The cost of A and B s two pieces of clothing totaled 500 yuan, and the store owner made a profit

Solution: Let the cost price of A be x and the cost price of B y.

x + y = 500 (a.) The cost of two pieces of clothing is 500 yuan) x (1 + 50%) * 90%.

A clothing is priced at 50% of the profit, and then, at the request of the customer, both garments are priced at a 10% discount **) y (1 + 40%) * 90%.

A clothing is priced at 40% of the profit, and then, at the request of the customer, both garments are discounted by 10% **) x (1 + 50%) * 90% + y (1 + 40%) * 90% -500 = 157 (the store makes a total profit of 157 yuan).

That is, y=500-x is obtained by substituting .

x=300y=200

A: A: 300 B: 200

Suppose that the cost of clothing A is $x, then the cost of clothing B is (500-x) yuan.

Then: [(1+50%)x+(500-x)(1+40%)] solution: x=300

So the cost of clothing A is 300 yuan, and the cost of clothing B is 200 yuan.

x + y =500

x *（1 +50%） x *（1 +40%） =730x=300y=200

The price of the first standard is 450

The price of the second standard is 280

The actual price of A is 405

The price of the second standard is 252

A's actual profit is 105

B actually made a profit of 52

Set: The cost of A and B two pieces of clothing is x and y respectively

1）、x+y=500 —>x=500-y

2), x (1 + 50%) + y (1 + 40%) = 730 - >1) substitute (2) - y = 200, x = 500 - y = 300 that: the actual price of clothing A = x (1 + 50%) * 90% = 300 * the actual price of clothing B = y (1 + 40%) * 90% = 200 * the actual profit of clothing A = 405-300 = 105 yuan.

The actual profit of B clothing = 252-200 = 52 yuan.

Solution: Let the cost of A be x yuan, then the cost of B is (500-x) yuan x (500-x -500=157x=300

500-300 = 200 (yuan).

A: The cost of B is $200 and the cost of A is $300.

Solution: Let the cost of A be $x, and the cost of B be $500-x (1+50%)x*

x=300500-300=200 yuan.

A: The cost of A is 300 yuan, and the cost of B is 200 yuan.

The cost of dissolving A is $x, and the cost of B is $y.

x+y=500

1+50%)x+(1+40%)y] 90%=500+157 solution: x=300 y=200

1 represents the index of cost and 50% represents the index of profit.

If the cost of A is 300:

300 * [1 + 50%] = 300 * the price is 450 yuan.

The above is 300 + 300 * 50% = cost 300 + profit 150 = selling price 450

Selling Price = Cost + Profit = Cost + Cost * Profit Margin = Cost * (1 + Profit Margin).

The formula is like this: 1+50% is equivalent to 1+ profit margin.

I wonder why A90 (x+50 x) is equal to 90% (1+50%)x, while B wants 90% (1+40%) (500-x) and can't be 90% (500-x)+40%? Ask a well-wisher to explain the explanation

1 indicates that these are added to the original price.

1 is the representative product cost base.

Let the cost of A be $x, and the price of A is $x (1-50%), then the cost of B is $500-x, and the price of B is (500-x) (1-40%).

x÷（1-50%）+500-x）÷（1-40%）]90%-500=157

2x+2500/3-5x/3）×

2x+2500/3-5x/3=730

x/3=-310/3

x=-310 yuan.

The cost of B is. 500-x=500-(-310)=810 yuan verification: the cost of A is -310 yuan, the pricing of A is -620 yuan, and the profit is:

248 yuan. The cost of B is 810 yuan, the price of B is 810 yuan, and the profit is:

405 yuan. The profit is: 405 + (-248) = 157 yuan, the calculation is correct.

A negative number indicates that there is a problem with the data given in the question.

Either the profit of 157 yuan is too little, or the discount is too low, or the price is too high.

Analysis: If the cost of clothing A is x yuan, then the cost of clothing B is (500 x) yuan According to the formula "total profit = total selling price - total purchase price", the equation can be listed Solution: If the cost of clothing A is x yuan, the cost of clothing B is (500 x) yuan, according to the title:

90%•（1+50%）x+90%•（1+40%）（500－x）－500=157

x = 300 then the cost price of B is: 500 300 = 200 (yuan) Answer: The cost of clothing A is 300 yuan, and the cost of clothing B is 200 yuan.

Solution: If the cost of clothing A is X yuan, the cost of clothing B is (500-x) yuan; The pricing of clothing A is (1+50) x = yuan, the selling price of clothing A is yuan, and the profit of clothing A is yuan; The pricing of clothing B is (1+40) (500-x) = (yuan, the selling price of clothing B is yuan, and the profit of clothing B is (yuan, according to the title, there is an equation:

x=300500-x=500-300=200

A: The cost of clothing A is 300 yuan, and the cost of clothing B is 200 yuan.

Solution: A's actual profit margin is (1+50%)

B's actual profit margin is (1+40%)

The cost of A is (157-500x26%) 35%-26%)=300 yuan, and the cost of B is 500-300=200 yuan.

A: The cost of A is 300 yuan, and the cost of B is 200 yuan.

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(1) If the original cost of home clothing is assumed to be x yuan, then the actual selling price of A is x*(1+50%)*yuan, and the actual selling price of B is (500-x)*(1+40%)*yuan(2)x=300

Therefore, the cost of two pieces of clothing A and B is 300 yuan and 200 yuan respectively.

Brother, it seems that you have less conditions in this question, and you can't calculate specific numbers, but you can only get a range. Unless commodity B is at 20% off cost**.

From the question: when pricing, the boss hopes to get half of the profit, let the cost of goods A and B be a and b respectively, then there is a + b = 500, and the price of a commodity is 2a; The actual selling price is, and the actual profit of the sale of commodity A is; If commodity B is at a 20% discount on cost**, then commodity B loses money. The total take-home profit of the boss is the profit of commodity A minus the loss of commodity B, i.e.:

and a+b=500, the solution is a=245, b=255

Let A be a and B be B

a+b=500

Yields: a=300

The ** of b=200** is:

A = B = calculated according to the nine-fold discount.

The ** sold by A is:

The ** sold by B is:

A profit = 405-300 = 105

B profit = 252-200 = 52

The cost of A is x, and the cost of B is y

x+y=500

The solution is x=300 y=200

A actually makes a profit.

B actually makes a profit.

Dad hit **, chirp

Solution: Let the cost price of A be x and the cost price of B y.

x + y = 500 (a.) The cost of two pieces of clothing is 500 yuan) x (1 + 50%) * 90%.

A clothing is priced at 50% of the profit, and then, at the request of the customer, both garments are priced at a 10% discount **) y (1 + 40%) * 90%.

A clothing is priced at 40% of the profit, and then, at the request of the customer, both garments are discounted by 10% **) x (1 + 50%) * 90% + y (1 + 40%) * 90% -500 = 157 (the store makes a total profit of 157 yuan).

That is, y=500-x is obtained by substituting .

x=500y=0A: The cost price of A is 500, and B does not need money. (Strange title).

Solution: (1) If the cost of clothing A is x yuan, then the cost of clothing B is (500-x) yuan, according to the question: 90% (1+30%) x + 90% (1 + 20%) (500-x)-500 = 67, solution: x = 300, 500-x = 200

Answer: the cost of clothing A is 300 yuan, the cost of clothing B is 200 yuan (2) The cost of clothing B is 200 yuan, after two increases, the purchase price of each piece of clothing B reaches 242 yuan, and the average growth rate of the purchase price of each piece of clothing B is y, then 200 (1 + y) 2 = 242, solution: y1 =, y2 = disagree with the topic).

Answer: The average growth rate of the purchase price of each piece of clothing is 10%;

3) The purchase price of each piece of B clothing is raised again according to the average growth rate, and the price is raised again**: 242 (1+10%)=yuan), and the shopping mall is still 9% off**, and when the price is set at a yuan, the solution is: A 26629

Therefore, when the price is at least 296 yuan, B clothing can make a profit

Original question: A and B two pieces of clothing cost a total of 500 yuan, in order to obtain profits, the store owner decided to price A clothing according to 50% of the profit, B clothing according to 40% of the profit pricing, in the actual **, at the request of the customer, the two pieces of clothing are 9% off**, so that the store made a total profit of 157 yuan, how much is the cost of the two pieces of clothing A and B?

Solution: If the cost of A is yuan, then the cost of B is 500-a yuan (or set to b yuan) according to the title.

A pricing a (1+50%)=, B pricing (500-a) (1+40%) = (

a=300 yuan.

The cost of A is 300 yuan, and the cost of B is 500-300 yuan = 200 yuan or a binary system of equations.

a+b=500（

Solution: If the cost of clothing A is X yuan, the cost of clothing B is (500-x) yuan; The pricing of clothing A is (1+50) x = yuan, the selling price of clothing A is yuan, and the profit of clothing A is yuan; The pricing of clothing B is (1+40) (500-x) = (yuan, the selling price of clothing B is yuan, and the profit of clothing B is (yuan, according to the title, there is an equation:

x=300500-x=500-300=200

A: The cost of clothing A is 300 yuan, and the cost of clothing B is 200 yuan.

1. The cost of A and B is x and y respectively

xPin Price -x) x=, xPin Price =

y-y) y=, y-pold=,x+y=500

Solve the above equations, x=300, y=200

I'll look at the second question later, so I'll be busy with the work at hand first.

After replying, I found that someone had already replied, and the replies of the following two people were correct.

Let the cost of A be x and the cost of B be y, then.

x+y=500

1 + solution gives x = 300

y=200 The second formula is simplified.

Divide by both sides.

Then let the first formula, multiply both sides at the same time, and get.

Subtract the two formulas.

The solution is y=200

Then return y=200 generations to the original formula.

Get x=300

1) The cost price of A is 300 yuan, and the cost price of B is 200 yuan.

2) Wins, 6 draws, 4 draws.