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Anonymous users2024-02-101) Left = x (2x + 5) = 0, x = 0 or 2x + 5 = 0, x = -5 22) Left - Right = y 2 + 2y + 1 = (y + 1) 2 = 0, y = -13) right = (2 + x) (2-x), x = 2 is a solution, or both sides are reduced, -x = 2 + x, x = -1
4) Left = (x-1) (3x-2) = 0, x = 1, or x = 6 35) Left - right with square difference = (7x+3) (-3x-7), x = -7 3 or -3 7
6) ( 2x-1) (x+1) = 0, x = -1 or x = 2 27) left - right = (x-3) (x + 3-1 2 (x-3)) = (x-3) (1 2x + 9 2) = 0, x = 3 or x = -9
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Anonymous users2024-02-091) x(2x+5)=0 x=0 or x=-5 22)(y+1) 2=0 y=-1
3) x 2-x-2=0 (x-2)(x+1)=0 x=2 or x=-14)3x 2-5x+2=0 (3x-2)(x-1)=0 x=2 3 or x=1
5) (3x+7) (7x+3) = 0 x=-7 3 or x=-3 76) (x-1) (x+1) = 0 x=1 or x=-17) (x-3) (x+9) = 0 x=3 or x=-9
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Anonymous users2024-02-08Quite speechless about your question.
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Anonymous users2024-02-07Untie; ① 2x+3)^2=(5x-4)^2
2x+3+5x-4)(2x+3-5x+4)=0 x1=1/5 x2=7/3
x-2) 2-2 (2-x) = 0
x-2 (x-2+2) = 0 x1 = 2 x2 = 2-2
4y^2+8y+4=0
4（y-1）^2=0 y1=y2=1
x-5)(x+3)+x(x+6)=-17
2x^2+4x+2=0 (x+1)^2=0 x1=x2=-1
3-x) ^2 =9-x ^2
3-x) 2-(3-x) (3+x)=0
3-x)(3-x-3-x)=0 x1=3 x2=0
t-3)(t+4)=-12 t^2+t=0 t（t+2）=0 t1=0 t2=-2
x+5)(x+3)+x(x+6)=-17 2x 2+14x+32=0 x 2+7x+16=0 There is no solution to the square leakage.
x^2-2ax+a^2-b^2=0 [x-(a+b)][x-(a-b)]=0
x1=a+b x2=a-b
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Anonymous users2024-02-06（1）5x²+4x=0
x(5x+4)=0
x=0 or 5x+4=0
x1=0, x2=-4/5
2)√2y²=3y
3y-√2y²=0
y(3-√2y)=0
y=0 or 3-2y=0
y1=0, y2=(3/2)√2
3)x²+7x+12=0
x+3)(x+4)=0
x+3=0 or x+4=0
x1=-3, x2=-4
4)x²-10x+16=0
x-2)(x-8)=0
x-2=0 or x-8=0
x1=2, x2=8
5)x²+3x-10=0
x+5)(x-2)=0
x+5=0 or x-2=0
x1=-5, x2=2
6)x²-6x-40=0
x-10)(x+4)=0
x-10=0 or x+4=0
x1=10, x2=-4
7)t(t+3)=28
t²+3y-28=0
t+7)(t-4)=0
t+7=0 or t-4=0
t1=-7, t2=4
8)(x+1)(x+3)=15
x²+4x+3=15
x²+4x-12=0
x+6)(x-2)=0
x+6=0 or x-2=0
x1=-6, x2=2
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Anonymous users2024-02-05（1）（2x-1）²=8x
4x²-4x+1+8x=0
4x²+4x+1=0
2x+1)²=0
x1=x2=-1/2
2）（x-2）²=2x（x-2）
x-2)²-2x(x-2)=0
x-2)(x-2-2x)=0
x-2)(-x-2)=0
x-2)(x+2)=0
x1=2,x2=-2
3) x -2 root number 3 x = -3
x -2 root number 3 x + 3 = 0
x-root number 3) 0
x1 = x2 = root number 3
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Anonymous users2024-02-041、(x-1)²-2(x-1)=0
x-1)(x-1-2)=0
x-1)(x-3)=0
x=1 or x=3
x²-4=0
3x+2)(3x-2)=0
x=-2 3 or x=2 3
3、(3x-1)²-4=0
3x-1+2)(3x-1-2)=0
3x+1)(3x-3)=0
x=-1 3 or x=1
x(x-3)=(x-3)(x+1)
5x-x-1)(x-3)=0
4x-1)(x-3)=0
x=1 4 or x=3
5、x²-4x-12=0
x-6)(x+2)=0
x=-2 or x=6
6、x²-12x+35=0
x-5)(x-7)=0
x=5 or x=7
The factorization method is a method of following a quadratic equation.
1. Polynomials.
Divide by polynomials is generally calculated vertically, the divided formula and the division formula are arranged by a certain letter as a decreasing power, and the missing term is filled with zero, the first term of the divided formula is divided by the first term of the division formula to get the first term of the quotient formula, the first term of the quotient formula is used to multiply and divide, the product is written below the divided formula (aligned with similar terms), the equal terms are eliminated, the unequal terms are combined, the difference obtained is taken as a new divided, and then the calculation is continued according to the above method until the colossal is zero or the number of the covariance is less than the number of divisions, Divided = Divided Quotient + Remainder. If the remainder is zero, the polynomial is divisible by another polynomial. >>>More
There are various divisions of factorization.
The cross division is the simplest and most commonly used one. >>>More
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