Well, I m here to ask you how to solve the equation at the beginning of the first day

Updated on educate 2024-05-26
12 answers
  1. Anonymous users2024-02-11

    1. Solution: 8x-16=10x-5

    2x=-11,x=

    Calculation: Substituting x=, left=8(, right=5((2*, left and right are equal, x= is the solution of the original equation.

    2. Solution: 3 (30x-1) = 24 (2x-1) 30x-1 = 8 (2x-1) = 16x-8

    14x=-7,x=-1/2

    Calculation: Substitute x=-1 2, left =(30*(-1 2)-1): 24=-16:

    24=-2:3, right=(2*(-1 2)-1):3=-2:

    3 is equal to left and right, and x=-1 2 is the solution of the original equation.

    I probably accidentally lost the negative sign during the calculation.

  2. Anonymous users2024-02-10

    You're right, why isn't it right, I'm right, yes, there's something wrong with your calculations.

  3. Anonymous users2024-02-09

    8(x-2)=5(2x-1)

    8x-16=10x-5

    16+5=10x-8x

    11=2xx=

    30x-1):24=(2x-1):3

    24(2x-1)=3(30x-1)

    48x-24=90x-3

    48x-90x=-3+24

    42x=21

    x = -1/2

    You should have made a mistake.

  4. Anonymous users2024-02-08

    The first question is correct.

    Question 2 9 14

  5. Anonymous users2024-02-07

    There is still a certain degree of difficulty in the teaching of solving equations in primary school mathematics, and there are often students who do not know how to solve them, the main reason is that they often do it blindly when they do not have a clear relationship between various quantities, so they often make mistakes. How can we improve students' ability to solve equations? After several years of elementary school mathematics study, I believe that when solving equations, it is important for students to understand the following relationships:

    Let the number be x

    1. One plus and another plus (one plus and another plus, another plus and one plus).

    2. Subtracted - Subtracted Difference (Difference Minus Subtracted Difference, Subtracted Difference Minus, Subtracted Difference Minus), Minus Minus Difference Subtracted Difference).

    3. The product of one factor and another factor (one factor product another factor, another factor product one factor).

    4. Dividend Divisor Quotient (Quotient Divisor Divisor Divisor Quotient, Divisor Dividend Quotient) Thank you for adopting.

  6. Anonymous users2024-02-06

    I'll tell you the easy way: for example, an equation 2x-8x+6=5x-2 knows what a similar term is (as the name suggests: an term that contains the same letter and has the same number of letters is called a similar term.

    Of course, you see that there is a 5x on the right, and a 6 on the left, what should we do? We should move to merge the same kind of terms, first of all, we must know that the positive number is moved to the left, or the right is to be changed to a negative sign, and the negative number is moved to the left or right to become a positive sign, and we can be sure that we can move the 6 on the right to the left, and the 5x on the left to the right, and now the formula becomes 2x-8x-5x=-2-6

    (2-5-8)x=-8 can then be calculated, which can be omitted.

    11x=-8

    x = plus 8/11 (because minus eight and minus eleven are both negative numbers, negative negative is positive and negative is positive, negative is negative, negative is negative, positive is negative).

    I hope it will help you, calculate very points, and I will help you if you can't.

  7. Anonymous users2024-02-05

    1.Suppose: If you do x questions correctly and the number of wrong questions is y, then, x+y=25

    4x-y=85

    Solution: x=22 y=3

    2.Set: If x students go out to travel, the cost is 1, then, 3*1+

    Solution: x 12

    When there are 12 students, travel agency A and B spend the same money, and when x 12, travel agency A saves more money.

  8. Anonymous users2024-02-04

    Let it be to x

    4x-(25-x)=85

    x=22 assigns students to x, and each student is a yuan.

    A: 3A+B; 3a+>0

    x<12

    That is, students with less than 12 students will be selected for A, and more than 12 students will be selected for B.

  9. Anonymous users2024-02-03

    If the speed of the express train is at least x km h, then the fast train and the slow train arrive at the same time

    180 60-1)*x=180, the solution: x=90(km h), that is, the speed of the express train should be at least 90km h.

  10. Anonymous users2024-02-02

    There are two situations, just see for yourself.

  11. Anonymous users2024-02-01

    Move on to the second question from the questioner.

    m=6,n=2,ab=6

    ap:pb=n=2

    pb=2,qb=1

    aq=ab-qb=5

  12. Anonymous users2024-01-31

    Solution: Let A x 10,000 yuan, then B (20-x) 10,000 yuan, and list the equation (1-20%) according to the meaning of the question[

    x=5B: 20-x=20-5=15

    A: A 50,000 yuan, B 150,000 yuan.

    Please click on "Review" in the top right corner, and then you can select "Satisfied, the problem has been solved perfectly".

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