Where is the plant tissue culture rack 1 35m 1m 2 3m size?

The general size of the tissue culture rack is 6 layers and 5 layers, and each layer is equipped with 2 tissue culture lights. Special sizes can generally be customized, and the general length is based on the length of the tissue culture lamp, not too long, and the light is uneven. The light is too short to fit in.

In reality, due to different materials and usage requirements, the general size will be different.

The length of the tissue culture frame is determined according to the lamp tube, the lamp is generally T5, so as to reserve a suitable space to connect the circuit, and the length of the frame is in the angle steel type) butterfly buckle type) square steel type).

The width of the tissue culture rack is generally between different needs according to the needs, and there are two types: layer plate type and frame type. If the number of lamps installed under the laminate is large, it generally needs to be widened, usually 50cm'5-6 lights can be installed. The frame type can be put galvanized mesh, glass, reflectors, tissue culture baskets (generally 3 on one layer, so the actual length of the shelf should be above and above).

Jinan Tenghao has a variety of tissue culture equipment and tissue culture racks, etc., which can be communicated.

Hello, our company has customized culture racks: length meters, width and height can be customized, practical layers are customized, shelves are selected according to customer needs, dark wiring, each layer is equipped with a special tissue culture lamp The number of customers chooses, and automatic timing.

Wuhan Double Helix Biotechnology****.

The bed is rice, and of course the mattress is also bought with rice.

Since the domain of f(x) is defined as r, then (m2

3m+2）x2

m-1)x+1 0 is always established, if m2

3m+2=0, that is, there is m=1 or 2, when m=1, 1 0, constantly, when m=2, x+1 0 is not constant

If m23m+2 0 and the discriminant formula is less than 0, i.e., (m-1)24(m23m+2) 0, i.e., there is m 2 or m 1, and m 7 or m limb file leaks 1, then m 7

Or the calendar is rotten m 1, in summary, it can be obtained, m 7

or m 1, so the answer is: m 7

or m 1

Original = m(3m?1)

m+1)(m+1)(m?1)?m(m?3)

m(m+1)

m(3m?1)

m+1)m(m+1)

3m?1mm+1, m is the equation 2x2

Solution of 7x-7=0, 2m2

7m-7=0, i.e. m2

7m+72, substituted into the original formula: 7(m+1)m+1

It is not recommended to raise tropical fish, the cement is thick, the insulation effect is not good, the cement is not leaky, the main thing is that there is less leakage, so that the wall is damp, the wall paint, or the decoration is easy to be damp and peel.

It is best to use glass, and then add a background pattern, and the glass in contact with the cement is then padded with some good insulation materials, which must be even, and then embedded into the cement, so that the temperature of the fish tank is ***, and it is easy to clean, and the fish tank is too thick, and the visibility is low if the water is not well maintained, after all, it is made of cement, please be cautious.

In this case, you need to use polyurethane sealant, and it takes several days for the sealant to fully solidify, so it is best to let it stand for a week and then inject water, and the adhesive layer is generally not more than 1cm.

Isn't it more reliable to put it in the tank? The force is more uniform.

A trough width of 25 is more appropriate.

High-strength silicone or modified silane, polyurethane should be fine.

4*3+4*3*2+3*3*2=54 (square meters) square meters) 47*25=1175 (grams).

1175 grams = kilograms.

A: A total of kilograms are required.

b (m-1, 3-2m, 3m are you sure it's m-1?Not 1-m?Added:

ab = ob-oa = (1-2m, 2-3m, -2+2m) |ab|= (1-2m) +2-3m) + 2+2m) =17m-24m+9 =17(m-12 17) +9 17 So|ab|The minimum value of 9 is 17 so |ab|=（3√17)）/ 17

Just use the formula for the distance between two points and then use the maximum value of the quadratic equation Follow-up question: (3 17) 17 The answer is this I can't calculate it Answer: What is the abscissa of point b Supplement:

l=|ab|^2=|(1,3m-2,2-2m)|2 =1 2+(3m-2) 2+(2m-2) 2 =13m 2-20m+6=13(m-10 13) 2+17 13 Therefore, when m=10 13, l takes the minimum value Supplement: I am dizzy I said how to make it and the answer is different l=|ab|^2=|(2m-1,3m-2,2-2m)|2 =(2m-1) 2+(3m-2) 2+(2m-2) 2 =17m 2-24m+9=17(m-12 17) 2+9 17 so when m=12 17, l takes the minimum value of 9 17 and then opens the root number.

Narrow at the top and wide at the bottom: width = ( ...The base of the column is generally narrow at the top and wide at the bottom.

or wide at the top and narrow at the bottom: width = (1