the molecular formula;

    Option c, the molecular weight of the oil is 882, then the amount of the substance of 100g of oil is 100 882=, and there are 4 double bonds in the molecule, which is consistent with the molecular formula;

    In option d, the molecular weight of the lipid is 802, and the amount of the substance of 100g of grease is 100 802=, and there is a double bond in the molecule, which is obviously impossible.

    So the answer is c.

  8. Anonymous users2024-02-04

    One mole of carbon-carbon double bond requires 1 mole of iodine to add...

    One mole of iodine is 127 * 2 = 254g 116 254 = that is, 100g of oil contains mole of unsaturation.

    a886g per mole with 2 moles of carbon-carbon double bonds. (2 886)*100= Not equal, so wrong.

    The same is true for calculating judgments. c option (4 882) * 100 = approximately equal. So C is correct.

  9. Anonymous users2024-02-03

    I don't think you will understand when he explains it like this ...

  10. Anonymous users2024-02-02

    It is a general term for cyclic hydrocarbons and their derivatives. Carbon ring compounds that belong to the aliphatic group are also known as alicyclic compounds.

    My understanding: Fat refers to triglycerides, esters of glycerol and fatty acids. Because fatty acids have a long carbon chain, aliphatic hydrocarbons are chain hydrocarbons. Fatty alcohols should be long-chain alcohols. It is characterized by a long straight line, and it can also have a double key...

  11. Anonymous users2024-02-01

    High school elective five: aliphatic hydrocarbons, alicyclic hydrocarbons, alicyclic compounds, aliphatic compounds.

    Hydrocarbons with the basic properties of aliphatic compounds are called aliphatic hydrocarbons, and the carbon atoms in the molecule are linked to each other to form a chain-like carbon frame, and the hydrocarbons that are open at both ends and do not form a ring are called open-chain hydrocarbons, referred to as chain hydrocarbons. Because fats have this structure, they are also called aliphatic hydrocarbons. Some cyclic hydrocarbons are different in nature from aromatic hydrocarbons and very similar to aliphatic chain hydrocarbons, and these cyclic hydrocarbons are called alicyclic hydrocarbons.

    In this way, aliphatic hydrocarbons become the general term for all hydrocarbons except aromatic hydrocarbons. Aliphatic hydrocarbons and their derivatives are collectively referred to as aliphatic compounds, and alicyclic hydrocarbons and their derivatives are collectively referred to as alicyclic compounds.

  12. Anonymous users2024-01-31

    cnh2n+2 ->nco2 + n+1)h2ocnh2n ->nco2 + nh2o

    The ratio of CO2 volume to initial volume is the number of carbon atoms in alkane or alkene, n = 21 volume C2H6 to generate 3 volumes of water vapor.

    1 volume of C2H4 produces 2 volumes of water vapor.

    Let the volume fraction of alkane be a: 3a + 2(1-a) = a =

    The volume fraction of alkene is: =

    Volume ratio of alkanes and olefins in gas mixtures: = 2:3

  13. Anonymous users2024-01-30

    The volume of this gas mixture is completely burned in oxygen, and the volume of CO2 and the volume of water vapor are generated under the same condition, then each mole of substance contains 2 moles of C atoms and 2* moles of hydrogen atoms. It should be ethane and ethylene.

    Set alkanes x molar and olefin y mol.

    x+y=16x+4y=

    The volume ratio of alkanes and olefins in the gas mixture is 2:3

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