Why is the outside of the train track at the turn higher than the inside?

Because the train has a great speed when traveling, when turning, because there is a circular arc, there is an arc that can produce a centripetal force, that is, a force that throws outward, and in this process, the train will exert a lot of pressure on the outer rail.

If you don't do it like this, it's easy to overturn. It has a balancing and protective effect.

Because of the speed of the train, it is easy to turn on the flat track.

Because the turning point often leads to overturning due to inertia, the balance is stressed.

Prevent the train from overturning due to inertia. Protective.

The train runs at a high speed, in order to prevent the train from derailing.

Prevent rollover, the train is too fast.

The train is fast and changes the altitude to prevent it from rolling over.

In order to prevent centrifugal force from derailing the car.

The train travels on an arc-shaped track when it turns, and there is centripetal acceleration. The train needs to be inclined towards the inside of the track, so the outer track of the railway is paved a little higher than the inner track. At this time, the gravitational force g mg is vertical, but the support force n of the rail is tilted inward.

The resultant force f of these two forces, the direction of which is directed horizontally towards the center of the arc (Fig. 1).The inclination of the track is designed based on the average speed v of the train. If the speed of the train is too high at the turn, it will cause a derailment and rollover accident.

Answer]: B The wheel of the train has a protruding rim, if the inner and outer rails at the turn are the same high, the rim of the outer wheel squeezes the base and balances the outer rail, so that the outer rail undergoes elastic deformation The elastic force of the outer rail on the wheel rim is the centripetal force that makes the train turn. The mass of the train is very large, and the centripetal force is obtained by this method, and the interaction force between the wheel flange and the outer rail should be very large, otherwise the rail is easily damaged.

If the outer rail is slightly higher than the inner rail at the turn, when the train passes through the turn, the direction of the rail's support force fn on the train is no longer vertical, but obliquely to the inside of the curve, and its resultant force with gravity c points to the center of the circle and becomes the force that makes the train turn. This reduces the squeezing of the rim and the outer rail.

Answer]: B Analysis: The wheels of the train have a prominent rim, if the inner and outer rails at the turn are the same high, the rim of the outer wheel Burning Chang squeezes the outer rail, so that the outer rail undergoes elastic deformation, and the fierce elastic force of the outer rail on the rim is the centripetal force that makes the train turn.

The mass of the train is very large, and the centripetal force is obtained by this method, and the interaction force between the wheel flange and the outer rail must be very large, otherwise the rail is easily damaged. If the outer rail is slightly higher than the inner rail at the turn, when the train passes through the turn, the direction of the rail's support force fn on the train is no longer vertical, but obliquely to the inside of the curve, and it points to the center of the circle with the force of gravity g, which becomes the force that makes the train turn. This reduces the squeezing of the rim and the outer rail.

Answer]:BAnswer】B. Analysis:

If the inner and outer rails are as high as the inner and outer rails at the turn, the rim of the outer wheels squeezes the outer rim to make the outer rails elastically deformed. The elastic force of the outer rail on the rim is the centripetal force that makes the train turn. The mass of the train is very large, and the centripetal force is obtained by this method, and the interaction force between the wheel flange and the outer rail should be very large, otherwise the iron rails are easily damaged.

If the outer rail is slightly higher than the inner rail at the turn, when the train passes through the bend, the direction of the rail's support force fn on the train is no longer vertical, but obliquely to the inside of the curve, and the resultant force of the lead liquid and gravity g points to the center of the circle, becoming the force that makes the train turn. This reduces the squeezing of the rim and the outer rail.

Turning requires a centripetal force, which is partly provided by the rails, (and the other part is provided by the gravitational component, which does not change with speed, so it is not considered), and the rails are underneath the train, so the moment of this force causes the train to roll outward.

Therefore, the outer rail is compressed when the train has a tendency to turn outwards and generates additional pressure, while the inner rail reduces the pressure, which is conducive to the reverse moment to resist the former. If you want to ask, why does it have to be one increase and one decrease? Because the vertical components of their sum must be equal to gravity.

The above is the principle, according to this principle, if the velocity is large, then the centripetal force required is large, so it is ......

When the train turns at a specified rate, the inner and outer rails are only subjected to elastic force (in this case, for the train, the combined force of support and gravity provides the centripetal force in the horizontal direction);

When the speed of the train is greater than the specified speed, the train has a tendency to move outward, and then the outer rail will be subjected to the outward lateral pressure of the wheels;

When the speed of the train is less than the specified rate, the train has a tendency to move inward, and then the inner rail will be subjected to the inward lateral pressure of the wheels.

Note: The rim of the wheel is between the inner and outer rails, and the outer rail is higher than the inner rail.

The train moves in a circular motion when it turns, and the object that does the circular motion requires a centripetal force f=mv 2 r, if the inner and outer rails are the same high, the outer rail provides a centripetal force to the train, and the wheels squeeze the outer rail, causing wear and tear on the outer rail.

In fact, the outer and outer rails are higher than the inner rails, so that there is an angle between the track and the horizontal direction, and the resultant force of gravity and support force on the train provides a centripetal force at a specified speed v0

mgtan = mv0 2 r v0 = (grtan ) 1 2 can avoid damage to the inner and outer rails.

Because it is equivalent to doing centripetal motion when the train is turning, it needs to provide centripetal force.

If the inner and outer rails are the same high, the train will have a tendency to throw out when turning, causing the wheels and the outer rail to squeeze, and then produce a centripetal force with the outer pointing to the inward, so it will cause the wear of the outer rail and the wheels, and there will be a risk of derailment in serious cases.

Only by setting the rails to be low inside and high outside, the train will produce a tilt of low inside and high outside when turning, and use the component of gravity to provide centripetal force, so as to reduce the wear and tear of the outer rails and wheels.

Here it should be a matter of the centripetal force in physics, and the turning of the train can be regarded as a circular motion, then the outer track and .

The special wheels act to provide centripetal force, but in this case, the squeezing between the wheels and the outer track will damage the wheels, and will also deform the rails, causing serious train derailment. Therefore, the outer track is raised in the curve, and the body of the train is inclined when it is in the curve, and the combined force of the train's gravity and its supporting force provides the centripetal force, and does not need to be provided by the extrusion of the outer track. Of course, it is not that there is no lateral pressure on the track, if the turning speed is too fast, then the train still has pressure on the outer track, and if the turning speed is too slow, there will be pressure on the inner track.

So to be on the safe side, the train should maintain a proper speed while turning.

If you run 300 yards, you'll know.

First of all, the centripetal force is needed when the train turns, that is, the force that can make him change the direction of motion, and when the train turns, the track is oblique, according to Newton's law, f=ma=mv r, so it can be known that the greater the speed, the greater the centripetal force required, so when the train turns, if the centripetal force provided by the component of gravity (that is, the force pointing to the center of the circle) is insufficient or too large, then a force and the component of gravity should be used to jointly provide centripetal force, and when the speed is fast, the gravitational component is less than the required centripetal force, Therefore, the outer rail can provide a support force to the center of the circle, and when the speed is small, the gravitational component is greater than the inner rail needs to provide a force so that the train will not fall.

In short, this is a relatively simple question, there is an introduction to this in the physics book of the first year of high school, and after reading the whole problem of circular motion, you should understand it better, and there are diagrams in the book.