Very simple chemistry topic, thank you

a. Sodium chloride solution should be stored in a fine-mouth bottle;

b. Zinc granules can be stored in jars;

c. Dilute hydrochloric acid should be stored in a fine-mouth bottle;

d. Marble or white phosphorus can be stored in a jar Answer: Solution: The jar in the picture is used to store solid reagents, and the bottle is frosted glass above the neck of the bottle, equipped with a cap or stopper

a. Sodium chloride solution should be stored in a fine-mouth bottle so it is not optional

b. Zinc granules are solids that can be stored in the jar in the figure, so they are optional

c. Dilute hydrochloric acid is an acidic solution and should be stored in a fine-mouth bottle with a glass stopper, so it is not optional

D. Marble or white phosphorus is a solid that can be stored in the jar in the picture Therefore, choose b so D fill: marble or white phosphorus Comments: This question examines the storage of medicines, and this type of question is not a common type of question in junior high school Students need to consider carefully.

A jar is a glass container used to hold solid reagents, and there are two types: clear and brown, brown bottle.

Jars are used for reagents that need to be kept away from light (e.g., silver nitrate). Jars are generally used to store reagents, and the inside of the mouth is frosted for use with the stopper.

As can be seen from the block diagram, nano3, Naoh, Hno3, and Ba(NO3)2 were mixed with solution X, respectively, and two precipitates appeared. This can only be generated by mixing NaOH and Ba(NO3)2 with X, respectively. Since nano3 and Hno3 react with any substance and there will be no precipitation, then b and d are HNO3 and nano3, and A and C are NAOH and BA(NO3)2 (breakthrough).

The precipitate formed by the reaction of NaOH and X, the base, must be dissolved by Hno3, but not by NaNo3, so A is NaOH, D is Hno3, B is Nano3, then C is Ba(NO3)2. The precipitate generated by the reaction of C i.e. Ba(NO3)2 and X is insoluble in Hno3 and knows that X contains SO42—, and combines X with excess A, i.e., NaOH to form a white precipitate (base), which can be introduced as MgSO4.

Solution: Because B and D can be used to dissolve and insoluble the precipitate, and do not react with X, it can be determined to be NaOH and HNO3.

And because the precipitate produced by adding A can be dissolved in the solution with B, it can be further determined that B is nano3 and D is Hno3, because the precipitate with a can be dissolved in solution D, so it can be determined that A is NaOH and C is BA(NO3)2

According to the solution of A, B, C, D, it can be determined that X is CaSO4, i.e., A is Naoh, B is NaNO3, C is Ba(NO3)2, D is Hno3, and X is CaSO4

1 Process: m m x x m m

2 Since it is a diatomic molecule, y 2x na 2mna m4 m/(1000+m)

5. m/(mv) mol/l

Solution: The total mass of the solution is (; According to v=m, the volume of the solution can be obtained v=40g;

1) According to the meaning of the title, the amount of CuSO4·5H2O is n(CuSO4·5H2O)=m m=; At this time, the solution is copper sulfate, the anion is SO42-, and the cation is Cu2+;

According to the conservation of sulfate, n(Cu2+)=n(SO42-)=n(CuSO4·5H2O)=;

So the amount of anionic total material in the solution is;

2) According to the conservation of copper sulfate, n(cuso4)=n(cuso4·5h2o)=, so c(cuso4)=n v=;

3) According to the amount of solute before and after dilution, the dilution formula is used to solve; Dilution formula: n=c1 v1=c2 v2;

v2=；Answer: The total amount of anions and cations in this solution is; The concentration of the substance of the amount of copper sulphate in the solution is; The volume of the diluted solution is 30 ml.

The molecular weight is 250

Therefore, the amount is. 1. The amount of cation and anion is each, and the total amount is.

2. The volume of the solution is (. 5）/。06ml

Amount concentration of CuSO4 =

B false. The bridging amount of the substance of the oh ion in term A is. The number of electrons of the oh ion is 10, so the number of electrons in the root elimination formula n=n*na is 1mol

As for item b, you don't seem to have said it all.

The number of tritium neutrons is 2The amount of tritium hydrogen is 3 mol, so the number of neutrons contained in it is 6 mol

1.Yes, concentrated sulphuric acid will c-c.

2.OK. zn + h2so4===znso4 +h2

3.OK. 2al + 3 h2so4 ====al2(so4)3 + 3h2

It's all right! Concentrated flow acid, strong oxidizing wood board will be charred and black, aluminum can replace copper ions can show red, zinc reacts with dilute flow acid, so you can make different shapes on wax, I guess, I'm a senior in high school!

1. Dehydration, carbonization of wood boards, 2 metal reaction with acid, 3 displacement reaction. What are you trying to express? I didn't get it.

Second, zinc can react with dilute sulfuric acid and leave traces.