There are a number of chickens and rabbits, they have a total of 15 heads and 48 legs, and how many

First of all, you may be misty, an animal has one head, and having 15 heads is 15 animals. But if you really get the question wrong, the correct question might be "how many chickens and rabbits are there?" If so, you can refer to the following method.

Rabbits have 4 legs and chickens have 2 legs.

Let's say it's all rabbits, and there are 15 and 4 legs. 15 4 = 60 (only) If it is all rabbits, then there are 60-48 more feet. 60-48 = 12 (only) If you replace a rabbit with a chicken, there are 4-2 fewer legs.

4-2=2 (only) Therefore, for each rabbit that is replaced by a chicken, there are two fewer extra feet.

Divide the extra number of legs by 2, which is the number of chickens. 12 2 = 6 (chickens) 6 chickens and rabbits 15-6 = 9 (only)

6 (only).

The simplest, suppose that both the chicken and the rabbit raise one foot first, that is, count with the feet - the head counts, the chicken has one leg, the rabbit has three legs, and then the chicken and the rabbit lift one more foot, the chicken sits down, and then the foot counts - the head counts, and there are two legs left of the rabbit, at this time, the remaining number of feet divided by 2 is the number of rabbits.

Let's say it's all rabbits.

9 rabbits, 6 chickens.

Suppose chicken x rabbit y then.

x+y=15

2x+4y=48

It can be known that x=6 y=9

The number of rabbits is: (48-15*2) 2=9 (only) (after removing the two feet of each rabbit, the remaining feet are the two feet of all rabbits).

The number of chickens is 15-9=6 (only).

Through thick and thin, learn to be in the same boat and have something to say.

88 heads, that is, chickens and Lushan rabbits, a total of 88.

Rabbit 4 legs Chicken 2 feet If two or no animals are subtracted from the total number of feet in the early group, then 244-88*2=68 are left.

At this point, all the chickens have their feet deducted, and all the rabbits have 2 feet left, so there are 68 2 = 34 rabbits.

The number of chickens is 54.

There are a number of chickens and rabbits, they have a total of 88 heads, 244 legs, and how many chickens and rabbits each have.

Assuming that all rabbits are rabbits, then the chickens have: (88 4-244) (4-2), = 352-244) 2, = 108 2, = 54 (only), then the rabbits are: 88-54 = 34 (Qin is not only messy beam), A: There are 54 chickens and 34 rabbits

Let's say all 88 are chickens.

88x2=176pcs.

244-176) (4-2) = 34.

88-34 = 54 pcs.

A: 34 rabbits and 54 chickens.

If there are x chickens, there will be (88-x) rabbits.

2x + 4 (88-x) = 246

2x+352-4x=246

2x=-106

x=5388-x=88-53=35

A: There are 53 chickens and 35 rabbits.

Solution: Suppose all rabbits have a total of 88 4 = 352 feet, which is 352-244 = 108 more than the known 244 feet, because 1 rabbit has 4-2 = 2 more legs than 1 chicken, so the chicken has: 108 2 = 54, so the problem can be solved

Assuming it's all rabbits, chickens have:

88 4-244) (4-2),(352-244) 2,108 2,54 (only), then rabbits have: 88-54 = 34 (only), answer: 54 chickens, rabbits have 34 Qing Lun Xuan.

1, rabbit (244-88x2) (Tongyin 4-2) = 68 2 = 34 chickens 88-34 = 54, 2, chicken (4 88-244) (4-2) 54 rabbits 88-54 = 34, 2, x+y = 882x + 4y = 244

x=54 y=34,2, if there are x chickens, then there are 88-x rabbits, and the column formula is. 2x+(88-x)*4=224, x=64, then there are 88-64=24 rabbits. ,1,

Suppose Tangerine Zheng is all rabbits, and the round grip is a chicken

88 4-244) (4-2), Pi Liang.

352-244) 2,108 2,54 (only), then rabbits have: 88-54=34 (only), answer: 54 chickens and 34 rabbits

Chickens and rabbits in the same cage: chicken head + rabbit head total number.

Chicken 2 + Rabbit 4 total feet.

If the chicken is x, then there are 88-x rabbits, according to the title:

2x+4(88-x)=244pcs.

Solve the equation to get x=54 (only) 88-x=34 (only) Answer: There are 54 chickens and 34 rabbits.

54 chickens and 34 rabbits.

Set chickens and rabbits respectively.

x+y=88

2x+4y=244

Solution x=54, y=34