6th grade summer math homework equations

c: Let y=-x, then the original equation is: 2x-(-7x)=452x+7x=45

9x=45 so x=5 and y=-5

d: Lianli 4x-5y+2z=0

x+4y-3z=0 ②

4- Get: 21y-14z=0, i.e.: 3y-2z=0y=2 3z

4+ *5 obtains: 21x-7z=0, that is: 3x-z=0x=1 3z

So: x=1 2y=1 3z

e: Let x=3a, y=4a, z=5a

Substituting the equation: 3a-8a+15a=30

a=3So: x=, z=15

Solution: c: When opposite to each other, x+y=0

So: x=-y... 1

Let's substitute Eq. 1 into the original equation, get.

2x+7x=45

9x=45x=5

And because x=-y so; y=-5

d: When x, y, z, is not equal to 0

So: 4x-5y+2z=x+4y-3z=0 gets: 3x-9y+5z=0....3

4x-5y+2z=0...2

x+4y-3z=0...1

No. e： x/3=y/4

4/3*x=y...1

x/3=z/5

5/3*x=z...2

Put substitution into the equation.

: x-8 3*x+5x=30

10/3*x=30

x=9 Ide.

y=12 ,z=15

Sorry, not all your problems.

c xy is the opposite of each other, then x=-y, so 2x+7x=45 gives x=5 y=-5

d 4x-5y+2z=0

x+4y-3z=0 5x-y-z=0 z=5x-y is substituted into 2x-y=0

2z-3y=0

3x-z=0

So x=1 y=2 z=3

e x 3=y 4=z 5 gives 20x=15y=12z gets 4x-3y=0

5x-3z=0 2 tries to add 3z=x+3y to 2x+y=30 in the substitution formula

4x=3y gives x=9 y=12 z=15

It's all there.

c；x,y are the opposite of each other, i.e., x=-y, and 2x-7y=45 are synthesized to x=5,y=-5

d；4x-5y=-2z, x+4y=3z, divide the two formulas to obtain, (4x-5y) (x+4y)=-3 2 to obtain 2x=y, respectively, substituting the original formula to obtain 4x-10x+2z=0, x+8x-3z=0, and the two formulas are synapsibly obtained 2z=6x=3y

e；Suppose x=3a, y=, substituting the original equation to get a=3, x=9, y=12, z=15

<> 6th grade math homework arrangement can be made according to individual circumstances and school teaching plan, and the following is a rough summer math homework arrangement suggestion.

First of all, make sure that you have a good grasp of what you have learned. You can review the content you have learned during the semester, review the key knowledge points, and consolidate the relevant practice questions. You can use textbooks, tutorials or ** resources to find the corresponding exercises, and review and train them in an orderly manner according to the chapters.

Secondly, you can choose some math study question sets or question banks that suit you for practice. You can choose some targeted exercise sets, such as improvement questions, competition questions, etc., to cultivate problem-solving ability and thinking flexibility. At the same time, you can also try to do some extended questions to exercise your reasoning and innovation ability.

Also, try to enroll in some math summer camps or class tuition classes. In this way, you will not only be able to learn better under the guidance of your teacher, but you will also be able to make friends with math enthusiasts of the same age and learn and progress together.

Finally, pay attention to the balance of rest and recreation. Summer vacation is a time for relaxation and rest, and in addition to studying, you should also set aside enough time for yourself to relax and participate in some fun activities. You can choose some math-related games or exercises, such as Sudoku, puzzle solving, etc., which can both exercise your mind and have fun.

In short, the 6th grade math homework arrangement needs to arrange the study and rest time reasonably, pay attention to reviewing the basic knowledge, improve the problem-solving ability, and participate in relevant tutoring or training classes at the appropriate time. I hope you find the above keygen tips helpful and have a great summer holiday and make progress!

Let cod=x

then boe=2x+12°

So boe- cod= boc+doe=x+12°Because aob= boc, eof= doe, so aob+ eof= boc+ doe=x+12° aof=135°= aob+ eof+ boe=x+12°+2x+12°=3x+24°

i.e. x = (135°-24°) 3 = 37°

boe=86°,∠cod=37°

Because: ob and oe are the bisector of AOC and DOF, respectively.

So: boc= aob, doe= eof

Because: AOF=135°, BoE is 12° larger than 2 times COD, so: 2 COD+12°= BoE

Then: 2 COD+12°+ BOC+ DOE=135°( COD+ BOC+ DOE)+ COD=135°-12° [This step can be omitted]: BOE+ COD=123°2 COD+12°+COD= 123°

3∠cod=111°

So cod=37°

So: boe = 37 ° x2 + 12 ° = 74 ° + 12 ° = 86 ° [a bit verbose, after you understand it, some steps can be omitted].

1) Set uphill x and downhill y when going, then go uphill y and downhill x when returning, 4 hours and 30 minutes = hours.

4 hours 42 minutes = hours.

Go x 28+(142-x-y) 30+y 35=Back to y 28+(142-x-y) 30+x 35=Solve the system of equations. 2) Set 1 egg x and 1 duck egg y, then the preserved egg z13x+5y+9z= (1).

2x+4y+3z= (2)

3(2)-(1) -x= (3)

3) Substituting (1) -z=

x+y+z=

m.ax+by=5 is the first attempt, and cx-2by=8 is the second attempt.

Because I only read the wrong c, so x=5,y= -3 and x=-3,y=3, all of them are true.

Bring it in for a try:

5a-3b=5, 3b-3a=5

Solution: a=5, b=20 3, bring b, x=5, y= -3 into the second attempt:

c=n.Let Ming's velocity be x, and Li's velocity be y.

Equations that can be listed with a title:

x+y）*24/60=

x*20 60+y*(10+20) 60=Solve this equation, (the basic computing power should be no problem, I believe the result can be calculated) Note: Pay attention to the time and speed units. The time is all hours, so the unit of speed is kilometers and hours.

1) The solution is x=5, y= -3 and the reconciliation is x= -3, y=3, both of which should satisfy ax+by=5, and substituting can obtain a, b

Then reconcile b is x=5, y= -3, and substitute cx-2by=8, and c2) is given to Xiao Ming x kilometers per hour and Xiao Li y kilometers per hour.

24 minutes = hours, 20 minutes = 1 3 hours, 30 minutes = 1 2 hours.

x/2+y/3=

Solve systems of equations.

a. Let this angle be x, according to the problem to get 180-x + (90-80) = 5 * (90-x) to get this angle x=65, the complementary angle of this angle is 180-65 = 115

b. (1 A cuboid has 6 faces, each of which is rectangular, and the two opposite sides may be squares.

2 The box has 12 edges, and the opposite edges are of equal length.

3 The box has 8 vertices.

c. Solve the equation according to abc=60 and the formula in the problem! Find 120 (1 a+1 b+1 c).

Degree. b.1 A box has 6 faces, each of which is rectangular and possibly two opposite sides are squares.

2 The box has 12 edges, and the opposite edges are of equal length.

3 The box has 8 vertices.

Cm.

Degree. b.Edges of a cuboid. The main characteristics of the surface are as follows. 1 (a box has 6 faces, each face is a rectangle, or two faces opposite each other are squares) 2 (a box has 12 edges, and the opposite edges are of equal length) 3 (the box has 8 vertices).

Cm.