The minimum positive period of y sin x

Accumulation and difference formulas.

sin sin =-1 2[cos( +cos( -make sin sin(x+ 3) sin sin(x+ 2)At this point, you should be able to solve it yourself.

This college entrance examination is not required!

Accumulation and difference. Refers to a set of identities in the trigonometric part of elementary mathematics.

Formula: sin sin =-1 2[cos( +cos( -cos cos =1 2[cos( +cos( -sin cos =1 2[sin( +sin( -cos sin =1 2[sin( +sin( -cos sin =1 2[sin( +sin( -The sum difference identity can be proved by the right-hand end of the sum difference identity of the angles.

That is, you only need to split the right side of the equation with the formula of the sum of the two corners to prove that sin sin = -1 2[cos( +cos( -1 2[(cos cos -sin sin )-cos cos +sin sin )].

1/2[-2sinαsinβ]

The others are also the same proof method:

cos cos = 1 2[cos( +cos( -sin cos = 1 2[sin( +sin( -cos sin = 1 2[sin( +sin( -see sum difference product)

Trigonometric function. The minimum positive period is 2

The image of this function is symmetrical to the x-axis of y=sinx, and the y<0 part of the image y=sinx is folded, so the period becomes half of the original after folding, which is row 2

If there is a minimum positive number in all the periods of the period function f(x) of the selling auspicious fruit, then this minimum positive number is called the minimum positive period of f(x).

Draw f(x)=|sinx|The image below the x-axis is flipped above x (because it is an absolute value), and you can see that the period of f(x) is k, and k=1 is taken to know that its minimum positive period is

y=sin^2πx

1/2(1-2sin^2πx)+1/2

1/2sin2πx+1/2

Therefore, the minimum Qi Ru positive period is: t=2 clearing2 =1

The minimum positive period of the function y=sin(cos) is the minimum positive period of y=cosx, so it is 2,10, the source is 2pi, if it is pi, you qin sin(cos0)=sin1, and sin(cos(pi))=sin(-1)=-sin1, the gods are obviously not equal. ,2,

By the period t=2

y=sin x, where is the angle frequency or circle frequency of the slag.

What is the minimum positive period of the function y=sinx sin2x?

Analysis: The minimum positive period of sinx t1=2

The minimum positive period of sin2x is t2=

The "generalized least common multiple" of t1 and t2 is: 2

y=sinx The minimum positive period for sin2x is 2

When x is in the second quadrant or on the horizontal axis.

sin(π+x)=sinx

sinx|=|sin(π+x)|

When x is in the first third quadrant or on the vertical axis.

sinx=-sin(π+x)

sinx|=|sin(π+x)|

In summary|sinx|=|sin(π+x)|

The absolute value is to invert the image below the x-axis, so the period is reduced by half to !

If you draw a diagram, you can see that its image is in the positive direction of the y-axis.

Summary. Hello, draw f(x)=|sinx|The graph below the x-axis is flipped above x (because it is an absolute value), and you can see that the period of f(x) is k, and if k=1, we can see that its minimum positive period is .

Hope mine is helpful to you.

Function y=|sinx|What is the minimum positive period of .

You are quick to draw f(x)=|sinx|The image below the x-axis is flipped to the top of x (because the trembling ridge is taken as an absolute value), and you can see that the period of f(x) is k, and k=1 shows that its most mu hole spike is a small positive period. Hope mine is helpful to you.

Is there a formula method? Is it just drawing?