What is the focus of the high school chemistry competition?

Updated on educate 2024-05-12
3 answers
  1. Anonymous users2024-02-10

    To be honest, competitions are what you want to learn in the future, such as competitions in junior high school are what you want to learn in high school.

  2. Anonymous users2024-02-09

    The role of the first prize at the provincial level in the high school chemistry competition:

    For the second prize or above in the provincial competition, 5 to 10 points will be added to the college entrance examination.

    It is possible to send to certain colleges and universities, such as some .

    Enrich your life experience and realize your personal value.

    After entering the provincial team, you can represent the province in the finals of the chemistry competition (winter camp), and you will be eligible for escort if you enter the training team.

    Conditions of entry for the High School Chemistry Competition:

    The contestants who participated in the preliminary round of the National High School Student Chemistry Competition were ordinary high school students. Be under 20 years of age before the next year's international competition. The number of finalists is 5 from each province, municipality and autonomous region.

    Since 1984, the Chinese Chemical Society has organized the National High School Student Chemistry Competition every year. These activities have played a positive role in raising the interest of young people in science, helping them establish a good habit of studying, loving, and applying science, and promoting the reform of chemistry teaching.

    The above content refers to the Encyclopedia - National High School Student Chemistry Competition.

  3. Anonymous users2024-02-08

    Summary. At a high pressure of 50 GPA, the structure of the H3 anion in CSH3 is triangular.

    Question 2: Thank you.

    At a high pressure of 50 GPA, the structure of the H3 anion in CSH3 is triangular.

    You can only answer in detail in the form of text.

    Can you change this question, only words.

    In equilibrium, the system contains mol of N2, mol of NH3 and mol of H2.

    Volume is not affected.

    And what about the second **.

    n2: molh2: molnh3:

    Mol solution: 1Calculate the concentration of the solution:

    1 mol/ kg= mol/l2.Calculate the pH of the solution: the acid is a weak acid, so it can be calculated by the Henderson-Hasselbalch equation

    pH=pka+log[a-] ha], where pka is the protonation constant of the acid, [a-] is the concentration of the substance or group of products of the acid, and [ha] is the concentration of the acid. Since the concentration of the protonation product of this acid is equal to the concentration of this acid, it can be obtained: pH = PKA+log[HA] [HA] = PKA3

    Calculate the dissociation rate of the acid: dissociation rate = 1-10 (-ph) = 1-10 (-pka) = 1-10 (-pka).

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